Understand Powers of 10 Patterns

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5th Grade Math › Understand Powers of 10 Patterns

Questions 1 - 10
1

A recipe uses $0.35$ liters of milk. The cook writes the number sentence $0.35 \times 10^1$ to convert to a different unit. Powers of 10 affect place value positions by shifting digits into new places. Which statement correctly describes the pattern and the result?

Each digit shifts 1 place value position to the left, so the result is 3.5.

You add 10 one time to 0.35, so the result is 10.35.

You add one zero to the end no matter what, so the result is 0.350.

Each digit shifts 1 place value position to the right, so the result is 0.035.

Explanation

Powers of 10 change place value by altering digit positions, as in converting 0.35 × $10^1$ for a recipe. Multiplying by $10^1$ shifts digits one place left, turning 0.35 into 3.5. Dividing by powers of 10 shifts digits right, decreasing the value. This links to digit positions, moving a tenths digit to the ones place with a left shift. A misconception is always adding a zero at the end for ×10, but with decimals, it's about moving the decimal point right. These patterns allow for fast unit conversions and calculations. They support efficient math in practical situations like cooking or measuring.

2

A student is working with the number sentence $905 \div 10^2$. Powers of 10 affect place value positions by shifting digits into new places. Which statement best explains how the digits shift and what the result should be?

Each digit shifts 2 place value positions to the right, so 905 becomes 9.05.

You add two zeros to the end because 100 has two zeros, so 905 becomes 90,500.

You subtract 100 twice from 905, so 905 becomes 705.

Each digit shifts 2 place value positions to the left, so 905 becomes 90,500.

Explanation

Powers of 10 change place value via digit shifts, as in 905 ÷ $10^2$. Multiplying by powers of 10 shifts digits left to enlarge the number. Dividing by $10^2$ shifts digits two places right, changing 905 to 9.05. This relates to digit positions, where right shifts move from hundreds to ones, then tenths, and so on. A misconception is adding zeros when dividing, but division actually introduces decimal places. Recognizing these patterns speeds up division without full processes. They foster efficiency in adjusting numbers for different scales.

3

A coach records a time of $350$ seconds and writes the number sentence $350 \div 10^1$ to convert it to a smaller number. Powers of 10 change place value positions, so the digits shift.

Text evidence of digit shift:

  • Before: 3 hundreds, 5 tens, 0 ones
  • After dividing by $10^1$: each digit shifts 1 place to the right

Which statement is correct?

Dividing by $10^1$ shifts digits 1 place left, so $350 \div 10^1 = 3{,}500$.

Dividing by $10^1$ always makes the number larger, so $350 \div 10^1$ must be greater than $350$.

Dividing by $10^1$ shifts digits 1 place right, so $350 \div 10^1 = 35$.

Dividing by $10^1$ means subtracting 10 one time, so $350 \div 10^1 = 340$.

Explanation

Powers of 10 change the place value of digits in a number. Multiplying by a power of 10 shifts digits to the left, increasing the number's value. When dividing a number like 350 by a power of 10 such as $10^1$, the digits shift to the right by 1 place, making each digit's value 10 times smaller and resulting in 35. This shifting connects to digit positions, where right shifts move digits to lower place values like from hundreds to tens. A common misconception is that dividing by $10^1$ makes the number larger, but it actually decreases the value. Recognizing these patterns enables quick conversions, such as changing units in time or measurements. This helps us work efficiently by avoiding long division and focusing on place value shifts.

4

A student is matching a number sentence to its result. Consider the number sentence $0.405 \times 10^1$. Powers of 10 change place value positions, so multiplying by $10^1$ shifts each digit 1 place to the left.

Which value matches $0.405 \times 10^1$?

