7th Grade Math - Describe Situations in Which Opposite Quantities Combine to Make 0: CCSS.Math.Content.7.NS.A.1a

For the equation provided, what value, when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}3+x=0\ -3\ \ \ \ -3\end{array}}{\\x=-3}$

For the equation provided, what value when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}59+x=0\ -59\ \ \ \ -59\end{array}}{\\x=-59}$

For the equation provided, what value when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}70+x=0\ -70\ \ \ \ -70\end{array}}{\\x=-70}$

For the equation provided, what value, when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}83-x=0\ +x+x\end{array}}{\\83=x}$

For the equation provided, what value, when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}10+x=0\ -10\ \ \ \ -10\end{array}}{\\x=-10}$

For the equation provided, what value, when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can add to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}27-x=0\ +x+x\end{array}}{\\27=x}$

For the equation provided, what value, when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}41+x=0\ -41\ \ \ \ -41\end{array}}{\\x=-41}$

Compute the following:

Explanation

Convert all the double signs to a single sign before solving. Remember, two minus (negative) signs combine to form a plus (positive) sign, and a plus (positive) sign and a minus (negative) sign combine to form a minus (negative) sign.

For the equation provided, what value when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}99+x=0\ -99\ \ \ \ -99\end{array}}{\\x=-99}$

For the equation provided, what value when substituted for , will equal

Explanation

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}38+x=0\ -38\ \ \ \ -38\end{array}}{\\x=-38}$

Describe Situations in Which Opposite Quantities Combine to Make 0: CCSS.Math.Content.7.NS.A.1a

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