We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividing by , we need to split up our into groups of

We can see that we have 2 groups of 2, thus the answer is 2.

The problem that you are challenged to solve is .

is the dividend, this is what is being broken up into groups. is our divisor which is the number of groups you are making. We need to split in half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what can be multiplied by to make or get close to it without going over. is the fact that works best ( is too large). We will place the numeral directly above the in the ones place to indicate that groups of fit into the . We will put the product of which was underneath the in the ones place and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the in the tenths place down and put it next to the . We will work with the numbers as if they were when thinking of multiplication facts, but it should be noted this is actually when you consider the decimal placement. so we place the above the "house" in the tenths place of our quotient and subtract the . We are left with remaining so there is no remainder.

Our final answer is , which means that half of is

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividing by , we need to split up our into groups of :

As you can see, we have groups; thus,

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividing by , we need to split up our into groups of

As you can see, we have groups; thus,

The problem that you are challenged to solve is .

is the dividend, this is what is being broken up into groups. is our divisor which is the number of groups you are making. We need to split in thirds to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what can be multiplied by to make or get close to it without going over. is the fact that works best ( is too large). We will place the numeral directly above the in the ones place to indicate that groups of fit into the . We will put the product of which was underneath the and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the in the tenths place down and put it next to the . We will work with the numbers as if they were when thinking of multiplication facts, but it should be noted this is actually when you consider the decimal placement. so we place the above the "house" in the tenths place of our quotient and subtract the . We are left with remaining.

Finally, we carry down the from the hundredths place and place it next to the giving us (or for the purpose of our multiplication facts.) so we place the above the in the hundredths place on top of our "house" and subtract the leaving us with a remainder of .

Our final answer is

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividing by , we need to split up our into groups of

As you can see, we have groups. Thus the answer is .

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent .2

Because we are dividing .2 by .2, we need to split up our .2 into groups of .2:

We can see that we have 1 group, thus our answer is 1.

The problem that you are challenged to solve is .

is the dividend, this is what is being broken up into groups. is our divisor which is the number of groups you are making. We need to split in quarters to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what can be multiplied by to make or get close to it without going over. is the fact that works best. We will place the numeral directly above the in the ones place to indicate that groups of fit into the . We will put the product of which was underneath the and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the in the tenths place down and put it next to the . so we place the above the "house" in the tenths place of our quotient and subtract the . We are left with remaining.

Finally, we carry down the from the hundredths place and place it next to the . so we place the above the in the hundredths place on top of our "house" and subtract the leaving us with a remainder of .

Our final answer is

The problem that you are challenged to solve is .

is the dividend, this is what is being broken up into groups. is our divisor which is the number of groups you are making. We need to split in half to see how many are in each group.

The first step is to place your decimal above your equation in the same place. It will line up with the decimal inside of your "long-division house".

Next, we need to use or multiplication facts to determine what can be multiplied by to make or get close to it without going over. is the fact that works best. We will place the numeral directly above the in the ones place to indicate that groups of fit into the . We will put the product of which was underneath the and subtract the difference. The numbers above the "house" are our quotient or answer to the division problem.

Next, we will carry the in the tenths place down and put it next to the . so we place the above the "house" in the tenths place of our quotient and subtract the . We are left with remaining so there is no remainder.

Our final answer is , which means that half of is

We can use base ten blocks to help us solve this problem. First, we want to use base ten blocks to represent

Because we are dividing by , we need to split up our into groups of :

As you can see, we have groups; thus,