$0.0405$

$0.4050$

$4.05$

$40.5$

Explanation

Powers of 10 change the place value of digits in a number. When multiplying a number like 0.405 by $10^1$, the digits shift left by 1 place, resulting in 4.05 as the decimal point moves right. Dividing by a power of 10 shifts digits right, decreasing the value. This shifting connects to digit positions, where even small shifts change decimals to whole numbers or vice versa. A common misconception is that multiplying adds trailing zeros without shifting, but it affects the entire place value. Understanding these patterns enables matching number sentences to results quickly. This helps work efficiently in tasks requiring precise decimal adjustments.

5

A coach records a distance as the number sentence $3{,}250 \div 10^1$. Powers of 10 affect place value positions by shifting digits into new places. Which statement explains how dividing by $10^1$ (10) changes the digits?

You subtract 10 from 3,250 one time, so the result is 3,240.

Each digit shifts 1 place value position to the left because dividing by 10 makes the number larger, so the result is 32,500.

Each digit shifts 1 place value position to the right because dividing by 10 makes each place ten times smaller, so the result is 325.

You add one zero to the end because 10 has one zero, so the result is 32,500.

Explanation

Powers of 10 change place value by shifting digits to new positions, as in the division 3,250 ÷ $10^1$. When multiplying by powers of 10, digits shift left by the exponent, making the number larger. When dividing by powers of 10, like dividing by $10^1$ which is 10, digits shift right by one place, making each place value ten times smaller, resulting in 325. This connects to digit positions, where a right shift moves a digit from, say, the hundreds place to the tens place. A misconception is that dividing by 10 means subtracting 10, but it's actually about scaling down the place values. Patterns like these enable quick mental math for resizing numbers without long division. They promote efficiency in problem-solving across various math applications.

6

A science class measures $0.63$ liters of water and writes the number sentence $0.63 \times 10^3$ to express it in a larger amount. Powers of 10 change place value positions.

Text evidence of digit shift:

  • Before: 0 ones, 6 tenths, 3 hundredths
  • After multiplying by $10^3$: each digit shifts 3 places to the left

Which statement correctly describes the digit shift and result?

You add $0.63$ three more times because $10^3$ means repeated addition, so the result is $2.52$.

The digits shift 3 places to the left, so $0.63$ becomes $630$ because each digit becomes 1,000 times larger.

The digits shift 3 places to the right, so $0.63$ becomes $0.00063$ because each digit becomes 1,000 times smaller.

You add three zeros to 0.63 without shifting digits, so the result is $0.63000$.

Explanation

Powers of 10 change the place value of digits in a number. When multiplying a number like 0.63 by a power of 10 such as $10^3$, the digits shift to the left by 3 places, making each digit's value 1,000 times larger and resulting in 630. Conversely, dividing by a power of 10 shifts the digits to the right, decreasing the number's value. This shifting connects to digit positions, where left shifts move digits from decimal places to whole number places. A common misconception is that multiplying by $10^3$ shifts digits right, but it actually shifts left to increase the value. Understanding these patterns allows for rapid calculations in science, like scaling measurements. This efficiency aids in working with very large or small quantities without errors.

7

A student compares two number sentences: $58 \times 10^1$ and $58 \times 10^2$. Powers of 10 change place value positions, so the digits shift left when multiplying.

Which statement correctly compares the results and explains the pattern?

$58 \times 10^1 = 580$ and $58 \times 10^2 = 5{,}800$ because shifting left 2 places makes the number 10 times larger than shifting left 1 place.

$58 \times 10^1 = 68$ and $58 \times 10^2 = 78$ because multiplying by powers of 10 means adding 10 or 100.

$58 \times 10^1 = 580$ and $58 \times 10^2 = 5{,}800$ because shifting left 2 places makes the number 10 times smaller than shifting left 1 place.

$58 \times 10^1 = 5.8$ and $58 \times 10^2 = 0.58$ because multiplying shifts digits to the right.

