Multiply Multi-Digit Numbers: CCSS.Math.Content.4.NBT.B.5 - 4th Grade Math

Card 0 of 48

Question

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 2\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 2$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 2}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 2}\end{array}}{\ \ \ 20}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 3\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 3$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 3}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 3}\end{array}}{\ \ \ 30}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 40}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}11\ \times\ 5\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 5$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ \times\ {\color{Red} 5}\end{array}}{\ \ \ \ 5}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ \times\ {\color{Red} 5}\end{array}}{\ \ \ 55}$

Compare your answer with the correct one above

Question

Solve the following:

$\frac{\begin{array}[b]{r}11\ \times\ 6\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 6$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ \times\ {\color{Red} 6}\end{array}}{\ \ \ \ 6}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ \times\ {\color{Red} 6}\end{array}}{\ \ \ 66}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}11\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 4}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 44}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 2}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 8}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}2\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 48}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 5\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 5$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 2}\ \times\ {\color{Red} 5}\end{array}}{\ \ \ \ 0}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}2\ \times\ {\color{Red} 5}\end{array}}{\ \ \ 60}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 6\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 6$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 2}\ \times\ {\color{Red} 6}\end{array}}{\ \ \ \ 2}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}2\ \times\ {\color{Red} 6}\end{array}}{\ \ \ 72}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}13\ \times\ 6\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $13\times 6$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 3}\ \times\ {\color{Red} 6}\end{array}}{\ \ \ \ 8}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}3\ \times\ {\color{Red} 6}\end{array}}{\ \ \ 78}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}13\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $13\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 3}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 2}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}3\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 52}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}13\ \times\ 2\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $13\times 2$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 3}\ \times\ {\color{Red} 2}\end{array}}{\ \ \ \ 6}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}3\ \times\ {\color{Red} 2}\end{array}}{\ \ \ 26}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 2\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 2$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 2}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 2}\end{array}}{\ \ \ 20}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 3\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 3$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 3}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 3}\end{array}}{\ \ \ 30}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 40}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}11\ \times\ 5\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 5$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ \times\ {\color{Red} 5}\end{array}}{\ \ \ \ 5}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ \times\ {\color{Red} 5}\end{array}}{\ \ \ 55}$

Compare your answer with the correct one above

Question

Solve the following:

$\frac{\begin{array}[b]{r}11\ \times\ 6\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 6$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ \times\ {\color{Red} 6}\end{array}}{\ \ \ \ 6}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ \times\ {\color{Red} 6}\end{array}}{\ \ \ 66}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}11\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 4}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 44}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 4\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 2}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 8}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}2\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 48}$

Compare your answer with the correct one above

Question

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 5\end{array}}{\space }$

Answer

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 5$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 2}\ \times\ {\color{Red} 5}\end{array}}{\ \ \ \ 0}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}2\ \times\ {\color{Red} 5}\end{array}}{\ \ \ 60}$

Compare your answer with the correct one above

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