How to find the area of a pentagon - ACT Math

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Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

Question

Suppose the side length of a pentagon is . What is the area of the pentagon?

Answer

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Compare your answer with the correct one above

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How to find the area of a pentagon - ACT Math

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Suppose the side length of a pentagon is . What is the area of the pentagon?

Write the formula for the area of a pentagon. Substitute the side length and simplify the radical.

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$

Write the formula for the area of a pentagon.

$A=\frac{1}{4}s^2\sqrt{5(5+2\sqrt5)}$

Substitute the side length and simplify the radical.

$A=\frac{1}{4}(4)^2\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{5(5+2\sqrt5)}$

$A=4\sqrt{25+10\sqrt5}$