Run Time Exceptions
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AP Computer Science A › Run Time Exceptions
BITWISE XOR OPERATION
Given the following binary values
a = 0100 1110
b = 0011 0101
perform an XOR operation (c = a^b). What is the result?
c = 0111 1011
c = 0111 1111
c = 0111 0011
c = 0000 0100
Explanation
Performing a bitwise excludive OR constitutes in taking both binary values and evaluating as follows: either one or the other (1) never both (0). This is the truth table for a bitwise XOR operation:
Taking both a and b and performing the operation bit by bit we get the following result:
BITWISE XOR OPERATION
Given the following binary values
a = 0100 1110
b = 0011 0101
perform an XOR operation (c = a^b). What is the result?
c = 0111 1011
c = 0111 1111
c = 0111 0011
c = 0000 0100
Explanation
Performing a bitwise excludive OR constitutes in taking both binary values and evaluating as follows: either one or the other (1) never both (0). This is the truth table for a bitwise XOR operation:
Taking both a and b and performing the operation bit by bit we get the following result:
BITWISE XOR OPERATION
Given the following binary values
a = 0100 1110
b = 0011 0101
perform an XOR operation (c = a^b). What is the result?
c = 0111 1011
c = 0111 1111
c = 0111 0011
c = 0000 0100
Explanation
Performing a bitwise excludive OR constitutes in taking both binary values and evaluating as follows: either one or the other (1) never both (0). This is the truth table for a bitwise XOR operation:
Taking both a and b and performing the operation bit by bit we get the following result:
True or False.
There is a runtime exception in this code snippet.
int wait_time = 0;
int wait_time = 5;
for (int i = 0; i < wait_time; i++) {
System.out.println(wait_time);
}
True
False
Explanation
Yes, there is a runtime exception in the code snippet. The int wait_time is defined twice which will give a runtime exception. This can be fixed by not declaring int before the second assignment of the variable wait_time.
True or False.
There is a runtime exception in this code snippet.
int wait_time = 0;
int wait_time = 5;
for (int i = 0; i < wait_time; i++) {
System.out.println(wait_time);
}
True
False
Explanation
Yes, there is a runtime exception in the code snippet. The int wait_time is defined twice which will give a runtime exception. This can be fixed by not declaring int before the second assignment of the variable wait_time.
True or False.
There is a runtime exception in this code snippet.
int wait_time = 0;
int wait_time = 5;
for (int i = 0; i < wait_time; i++) {
System.out.println(wait_time);
}
True
False
Explanation
Yes, there is a runtime exception in the code snippet. The int wait_time is defined twice which will give a runtime exception. This can be fixed by not declaring int before the second assignment of the variable wait_time.