This question assesses the skill of distinguishing between scalars and vectors in one-dimensional motion. Scalars are magnitude-only, like average speed, which is total distance over time and always positive. Vectors include magnitude and direction, such as average velocity, which is displacement over time and can be negative. The core difference is that scalars do not consider direction, remaining positive, while vectors use signs for direction. One distractor, choice B, incorrectly assigns a negative sign to average speed, treating it as if it includes direction like a vector. A transferable strategy is to use displacement for vector calculations and distance for scalars to compute velocities and speeds accurately.

This question tests understanding of scalars and vectors in one dimension. Displacement is a vector showing net position change, while distance is a scalar showing total path length. Zero displacement means the puck returned to its starting position, but it could have traveled any distance to get there (forward then back). Distance traveled can be nonzero even when displacement is zero, and average speed can be positive while average velocity is zero. Choice A incorrectly assumes zero displacement means no motion occurred, confusing the vector and scalar concepts. When displacement is zero, remember that the object returned to its starting point but may have taken any path to do so, accumulating positive distance along the way.

This question tests understanding of scalars and vectors in one dimension. Acceleration is a vector quantity that represents the rate of change of velocity, including direction. The acceleration is calculated as (vf - vi)/t = (-1 - 4)/1 = -5 m/s², which is negative indicating leftward acceleration. Speed and mass are scalar quantities with only magnitude, while time is also a scalar. Among the choices, only acceleration has both magnitude and direction, making it the vector quantity. When identifying vectors versus scalars, remember that vectors have direction (can be positive or negative in 1D), while scalars only have magnitude.

This question tests understanding of scalars and vectors in one dimension. Displacement is a vector quantity showing net change in position with direction, while average velocity is displacement divided by time. Since displacement is +4 m (positive), the average velocity must also be positive because it equals positive displacement divided by positive time. Distance traveled could be 4 m or more (if the ball changed direction), and speed is always positive regardless of displacement direction. Choice D is incorrect because the ball could have moved down then up more, still yielding positive net displacement. To analyze motion with given displacement, remember that average velocity has the same sign as displacement, but the actual path taken could be more complex.

This question assesses the skill of distinguishing between scalars and vectors in one-dimensional motion. Scalars have magnitude only, such as speed, which remains positive regardless of direction changes. Vectors have both magnitude and direction, like velocity, which changes sign when direction reverses. The distinction is that scalars disregard direction, staying the same even if direction flips, while vectors reflect directional changes. One distractor, choice A, incorrectly applies a sign change to speed, treating it like a vector. A transferable strategy is to check if the quantity changes when only direction reverses; if it stays the same, it's a scalar like speed.

This question assesses the skill of distinguishing between scalars and vectors in one-dimensional motion. Scalars are magnitude-only, like distance traveled, which is positive and ignores direction. Vectors include magnitude and direction, such as displacement, calculated with signs from velocity and time. Scalars focus on absolute change, while vectors incorporate directional information. One distractor, choice C, incorrectly makes distance negative, treating it like a vector. A transferable strategy is to use the sign from velocity in displacement calculations, but take absolute value for distance.

This question tests understanding of scalars and vectors in one dimension. Scalars have only magnitude (always positive), while vectors have both magnitude and direction (can be positive or negative). With velocity v = -3 m/s for 2 s, the runner moves left (negative direction). Displacement = velocity × time = (-3 m/s)(2 s) = -6 m (a vector pointing left). Speed is the magnitude of velocity: |−3| = 3 m/s (scalar, always positive), and distance traveled = speed × time = 6 m (scalar). Choice B correctly identifies displacement as -6 m, a vector quantity. Remember that speed and distance are scalars (never negative), while velocity and displacement are vectors (use signs for direction).

This question tests understanding of scalars and vectors in one dimension. Scalars have only magnitude (always positive), while vectors have both magnitude and direction (can be positive or negative). The student walks from x = 0 to x = +5 m (displacement₁ = +5 m), then from x = +5 m to x = +2 m (displacement₂ = +2 - 5 = -3 m). Total displacement = +2 m (vector), total distance = 5 + 3 = 8 m (scalar), and average speed = 8 m/time (scalar, positive). Only the displacement during the second part is negative (-3 m). To identify negative quantities, look for vectors where motion opposes the positive direction.

This question tests understanding of scalars and vectors in one dimension. Scalars have only magnitude (always positive), while vectors have both magnitude and direction (can be positive or negative). Acceleration is a vector quantity, so a = -1 m/s² means the acceleration has magnitude 1 m/s² and points in the negative direction (left). The negative sign indicates direction, not that acceleration is "slowing down" (which depends on velocity direction too). Choice B correctly identifies acceleration as a vector pointing left with magnitude 1 m/s². When working with vector quantities, always interpret the sign as indicating direction relative to the chosen coordinate system.

This question tests understanding of scalars and vectors in one dimension. Average velocity is a vector quantity calculated as displacement divided by time, while average speed is a scalar quantity calculated as total distance divided by time. With displacement of -30 m over 10 s, the average velocity is -30 m ÷ 10 s = -3 m/s (westward). Since we don't know the exact path taken, we must assume the car traveled directly, making distance = |-30| = 30 m, and average speed = 30 m ÷ 10 s = 3 m/s. Choice D incorrectly claims average speed is zero when displacement is negative, but speed is always non-negative. Remember that average velocity includes direction (can be negative), while average speed is always positive or zero.