Operations & Algebraic Thinking - 1st Grade Math

Card 0 of 3828

Question

$\frac{\begin{array}[b]{r}20\ -\ 1\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back

$\frac{\begin{array}[b]{r}20\ -\ 1\end{array}}{ \ \ \space19}$

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Question

$\frac{\begin{array}[b]{r}19\ -\ 2\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back

$\frac{\begin{array}[b]{r}19\ -\ 2\end{array}}{ \ \ \space17}$

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Question

$\frac{\begin{array}[b]{r}16\ -\ 14\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back

$\frac{\begin{array}[b]{r}16\ -\ 14\end{array}}{ \ \ \ \ \ \space2}$

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Question

Which math problem below equals

Answer

We can add . So the math problem becomes . Both and equal .

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Question

$\frac{\begin{array}[b]{r}13\ -\ 6\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}13\ -\ 6\end{array}}{ \ \ \ \space7}$

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Question

$\frac{\begin{array}[b]{r}9\ -\ 3\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}9\ -\ 3\end{array}}{ \ \ \ \space6}$

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Question

$\frac{\begin{array}[b]{r}7\ -\ 7\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}7\ -\ 7\end{array}}{ \ \ \ \space0}$

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Question

$\frac{\begin{array}[b]{r}6\ -\ 5\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}6\ -\ 5\end{array}}{ \ \ \ \space1}$

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Question

What can we add to to get

Answer

or as a subtraction problem, .

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Question

$\frac{\begin{array}[b]{r}5\ -\ 3\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}5\ -\ 3\end{array}}{ \ \ \ \space2}$

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Question

$\frac{\begin{array}[b]{r}4\ -\ 1\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back

$\frac{\begin{array}[b]{r}4\ -\ 1\end{array}}{ \ \ \ \space3}$

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Question

$\frac{\begin{array}[b]{r}7\ -\ 2\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}7\ -\ 2\end{array}}{ \ \ \ \space5}$

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Question

$\frac{\begin{array}[b]{r}9\ -\ 5\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}9\ -\ 5\end{array}}{ \ \ \ \space4}$

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Question

What can we add to to get to

Answer

or as a subtraction problem, .

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Question

$\frac{\begin{array}[b]{r}11\ -\ 6\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}11\ -\ 6\end{array}}{ \ \ \ \space5}$

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Question

$\frac{\begin{array}[b]{r}20\ -\ 10\end{array}}{ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back

$\frac{\begin{array}[b]{r}20\ -\ 10\end{array}}{ \ \ \ \space10}$

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Question

$\frac{\begin{array}[b]{r}19\ -\ 4\end{array}}{ \ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}19\ -\ 4\end{array}}{ \ \ \space15}$

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Question

$\frac{\begin{array}[b]{r}18\ -\ 5\end{array}}{ \ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}18\ -\ 5\end{array}}{ \ \ \space13}$

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Question

What can we add to to get

Answer

or as a subtraction problem, .

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Question

$\frac{\begin{array}[b]{r}18\ -\ 14\end{array}}{ \ \ \ \ \space?}$

Answer

To subtract we can count backwards. Start at and count back

$\frac{\begin{array}[b]{r}18\ -\ 14\end{array}}{ \ \ \ \ \space4}$

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