Increase - Basic Math

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In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

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To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

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To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

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The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

Tap to see back →

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

Tap to see back →

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

Tap to see back →

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

Tap to see back →

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

Tap to see back →

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

Tap to see back →

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

Tap to see back →

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

Tap to see back →

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

Tap to see back →

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

Tap to see back →

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

Tap to see back →

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

Tap to see back →

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

Tap to see back →

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

Increase - Basic Math

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

To find the percent change, use the following formula: Our new number of applicants is 190,201, while the original number of applicants is 150,249.

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

To find the percent increase, use the following formula: In the case of Widget Company, Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes. What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of . This can be calculated using the following equation: Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made in profit, and in June of that same year, his company made in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula: Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

To find the percent change, use the following formula: Our new number of applicants is 190,201, while the original number of applicants is 150,249.

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

To find the percent increase, use the following formula: In the case of Widget Company, Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes. What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of . This can be calculated using the following equation: Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made in profit, and in June of that same year, his company made in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula: Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

To find the percent change, use the following formula: Our new number of applicants is 190,201, while the original number of applicants is 150,249.

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

To find the percent increase, use the following formula: In the case of Widget Company, Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes. What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of . This can be calculated using the following equation: Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made in profit, and in June of that same year, his company made in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula: Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

In 2012, a university received 150,249 applicants. In 2013, the same university received 190,201 applicants. By what percent did the total number of applicants increase from 2012 to 2013?

To find the percent change, use the following formula: Our new number of applicants is 190,201, while the original number of applicants is 150,249.

In January, Widget Company made , widgets. In February, the same company made , widgets. By what percentage did the amount of widgets made increase?

To find the percent increase, use the following formula: In the case of Widget Company, Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes. What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of . This can be calculated using the following equation: Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made in profit, and in June of that same year, his company made in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula: Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$

To find the percent change, use the following formula:

$\bigg($\frac{new-original}{original}$\bigg)\times 100$

Our new number of applicants is 190,201, while the original number of applicants is 150,249.

$\bigg($\frac{190201-150249}{150249}$\bigg)\times100=26.6%$

To find the percent increase, use the following formula:

$($\frac{\text{New value-Old value}$}{$\text{Old value}$})\times 100$

In the case of Widget Company,

$($\frac{200382-180129}{180129}$)\times 100 = 11.2%$

Therefore, the percent increase is

Derek ran his first mile in minutes and his second mile in minutes.

What is the percent increase between the time it took Derek to run the first and second mile?

The correct answer is a percent change (increase) of .

This can be calculated using the following equation:

$$\frac{\text{new}$-$\text{original}$}{$\text{original}$}\cdot100 = $\frac{11-10}{10}$\cdot100 = $\frac{1}{10}$ \cdot 100 = 10$

Therefore, the answer is a percent increase of .

In May of the past year, Harry's company made $\$189,281$ in profit, and in June of that same year, his company made $\$210,219$ in profit. By what percent did his profit increase from May to June?

To find percent change, use the following formula:

$\frac{\text{New Value - Old Value}}{\text{Old Value}}\times 100$

Our new value is the profit in June, $210,219. Our old value is the profit in May, $189,281.

$\frac{210219-189281}{189281}\times100=11.06%$