Electrostatics - AP Physics 1
Card 0 of 144
If the distance between two charged particles is doubled, the strength of the electric force between them will .
If the distance between two charged particles is doubled, the strength of the electric force between them will .
Tap to see back →
Coulomb's law gives the relationship between the force of an electric field and the distance between two charges:
The strength of the force will be inversely proportional to the square of the distance between the charges.
When the distance between the charges is doubled, the total force will be divided by four (quartered).
Coulomb's law gives the relationship between the force of an electric field and the distance between two charges:
The strength of the force will be inversely proportional to the square of the distance between the charges.
When the distance between the charges is doubled, the total force will be divided by four (quartered).
An excess charge of 
is put on an ideal neutral conducting sphere with radius 
. What is the Coulomb force this excess charge exerts on a point charge of 
that is 
from the surface of the sphere?
An excess charge of
Tap to see back →
Two principal realizations help with solving this problem, both derived from Gauss’ law for electricity:
-
The excess charge on an ideal conducting sphere is uniformly distributed over its surface
-
A uniform shell of charge acts, in terms of electric force, as if all the charge were contained in a point charge at the sphere’s center
With these realizations, an application of Coulomb’s law answers the question. If 
is the point charge outside the sphere, then the force 
on 
is:
In this equation, 
is Coulomb’s constant, 
is the excess charge on the spherical conductor, and 
is total distance in meters of 
from the center of the conducting sphere.
Using the given values in this equation, we can calculate the generated force:
Two principal realizations help with solving this problem, both derived from Gauss’ law for electricity:
-
The excess charge on an ideal conducting sphere is uniformly distributed over its surface
-
A uniform shell of charge acts, in terms of electric force, as if all the charge were contained in a point charge at the sphere’s center
With these realizations, an application of Coulomb’s law answers the question. If
In this equation,
Using the given values in this equation, we can calculate the generated force:
Charges A and B are placed a distance of 
from one another. The charge of particle A is 
whereas the charge of particle B is 
. Charge B experiences an electrostatic force of 
from charge A. Similarly, charge A experiences an electrostatic force of 
from charge B.
What is the ratio of 
to 
?
Charges A and B are placed a distance of
What is the ratio of
Tap to see back →
This question is very simple if you realize that the force experienced by both charges is equal.
The definition of the two electrostatic forces are given by Coulomb's law:
In this question, we can rewrite this equation in terms of our given system.
It doesn’t matter if the charges of the two particles are different; both particles experience the same force because the charges of both particles are accounted for in the electrostatic force equation (Coulomb's law). This conclusion can also be made by considering Newton's third law: the force of the first particle on the second will be equal and opposite the force of the second particle on the first.
Since the forces are equal, their ratio will be 
.
This question is very simple if you realize that the force experienced by both charges is equal.
The definition of the two electrostatic forces are given by Coulomb's law:
In this question, we can rewrite this equation in terms of our given system.
It doesn’t matter if the charges of the two particles are different; both particles experience the same force because the charges of both particles are accounted for in the electrostatic force equation (Coulomb's law). This conclusion can also be made by considering Newton's third law: the force of the first particle on the second will be equal and opposite the force of the second particle on the first.
Since the forces are equal, their ratio will be
Two protons are on either side of an electron as shown below:
The electron is 30 µm away from the proton on its left and 10 µm away from the proton on its right. What is the magnitude and direction of the net electric force acting on the electron?
A proton has a charge of 
Two protons are on either side of an electron as shown below:
The electron is 30 µm away from the proton on its left and 10 µm away from the proton on its right. What is the magnitude and direction of the net electric force acting on the electron?
A proton has a charge of
Tap to see back →
The net force on the electron is the sum of the forces between the electron and each of the protons:
These forces are given by Coulomb's law:
Using the numbers given, we get:
Because opposite charges attract, 
points left (the negative direction) and 
points right (the positive direction).
Therefore, the net force is
Because this value is positive, the direction is rightward.
The net force on the electron is the sum of the forces between the electron and each of the protons:
These forces are given by Coulomb's law:
Using the numbers given, we get:
Because opposite charges attract,
Therefore, the net force is
Because this value is positive, the direction is rightward.
If we have 2 charges, 
and 
, that are 
apart, what is the magnitude of the force exerted on 
by 
if we know that 
has a charge of 
and 
has a charge of 
?
If we have 2 charges,
Tap to see back →
Use Coulomb's Law
Plug in known values and solve.
A negative value for electric force indicates an attractive force. This makes sense since our two charges have opposite signs. Since we're asked for magnitude, all answer choices are positive.
Use Coulomb's Law
Plug in known values and solve.
A negative value for electric force indicates an attractive force. This makes sense since our two charges have opposite signs. Since we're asked for magnitude, all answer choices are positive.
If we have 2 charges, 
and 
, that are 
apart, what is the force exerted on 
by 
if we know that 
has a charge of 
and 
has a charge of 
?
