Solving Absolute Value Equations - Algebra 2
Card 0 of 300
An individual's heart rate during exercise is between 
and 
of the individual's maximum heart rate. The maximum heart rate of a 
year old is 
beats per minute. Express a 
year old's target heart rate in an absolute value equation. Note: round the 
and 
endpoints to the nearest whole number.
An individual's heart rate during exercise is between
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We start by finding the midpoint of the interval, which is enclosed by 60% of 204 and 80% of 204.
We find the midpoint, or average, of these endpoints by adding them and dividing by two:
142.5 is exactly 20.5 units away from both endpoints, 122 and 163. Since we are looking for the range of numbers between 122 and 163, all possible values have to be within 20.5 units of 142.5. If a number is greater than 20.5 units away from 142.5, either in the positive or negative direction, it will be outside of the \[122, 163\] interval. We can express this using absolute value in the following way:
We start by finding the midpoint of the interval, which is enclosed by 60% of 204 and 80% of 204.
We find the midpoint, or average, of these endpoints by adding them and dividing by two:
142.5 is exactly 20.5 units away from both endpoints, 122 and 163. Since we are looking for the range of numbers between 122 and 163, all possible values have to be within 20.5 units of 142.5. If a number is greater than 20.5 units away from 142.5, either in the positive or negative direction, it will be outside of the \[122, 163\] interval. We can express this using absolute value in the following way:
Solve the inequality:
Solve the inequality:
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The inequality compares an absolute value function with a negative integer. Since the absolute value of any real number is greater than or equal to 0, it can never be less than a negative number. Therefore, 
can never happen. There is no solution.
The inequality compares an absolute value function with a negative integer. Since the absolute value of any real number is greater than or equal to 0, it can never be less than a negative number. Therefore,
Solve for 
:
Solve for
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Solve for positive values by ignoring the absolute value. Solve for negative values by switching the inequality and adding a negative sign to 7.
Solve for positive values by ignoring the absolute value. Solve for negative values by switching the inequality and adding a negative sign to 7.
Give the solution set for the following equation:
Give the solution set for the following equation:
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First, subtract 5 from both sides to get the absolute value expression alone.
Split this into two linear equations:
or
The solution set is 
First, subtract 5 from both sides to get the absolute value expression alone.
Split this into two linear equations:
or
The solution set is
In order to ride a certain roller coaster at an amusement park an individual needs to be between 
and 
pounds. Express this rule using an absolute value.
In order to ride a certain roller coaster at an amusement park an individual needs to be between
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We start by finding the midpoint of the interval, which is enclosed by 90 and 210. We find the midpoint, or average, of these two endpoints by adding them and dividing by two:
150 is exactly 60 units away from both endpoints, 90 and 210. Since we are looking for the range of numbers that fall in between 90 and 210, this means that any possible value can't be more than 60 units away from 150. If a number is more than 60 units away from 150, in either the increasing or decreasing direction, it will be outside of the \[90, 210\] interval. We can express this using absolute value in the following way:
We start by finding the midpoint of the interval, which is enclosed by 90 and 210. We find the midpoint, or average, of these two endpoints by adding them and dividing by two:
150 is exactly 60 units away from both endpoints, 90 and 210. Since we are looking for the range of numbers that fall in between 90 and 210, this means that any possible value can't be more than 60 units away from 150. If a number is more than 60 units away from 150, in either the increasing or decreasing direction, it will be outside of the \[90, 210\] interval. We can express this using absolute value in the following way:
Solve for 
.
Solve for
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Divide both sides by 3.
Consider both the negative and positive values for the absolute value term.
Subtract 2 from both sides to solve both scenarios for 
.
Divide both sides by 3.
Consider both the negative and positive values for the absolute value term.
Subtract 2 from both sides to solve both scenarios for
Solve for 
in the inequality below.
Solve for
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The absolute value gives two problems to solve. Remember to switch the "less than" to "greater than" when comparing the negative term.
or 
Solve each inequality separately by adding 
to all sides.
or 
This can be simplified to the format 
.
The absolute value gives two problems to solve. Remember to switch the "less than" to "greater than" when comparing the negative term.
Solve each inequality separately by adding
This can be simplified to the format
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Solve the inequality.
Solve the inequality.
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Remove the absolute value by setting the term equal to either 
or 
. Remember to flip the inequality for the negative term!
Solve each scenario independently by subtracting 
from both sides.
