Find Factors and Identify Primes

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4th Grade Math › Find Factors and Identify Primes

Questions 1 - 10
1

A factor is a whole number that divides another number evenly (with no remainder). Which of these numbers are factors of $42$: $3, 5, 6, 7$?

$3, 6,$ and $7$

$3$ and $5$

$3, 5, 6,$ and $7$

$5$ and $7$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 42, to find which of 3,5,6,7 are factors: systematically check divisibility: 42÷3=14 (yes), 42÷5=8.4 (no), 42÷6=7 (yes), 42÷7=6 (yes). Choice C is correct because it lists 3,6,7 as factors (all divide evenly) and excludes 5, demonstrating systematic factor finding and understanding of prime/composite definitions. Choice D represents including non-factors, which happens when students include numbers that don't divide evenly like 5 (42÷5=8.4). To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

2

A factor divides a number evenly (no remainder). Which numbers are factors of $40$? Choose the best answer.

Numbers to check: $5, 6, 8, 10$

$5$ and $10$ only

$5, 6, 8,$ and $10$

$5, 8,$ and $10$

$6$ and $8$ only

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 40, to find which of 5,6,8,10 are factors: check divisibility—40÷5=8 (yes), 40÷6≈6.67 (no), 40÷8=5 (yes), 40÷10=4 (yes). Choice B is correct because it lists all that divide evenly: 5,8,10. This demonstrates systematic factor finding and understanding of prime/composite definitions. Choice D represents including non-factors, which happens when students include numbers that don't divide evenly. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

3

A factor is a whole number that divides another number evenly (with no remainder). List all the factors of $36$.

$1, 2, 3, 4, 6, 8, 9, 12, 18, 36$

$2, 3, 4, 6, 9, 12, 18, 36$

$1, 2, 3, 4, 6, 9, 12, 18$

$1, 2, 3, 4, 6, 9, 12, 18, 36$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 36, to find all factor pairs: systematically check divisibility starting from 1: 1×36, 2×18, 3×12, 4×9, 6×6, and list all unique factors: 1,2,3,4,6,9,12,18,36. Choice A is correct because all factors are listed (checked all numbers 1 through √36=6) and none are missing or extra, demonstrating systematic factor finding and understanding of prime/composite definitions. Choice B represents including non-factors, which happens when students include numbers that don't divide evenly like 8 (36÷8=4.5). To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

4

A factor is a whole number that divides another number evenly (with no remainder). Find all factor pairs for $24$.

$(1, 24), (2, 12), (3, 8)$

$(1, 24), (2, 12), (4, 6), (8, 3)$

$(1, 24), (2, 11), (3, 8), (4, 6)$

$(1, 24), (2, 12), (3, 8), (4, 6)$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 24, to find all factor pairs: systematically check divisibility starting from 1: 1×24, 2×12 if even, 3×8 if divisible, 4×6 if divisible, continuing until factors repeat. Choice B is correct because all pairs are listed (checked all numbers 1 through √24 ≈4.9) and none are missing, including (4,6), which demonstrates systematic factor finding and understanding of prime/composite definitions. Choice A represents missing factor pairs, which happens when students don't check all possible factors systematically. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

5

A factor is a whole number that divides another number evenly (with no remainder). Find all factor pairs for $64$.

$(1, 64), (2, 32), (4, 16)$

$(1, 64), (2, 32), (4, 16), (8, 8)$

$(1, 64), (2, 32), (8, 8), (16, 4)$

$(1, 64), (2, 32), (3, 21), (4, 16), (8, 8)$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 64, to find all factor pairs: systematically check divisibility starting from 1: 1×64, 2×32, 4×16, 8×8, continuing until factors repeat. Choice A is correct because all pairs are listed (checked all numbers 1 through √64=8) and none are missing. Choice B represents missing factor pairs, which happens when students stop too early. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

6

A factor is a whole number that divides another number evenly (no remainder). List all the factors of $18$.

$1, 3, 6, 9$

$2, 3, 6, 9, 18$

$1, 2, 3, 6, 9, 18$

$1, 2, 3, 4, 6, 9, 18$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 18, to find all factors: systematically check divisibility starting from 1 up to 18, listing all that divide evenly: 1,2,3,6,9,18. Choice A is correct because all factors are listed (checked all numbers 1 through 18) and none are missing or extra. This demonstrates systematic factor finding and understanding of prime/composite definitions. Choice B represents including non-factors, which happens when students include numbers that don't divide evenly. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

7

A factor is a whole number that divides another number evenly (with no remainder). List all the factors of $45$.

