How to find the area of an acute / obtuse isosceles triangle - ACT Math

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Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

Answer

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Compare your answer with the correct one above

Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

Answer

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Compare your answer with the correct one above

Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

Answer

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Compare your answer with the correct one above

Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

Answer

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

Question

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

Answer

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

Question

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

Answer

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Compare your answer with the correct one above

Question

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

Answer

Based on the description of your triangle, you can draw the following figure:

You can do this because you know:

The two equivalent sides are given.

Since a triangle is degrees, you have only or degrees left for the two angles of equal size. Therefore, those two angles must be degrees and degrees.

Now, based on the properties of an isosceles triangle, you can draw the following as well:

Based on your standard reference triangle, you know:

$\frac{h}{4}=\frac{1}{2}$

Therefore, is .

This means that is $2\sqrt{3}$ and the total base of the triangle is $4\sqrt{3}$ .

Now, the area of the triangle is:

$\frac{1}{2}bh$ or $\frac{1}{2}24\sqrt{3}=4\sqrt{3}:cm^2$

Compare your answer with the correct one above

Question

An isosceles triangle has a height of and a base of . What is its area?

Answer

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

Compare your answer with the correct one above

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How to find the area of an acute / obtuse isosceles triangle - ACT Math

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

1. Find the height of the triangle: 2. Use the formula for area of a triangle:

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

1. Find the height of the triangle: 2. Use the formula for area of a triangle:

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

1. Find the height of the triangle: 2. Use the formula for area of a triangle:

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

1. Find the height of the triangle: 2. Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

1. Find the height of the triangle: 2. Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

An isosceles triangle has a base length of and a height that is twice its base length. What is the area of this triangle?

1. Find the height of the triangle: 2. Use the formula for area of a triangle:

What is the area of an isosceles triangle with a vertex of degrees and two sides equal to ?

An isosceles triangle has a height of and a base of . What is its area?

Use the formula for area of a triangle:

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$

1. Find the height of the triangle:

$height=2\cdot base$

2. Use the formula for area of a triangle:

$A=\frac{1}{2}(b)(h)$

$A=\frac{1}{2}(10)(20)=100$

Use the formula for area of a triangle:

$A=\frac{1}{2}(base)(height)$

$A=\frac{1}{2}(4)(7)=14$