Remove the absolute value by setting the term equal to either
Solve each scenario independently by subtracting
Solve for 
:
Solve for
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To solve absolute value equations, we must understand that the absoute value function makes a value positive. So when we are solving these problems, we must consider two scenarios, one where the value is positive and one where the value is negative.
and
This gives us:
and 
However, this question has an 
outside of the absolute value expression, in this case 
. Thus, any negative value of 
will make the right side of the equation equal to a negative number, which cannot be true for an absolute value expression. Thus, 
is an extraneous solution, as 
cannot equal a negative number.
Our final solution is then
To solve absolute value equations, we must understand that the absoute value function makes a value positive. So when we are solving these problems, we must consider two scenarios, one where the value is positive and one where the value is negative.
and
This gives us:
However, this question has an
Our final solution is then
Solve for 
:
Solve for
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The absolute value of any number is nonnegative, so 
must always be greater than 
. Therefore, any value of 
makes this a true statement.
The absolute value of any number is nonnegative, so
Solve the following absolute value inequality:
Solve the following absolute value inequality:
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To solve this inequality, it is best to break it up into two separate inequalities to eliminate the absolute value function:
or 
.
Then, solve each one separately:
Combining these solutions gives: 
To solve this inequality, it is best to break it up into two separate inequalities to eliminate the absolute value function:
Then, solve each one separately:
Combining these solutions gives:
Which values of 
provide the full solution set for the inequality:
Which values of 
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A certain doctor's office specializes in treating patients 
years old or younger, and 
years old or older. Patients between 
and 
years of age are referred elsewhere. Express the allowed patient population in terms of an absolute value.
A certain doctor's office specializes in treating patients
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We start problems like these by finding the midpoint of the two endpoints, which in this case are 21 and 65. We find the midpoint, or average, by adding them and dividing by two:
43 is right in between 21 and 65, and is exactly 22 units away from each endpoint. Since we are looking for all numbers which fall outside of the the \[21, 65\] interval, we are looking for values which are further than 22 units away from 43, in both the positive and negative directions. Using absolute value, we express this as:
When you subtract 43 from any number larger than 65, the absolute value of the result will be greater than 22. Similarly, when you subtract 43 from any number less than 21, the absolute value of the result will be greater than 22.
Using the "greater than or equal to" sign is necessary in order to include the endpoints, 21 and 65, in our set of allowed ages.
We start problems like these by finding the midpoint of the two endpoints, which in this case are 21 and 65. We find the midpoint, or average, by adding them and dividing by two:
43 is right in between 21 and 65, and is exactly 22 units away from each endpoint. Since we are looking for all numbers which fall outside of the the \[21, 65\] interval, we are looking for values which are further than 22 units away from 43, in both the positive and negative directions. Using absolute value, we express this as:
When you subtract 43 from any number larger than 65, the absolute value of the result will be greater than 22. Similarly, when you subtract 43 from any number less than 21, the absolute value of the result will be greater than 22.
Using the "greater than or equal to" sign is necessary in order to include the endpoints, 21 and 65, in our set of allowed ages.
Solve for 
.
Solve for
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When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
. S
ubtract 
on both sides of all equations.
When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
ubtract
Solve for 
.
Solve for
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When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
Add 
to both sides of both equations.
When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
Add
Solve for 
.
Solve for
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When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
Multiply both sides by 
for both equations.
When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
Multiply both sides by
Solve for 
.
Solve for
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When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
Divide both sides by 
for both equations.
When solving for absolute values, remember there's an equation for positive value and another equation for negative value.
Divide both sides by
Solve:
Solve:
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To solve absolute value equations, you have to set up the equation two different ways to account for two answers.
The first is how you see it:
.
The second is by making the answer negative:
.
Next solve each one for x. The first equation yields x to be 7. The second one gives you x=-6. Those are your two answers.
To solve absolute value equations, you have to set up the equation two different ways to account for two answers.
The first is how you see it:
The second is by making the answer negative:
Next solve each one for x. The first equation yields x to be 7. The second one gives you x=-6. Those are your two answers.
Solve for 
:
Solve for
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Given
first subtract 8 from both sides to get 
on the right.
Based upon what we know about absolute value functions, it is impossible for an absolute value to be negative. So it is also impossible for an absolute value to be less than a negative number, which in this case is 
.
The only answer can be No Solution.
Given
first subtract 8 from both sides to get
Based upon what we know about absolute value functions, it is impossible for an absolute value to be negative. So it is also impossible for an absolute value to be less than a negative number, which in this case is
The only answer can be No Solution.