4th Grade Math - Multiply Multi-Digit Numbers: CCSS.Math.Content.4.NBT.B.5

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 2\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 2$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 10.32.59 am

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 2}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 2}\end{array}}{\ \ \ 20}$

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 3\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 3$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 11.07.48 am

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 3}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 3}\end{array}}{\ \ \ 30}$

Solve:

$\frac{\begin{array}[b]{r}13\ \times\ 2\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $13\times 2$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 2.15.20 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 3}\ \times\ {\color{Red} 2}\end{array}}{\ \ \ \ 6}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}3\ \times\ {\color{Red} 2}\end{array}}{\ \ \ 26}$

Solve:

$\frac{\begin{array}[b]{r}13\ \times\ 4\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $13\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 2.05.45 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 3}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 2}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}3\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 52}$

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 6\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 6$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 12.53.41 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 2}\ \times\ {\color{Red} 6}\end{array}}{\ \ \ \ 2}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}2\ \times\ {\color{Red} 6}\end{array}}{\ \ \ 72}$

Solve:

$\frac{\begin{array}[b]{r}13\ \times\ 6\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $13\times 6$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 1.11.14 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 3}\ \times\ {\color{Red} 6}\end{array}}{\ \ \ \ 8}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}3\ \times\ {\color{Red} 6}\end{array}}{\ \ \ 78}$

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 4\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 12.36.48 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 2}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 8}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}2\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 48}$

Solve:

$\frac{\begin{array}[b]{r}12\ \times\ 5\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $12\times 5$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 12.45.25 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}^11{\color{Red} 2}\ \times\ {\color{Red} 5}\end{array}}{\ \ \ \ 0}$

Because the product is greater than , we carry the and add it to the next product.

Next, we multiply and and then add the we carried.

$\frac{\begin{array}[b]{r}^1{\color{Red} 1}2\ \times\ {\color{Red} 5}\end{array}}{\ \ \ 60}$

Solve:

$\frac{\begin{array}[b]{r}10\ \times\ 4\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $10\times 4$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 12.00.41 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.

First, we multiply and

$\frac{\begin{array}[b]{r}1{\color{Red} 0}\ \times\ {\color{Red} 4}\end{array}}{\ \ \ \ 0}$

Next, we multiply and

$\frac{\begin{array}[b]{r}{\color{Red} 1}0\ \times\ {\color{Red} 4}\end{array}}{\ \ \ 40}$

Solve:

$\frac{\begin{array}[b]{r}11\ \times\ 5\end{array}}{\space }$

Explanation

We can make a rectangular array using squares to help us solve this problem. Our multiplication problem is $11\times 5$ ; therefore, the rectangular array should have squares across the top row and squares down the first column. The rectangular array should look like the image below:

Screen shot 2016 05 18 at 12.14.20 pm

We can count the squares to find our answer. The correct answer is is

In order to solve this problem using multiplication, we must multiply the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, is the multiplier and is the multiplicand.