$3, 5, 9, 15$

$1, 5, 9, 10, 15, 45$

$1, 3, 5, 9, 45$

$1, 3, 5, 9, 15, 45$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 45, to find all factors: systematically check divisibility starting from 1 up to √45≈6.7, listing 1,3,5,9,15,45 since they divide evenly. Choice A is correct because all factors are listed (checked all numbers 1 through √45) and none are missing. Choice B represents including non-factors, which happens when students include numbers that don't divide evenly. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

8

A factor is a whole number that divides another number evenly (no remainder). List all the factors of $36$.

$1, 2, 3, 4, 6, 9, 12, 18, 36$

$1, 2, 3, 4, 6, 9, 12, 18$

$2, 3, 4, 6, 9, 12, 18, 36$

$1, 2, 3, 4, 5, 6, 9, 12, 18, 36$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 36, to find all factors: systematically check divisibility starting from 1 up to 36, listing all that divide evenly: 1,2,3,4,6,9,12,18,36. Choice A is correct because all factors are listed (checked all numbers 1 through 36) and none are missing or extra. This demonstrates systematic factor finding and understanding of prime/composite definitions. Choice B represents including non-factors, which happens when students include numbers that don't divide evenly. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

9

A factor is a whole number that divides another number evenly (with no remainder). Is $29$ prime or composite? Use the fact that prime numbers have exactly 2 factors.

Composite, because $29$ has factors $1, 2, 29$.

Prime, because its only factors are $1$ and $29$.

Composite, because $29$ is odd.

Prime, because all numbers ending in $9$ are prime.

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 29, to determine prime or composite: count factors—if exactly 2 factors (1 and 29) then prime, if more than 2 then composite. Choice B is correct because the number has exactly 2 factors (only 1 and itself divide evenly), which demonstrates systematic factor finding and understanding of prime/composite definitions. Choice C represents wrong prime/composite determination, which happens when students make division error like thinking 2 divides 29 (29÷2=14.5). To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

10

A factor is a whole number that divides another number evenly (with no remainder). $12$ objects can be arranged into rectangular arrays. Which list shows all possible arrays?

$1\times 12,\ 3\times 4,\ 6\times 2$

$1\times 12,\ 2\times 5,\ 3\times 4$

$1\times 12,\ 2\times 6,\ 3\times 4$

$1\times 12,\ 2\times 6$

Explanation

This question tests 4th grade ability to find all factor pairs for whole numbers 1-100, recognize that a number is a multiple of each of its factors, determine if a number is a multiple of a given one-digit number, and determine whether a number is prime or composite (CCSS.4.OA.4). A factor is a whole number that divides another number evenly with no remainder—if a × b = n, then both a and b are factors of n, and (a, b) is a factor pair. To find all factor pairs, systematically check: does 1 divide n? does 2? does 3? and so on up to √n, stopping when factors start repeating. A prime number has exactly 2 factors (1 and itself), while a composite number has more than 2 factors. The number 1 is special—it's neither prime nor composite (only 1 factor). For the number 12, to find all factor pairs: systematically check divisibility starting from 1: 1×12, 2×6, 3×4, and these correspond to rectangular arrays. Choice A is correct because all pairs are listed (checked all numbers 1 through √12≈3.46) and none are missing, demonstrating systematic factor finding and understanding of prime/composite definitions. Choice B represents including non-factors, which happens when students include pairs that don't multiply to 12 like 2×5=10. To help students: For finding factor pairs, use systematic approach—start with 1 (always works), check 2, 3, 4, 5, etc., stop when you start seeing the same pairs reversed. Example for 24: 1×24 ✓, 2×12 ✓, 3×8 ✓, 4×6 ✓, 5 doesn't work, 6×4 (already have 4×6, stop). For prime/composite, count factors: exactly 2 = prime, more than 2 = composite. Remember: 1 is neither (only 1 factor), 2 is only even prime. For multiples, divide: if no remainder, it IS a multiple (48 ÷ 6 = 8 R0 ✓). Use arrays to visualize: 12 objects can arrange as 1×12, 2×6, 3×4—each arrangement shows a factor pair. Connect: if f is a factor of n, then n is a multiple of f (inverse relationship). Watch for: missing factor pairs, including non-factors, calling 1 prime, thinking all odd numbers are prime (9, 15, 21 are composite), confusing factors with multiples, and not checking systematically.

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