Extreme Value Theorem, Extrema, Critical Points Practice Test

$s$ has an absolute minimum at $x=5$.

$s$ has no extrema because $s'(x)$ is never $0$ on $(2,8)$.

$s$ has a local minimum at $x=5$, but it may not be absolute.

$s$ must be constant on $[2,8]$ since the derivative changes sign.

$s$ has an absolute maximum at $x=5$.