Explanation

Powers of 10 change the place value of digits in a number. Multiplying by powers of 10, such as 58 × $10^1$ resulting in 580 and 58 × $10^2$ resulting in 5,800, shifts digits left, with each additional exponent making the result 10 times larger. Dividing by powers of 10 shifts digits right, reducing the value accordingly. This shifting connects to digit positions, where the exponent determines how many places digits move. A common misconception is that higher exponents make numbers smaller, but actually, for multiplication, they make numbers larger. Recognizing these patterns helps compare results quickly without calculating each time. This allows efficient scaling in problems involving growth or patterns in math.

8

A student solves the number sentence $7.02 \div 10^2$ and writes $702$ as the answer. Powers of 10 change place value positions, so dividing by $10^2$ should shift digits.

Text evidence of the intended shift:

  • Dividing by $10^2$ shifts each digit 2 places to the right

Which statement best identifies the error and gives the correct result?

The student should have subtracted 100 because $10^2$ means repeated subtraction; the correct result is $6.02$.

The student shifted digits 2 places left instead of right; the correct result is $0.0702$.

There is no error because dividing by $10^2$ always makes the number larger; $702$ is reasonable.

The student forgot to add two zeros; the correct result is $7.0200$.

Explanation

Powers of 10 change the place value of digits in a number. Multiplying by a power of 10 shifts digits to the left, increasing the value. When dividing a number like 7.02 by $10^2$, the digits should shift right by 2 places, resulting in 0.0702, not left as the student did to get 702. This shifting connects to digit positions, where errors occur if the direction is reversed. A common misconception is confusing multiplication with division, leading to shifting left instead of right. Understanding these patterns helps identify and correct errors in place value shifts. This promotes efficient problem-solving by verifying results through patterns rather than recalculation.

9

A store has a ribbon length of $900$ centimeters and writes the number sentence $900 \div 10^3$. Powers of 10 change place value positions.

Text evidence of digit shift:

  • 900 has digits 9, 0, 0 in the hundreds, tens, and ones places
  • Dividing by $10^3$ shifts each digit 3 places to the right

How does dividing by $10^3$ change the number, and what is the result?

The digits shift 3 places to the left, so $900 \div 10^3 = 900{,}000$.

You remove three zeros without shifting digits, so $900 \div 10^3 = 9$.

The digits shift 3 places to the right, so $900 \div 10^3 = 0.9$.

Dividing by $10^3$ always makes a number bigger, so the result must be greater than $900$.

Explanation

Powers of 10 change the place value of digits in a number. Multiplying by a power of 10 shifts digits left, making the number larger. When dividing a number like 900 by $10^3$, the digits shift right by 3 places, making each digit's value 1,000 times smaller and resulting in 0.9. This shifting connects to digit positions, moving from whole numbers to decimals when shifting right multiple places. A common misconception is that dividing removes zeros without shifting, but it actually requires proper place value adjustment. Recognizing these patterns allows quick unit conversions, like from centimeters to kilometers. This efficiency helps in handling large-scale divisions in everyday math tasks.

10

A student is deciding which explanation is correct for the number sentence $3.5 \div 10^1$. Powers of 10 change place value positions.

Which statement correctly explains what happens to the digits?

Dividing by $10^1$ shifts each digit 1 place to the right, so $3.5$ becomes $0.35$ because each digit is worth 10 times less.

Dividing by $10^1$ shifts each digit 1 place to the left, so $3.5$ becomes $35$ because each digit is worth 10 times more.

Dividing by $10^1$ always makes numbers larger, so $3.5 \div 10^1$ must be greater than $3.5$.

Dividing by $10^1$ means subtracting 10 one time, so $3.5$ becomes $-6.5$.

Explanation

Powers of 10 change the place value of digits in a number. Multiplying by a power of 10 shifts digits left, increasing the value. When dividing a number like 3.5 by $10^1$, the digits shift right by 1 place, making each digit 10 times smaller and resulting in 0.35. This shifting connects to digit positions, moving from ones to tenths in this case. A common misconception is that division by 10 makes numbers larger, but it actually decreases them. Understanding these patterns helps explain digit movements accurately. This allows efficient verification of explanations in math problems.

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