If we have 2 charges,
Tap to see back →
Use Coulomb's law.
Plug in known values and solve.
Note that the force between two charges of the same sign (both positive or both negative) is positive. This indicates the force is repulsive, which makes sense since both charges are positive.
Use Coulomb's law.
Plug in known values and solve.
Note that the force between two charges of the same sign (both positive or both negative) is positive. This indicates the force is repulsive, which makes sense since both charges are positive.
If we have 2 charges, 
and 
, that are 
apart, what is the force exerted on 
by 
if we know that 
has a charge of 
and 
has a charge of 
?
If we have 2 charges,
Tap to see back →
Use Coulomb's law.
Plug in known values and solve.
Note that this force is positive, which means it's repulsive.
Use Coulomb's law.
Plug in known values and solve.
Note that this force is positive, which means it's repulsive.
If we have 2 charges, 
and 
, that are 
apart, what is the force exerted on 
by 
if we know that 
has a charge of 
and 
has a charge of 
?
If we have 2 charges,
Tap to see back →
Use Coulomb's law.
Plug in known values and solve.
Note that this force is positive, which means that it's repulsive.
Use Coulomb's law.
Plug in known values and solve.
Note that this force is positive, which means that it's repulsive.
Two point charges, 
and 
are separated by a distance of 
. What is the force of repulsion between them?
Two point charges,
Tap to see back →
The force of attraction/repulsion between two point charges is given by Coulomb's Law:
If the charges are of like sign, then there well be a repulsive force between the two. Alternatively, if the net force is positive, it is repulsive; if it is negative, it is attractive.
Therefore, the force of repulsion between the two charges is:
The force of attraction/repulsion between two point charges is given by Coulomb's Law:
If the charges are of like sign, then there well be a repulsive force between the two. Alternatively, if the net force is positive, it is repulsive; if it is negative, it is attractive.
Therefore, the force of repulsion between the two charges is:
Two point charges, 
and 
are separated by a distance of 
. What is the work required to move them closer together to a distance of 
?
Two point charges,
Tap to see back →
The force of attraction/repulsion between two point charges is given by Coulomb's Law:
If the charges are of like sign, then there well be a repulsive force between the two.
Work is given as the dot product of force and distance. However, in this case, force is also dependent on distance.
The amount of work required to move a charge an incremental distance, 
, is given as:
The negative sign in this case is to account for repulsion.
The total work to change distances between charges can then be found by taking the integral with respect to distance:
Since 
are constants, they can be factored out of the integral:
The force of attraction/repulsion between two point charges is given by Coulomb's Law:
If the charges are of like sign, then there well be a repulsive force between the two.
Work is given as the dot product of force and distance. However, in this case, force is also dependent on distance.
The amount of work required to move a charge an incremental distance,
The negative sign in this case is to account for repulsion.
The total work to change distances between charges can then be found by taking the integral with respect to distance:
Since
Write, in vector notation, the force exerted on a positive charge of 
by a negative charge of 
, if the two charges sitting on the 
-axis, with the positive charge sitting 
to the right of the negative charge?
Write, in vector notation, the force exerted on a positive charge of
Tap to see back →
Coulomb's law in vector notation is given as:
, where 
is Coulomb's constant, 
and 
are the two charges, 
is the distance between the charges squared, and 
is the unit vector going from one charge to another.
To write this in vector notation, we have to know the unit vector going from the negative to the positive charge, since we're trying to determine the force on the positive charge. Since they are both sitting on the 
-axis, with the negative charge to the left of the positive, the unit vector will be going in the direction of positive 
:
We know that 
We know that 
, 
, and 
. Putting this together:
We can rewrite this as:
Coulomb's law in vector notation is given as:
To write this in vector notation, we have to know the unit vector going from the negative to the positive charge, since we're trying to determine the force on the positive charge. Since they are both sitting on the
We know that
We know that
We can rewrite this as:
What are the unit(s) of Coulomb's constant 
?
What are the unit(s) of Coulomb's constant
Tap to see back →
To determine this, we have to solve for 
in Coulomb's law and then determine its constants.
Recall that the magnitude of the electrostatic force between point charges is given as:
, 
is the force given in 
, 
and 
are the charges given in 
and 
is distance given in 
Solving for 
,
Writing out the terms on the left in their units:
Therefore, 
is given in 
To determine this, we have to solve for
Recall that the magnitude of the electrostatic force between point charges is given as:
Solving for
Writing out the terms on the left in their units:
Therefore,
Two protons are at a distance 
away from each other. There is a force 
acting on each proton due to the other. If the protons are moved so that they are now at a distance
apart, what is the new force acting on each proton due to the other 
?
Two protons are at a distance
Tap to see back →
Coulomb's law shows that the force between two charged particles is inversely proportional to the square of the distance between the particles.
