This is a calculation and prediction question requiring you to read values from a graph and determine the change. Figure 2 shows oxygen solubility at 20°C is approximately 9 mg/L and at 40°C is approximately 6 mg/L. The change is 6 - 9 = -3 mg/L (a decrease of 3 mg/L). Since the curve slopes downward (gas solubility decreases with temperature), warming the lake causes oxygen loss. Choice C (decrease by approximately 3 mg/L) is correct. Choices A and B suggest increases, which contradicts the downward-sloping curve. Choice D (decrease by 6 mg/L) would be the change from 9 mg/L to 3 mg/L (from 20°C to 60°C), not to 40°C. Pro tip: For change questions, read both values carefully and subtract to find the difference.

This is a graph interpolation question testing your ability to read values between plotted data points. Figure 1 shows KNO₃ solubility at 40°C is approximately 60 g and at 60°C is approximately 110 g. The question asks for the value at 50°C, which falls exactly between these two temperatures. Since 50°C is the midpoint between 40°C and 60°C, you can estimate the solubility as roughly the midpoint between 60 g and 110 g. The midpoint is (60 + 110) ÷ 2 = 85 g. Choice C (85 g) is correct. Choice A (30 g) is far too low. Choice B (60 g) is the value at 40°C, not 50°C. Choice D (110 g) is the value at 60°C. Pro tip: For interpolation, locate the two surrounding known points and estimate between them.

This is a calculation and prediction question requiring you to read values from a graph and determine the change. Figure 2 shows oxygen solubility at 20°C is approximately 9 mg/L and at 40°C is approximately 6 mg/L. The change is 6 - 9 = -3 mg/L (a decrease of 3 mg/L). Since the curve slopes downward (gas solubility decreases with temperature), warming the lake causes oxygen loss. Choice C (decrease by approximately 3 mg/L) is correct. Choices A and B suggest increases, which contradicts the downward-sloping curve. Choice D (decrease by 6 mg/L) would be the change from 9 mg/L to 3 mg/L (from 20°C to 60°C), not to 40°C. Pro tip: For change questions, read both values carefully and subtract to find the difference.

This is a graph reading question. At 2,000 km depth (within the Mantle), trace up to the solid P-wave line. The specification indicates P-waves "increase steadily through the Mantle to ~13 km/s at 2,900 km." At 2,000 km (about 70% through the mantle from 40 to 2,900), the velocity should be around 11-12 km/s. Choice C (12 km/s) is correct. Choice A (7 km/s) is too low. Choice B (10 km/s) is slightly low. Choice D (14 km/s) exceeds the maximum shown. Pro tip: For reading between points, estimate based on the curve's position relative to nearby values.

This is a trend reading question. Following the Mouse curve in Figure 1 from 5°C to 25°C, the metabolic rate starts at approximately 5.5 mL and decreases to approximately 1.5 mL at 25°C. This is a consistent downward trend throughout this temperature range. Choice B (decreases only) is correct. Note that the curve does increase slightly after 25°C (at 35°C it rises to ~2.0), but the question specifically asks about 5°C to 25°C, not the full range. Choice A (increases) is opposite. Choice C (decreases then increases) would be correct for the full 5-35°C range, but not for the 5-25°C range specified. Choice D (constant) is wrong. Pro tip: Read question limits carefully—answer based on the specified range only.

The bar graph compares rainfall totals for April (45 mm), May (62 mm), June (80 mm), and July (55 mm). May's bar at 62 mm is closest to 60 mm, as it's only 2 mm above while others differ more. This is correct because comparing bar heights to the target value identifies the nearest, demonstrating bar graph comparison. Option C, July at 55 mm, is close but farther from 60 than May.

The graph depicts bacterial population doubling every 2 hours, from 1 at 0 h, to 2 at 2 h, 4 at 4 h, 8 at 6 h, and 16 at 8 h. Extrapolating the trend to 10 h gives 32 million cells, as it doubles from 16. This is correct because continuing the pattern assumes the same growth rate, illustrating extrapolation from graphs. Option C, 24 million, might result from adding instead of multiplying.

The graph shows the temperature of the cooling rod decreasing over time, with the curve passing through points like (0, 200), (5, 120), (10, 85), (15, 65), and (20, 55). To find the temperature at 10 minutes, follow the x-axis to 10 min, go up to the curve, and read across to the y-axis, which gives approximately 85 °C. This is correct because the graph directly indicates 85 °C at that point, demonstrating how to read a specific value from a line graph. Option C, 65 °C, might be chosen if someone misreads the time as 15 minutes instead.

The scatter plot shows cart speed increasing with ramp angle, with points clustering around (5, 0.6), (10, 1.0), (15, 1.4), (20, 1.9), (25, 2.3), and (30, 2.8). The overall trend is a steady rise, best described as speed generally increasing as ramp angle increases. This is correct because the pattern of points demonstrates a positive correlation, illustrating how to interpret trends in scatter plots. Option D might mislead if someone sees a false peak at 15° due to not viewing the full trend.

The Desert habitat had the fewest insects observed according to Figure 1. Comparing the bar heights for all five habitats (Field, Forest, Pond, Garden, Desert), the Desert bar is clearly the shortest, indicating the lowest insect count during the 1-hour survey period.