If the distance between the charges is reduced by 
, that means the 
is squared in the denominator and the 
will flip up to the top to give 
time the original force. More explicitly, if we plug in the given information the initial force will be:
Coulomb's law shows that the force between two charged particles is inversely proportional to the square of the distance between the particles.
If the distance between the charges is reduced by
Determine the strength of a force of proton on another proton in the nucleus if they are 
apart.
Determine the strength of a force of proton on another proton in the nucleus if they are
Tap to see back →
Use Coulomb's law:
, where 
is Coulomb's constant, 
are charges of the two points and 
is the distance between the charges.
Use Coulomb's law:
Two point charges, each having a charge of +1C, are 2 meters apart. If the distance between them is doubled, by what factor does the force between them change?
Two point charges, each having a charge of +1C, are 2 meters apart. If the distance between them is doubled, by what factor does the force between them change?
Tap to see back →
This is a question where knowing how to effectively sift through a problem statement and choose only the information you need will really help. We are given a bunch of values, but only need to know one thing, which is that the distance between the two charges is doubled.
Coulomb's law is as follows:
We can rewrite this for the initial and final scenarios:
We can divide one equation by the other to set up a ratio:
We know that the final radius is double the intial, which is written as:
Substituting this in we get:
Rerranging for the final force, we get:
This is a question where knowing how to effectively sift through a problem statement and choose only the information you need will really help. We are given a bunch of values, but only need to know one thing, which is that the distance between the two charges is doubled.
Coulomb's law is as follows:
We can rewrite this for the initial and final scenarios:
We can divide one equation by the other to set up a ratio:
We know that the final radius is double the intial, which is written as:
Substituting this in we get:
Rerranging for the final force, we get:
If 
, 
, and 
, then what is the magnitude of the net force on charge 2?
If
Tap to see back →
First lets set up two axes. Have 
be to the right of charge 3 and 2 in the diagram and 
be above charges 1 and 2 in the diagram with charge 2 at the origin.
Coloumb's law tells us the force between point charges is
The net force on charge 2 can be determined by combining the force on charge 2 due to charge 1 and the force on charge 2 due to charge 3.
Since charge 1 and charge 2 are of opposite polarities, they have an attractive force; therefore, charge 2 experiences a force towards charge 1 (in the 
direction). By using Coloumb's law, we can determine this force to be
in the 
direction
Since charge 2 and 3 have the same polarities, they have a repulsive force; therefore, charge 2 experiences a force away from charge 2 (in the 
direction). By using Coloumb's law, we can determine this force to be:
in the 
-direction
If we draw out these two forces tip to tail, we can construct the net force:
From this, we can see that 
and 
create a right triangle with the net force on charge 2 as the hypotenuse. By using the Pythagorean theorem, we can calculate the magnitude of the net force:
First lets set up two axes. Have
Coloumb's law tells us the force between point charges is
The net force on charge 2 can be determined by combining the force on charge 2 due to charge 1 and the force on charge 2 due to charge 3.
Since charge 1 and charge 2 are of opposite polarities, they have an attractive force; therefore, charge 2 experiences a force towards charge 1 (in the
Since charge 2 and 3 have the same polarities, they have a repulsive force; therefore, charge 2 experiences a force away from charge 2 (in the
If we draw out these two forces tip to tail, we can construct the net force:
From this, we can see that
What is the force exerted on a point charge of 
by a point charge of 
that is located 
away?
What is the force exerted on a point charge of
Tap to see back →
Use Coulomb's law.
Plug in known values and solve.
Note that a positive value for electric force corresponds to a repulsive force. This should make sense since the charge on both particles are the same sign (positive).
Use Coulomb's law.
Plug in known values and solve.
Note that a positive value for electric force corresponds to a repulsive force. This should make sense since the charge on both particles are the same sign (positive).
If we have 2 charges, 
and 
, that are 
apart, what is the force exerted on 
by 
if we know that 
has a charge of 
and 
has a charge of 
?
If we have 2 charges,
Tap to see back →
Use Coulomb's law.
Note that the electric force between two charges of the same sign (both positive or both negative) is a positive value. This indicates a repulsive force.
Use Coulomb's law.
Note that the electric force between two charges of the same sign (both positive or both negative) is a positive value. This indicates a repulsive force.
A point charge of magnitude 
is located 0.01m away from a point charge of magnitude 
. What is the electric force between the point charges?
A point charge of magnitude
Tap to see back →
Use Coulomb's law to find the electric force between the charges:
Use Coulomb's law to find the electric force between the charges:
A point charge of magnitude 
is 2nm away from a point charge of identical charge. What is the electric force between the point charges?
A point charge of magnitude
Tap to see back →
The electric force between two point charges is given by Coulomb's law:
Now, plug in the given charges (both the same magnitude), the given constant, and the distance between the charges (in meters) to get our answer:
The electric force between two point charges is given by Coulomb's law:
Now, plug in the given charges (both the same magnitude), the given constant, and the distance between the charges (in meters) to get our answer: