Use Probability for Trait Frequency
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Biology › Use Probability for Trait Frequency
A bacterial population contains two types: antibiotic-resistant (R) and antibiotic-susceptible (S). Before treatment, most bacteria are S. During antibiotic treatment, 90% of R bacteria survive, but only 5% of S bacteria survive. After treatment, what will most likely happen to the frequency of resistance in the population that regrows?
Resistance will become more common because R bacteria have a much higher survival probability.
Resistance will become less common because antibiotics cause mutations that remove resistance.
Resistance frequency will stay the same because antibiotics only affect individuals, not populations.
Resistance frequency will change randomly with no predictable direction because survival probabilities do not matter.
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if resistant bacteria have 90% survival probability while susceptible bacteria have only 5% survival probability (HUGE probability difference), then resistant bacteria contribute disproportionately more offspring to next generation, causing resistance frequency to INCREASE dramatically and susceptibility frequency to DECREASE. Example: if 100 bacteria, 10 resistant (10%) and 90 susceptible (90%), antibiotic kills 95% of susceptible (only ~5 survive) but kills only 10% of resistant (9 survive), then next generation starts with ~5 susceptible + ~9 resistant = ~14 total, with ~64% resistant (9/14)—resistance frequency jumped from 10% to 64% in one generation! Choice A correctly predicts that resistance will become more common because R bacteria have a much higher survival probability (90% vs 5%). Choice B incorrectly claims antibiotics cause mutations that remove resistance, when actually antibiotics SELECT FOR existing resistance; C wrongly states antibiotics only affect individuals not populations, missing how differential survival changes population frequencies. Predicting frequency changes: (1) IDENTIFY survival probabilities: R bacteria: 90% survive, S bacteria: 5% survive. (2) COMPARE: R has MUCH HIGHER survival (85 percentage point difference!). (3) PREDICT: R frequency INCREASES rapidly, S frequency DECREASES rapidly. This extreme selection pressure explains why antibiotic resistance spreads so quickly in real populations!
Hardy-Weinberg equilibrium is a baseline idea that allele frequencies stay the same when no evolutionary forces act. A mouse population had stable fur-color allele frequencies for many generations. Then a new predator arrives and mice with dark fur have a 70% chance to survive to reproduce, while mice with light fur have a 30% chance. What is the most likely outcome over the next several generations?
Individuals will change from light to dark fur during their lifetime to avoid predation
The dark-fur allele will increase in frequency because dark mice survive and reproduce more often
The light-fur allele will increase in frequency because predators remove dark mice more easily
Allele frequencies will remain constant because Hardy-Weinberg predicts no change
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this mouse population, the new predator creates differential survival: dark-fur mice have 70% survival probability while light-fur mice have only 30% survival probability—this 40 percentage point difference means dark mice contribute more than twice as many offspring to the next generation, causing dark-fur allele frequency to increase over time. Choice B correctly predicts that the dark-fur allele will increase in frequency because dark mice survive and reproduce more often under the new predation pressure. Choice A incorrectly invokes Hardy-Weinberg (which assumes NO selection), C gets the direction backwards (dark mice survive better, not worse), and D misunderstands evolution (individuals don't change their genes during their lifetime—populations evolve through differential survival/reproduction). Predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities: Dark fur: 70% survive to reproduce. Light fur: 30% survive to reproduce. (2) COMPARE probabilities: Dark fur mice have 2.3× higher survival (70% vs 30%). (3) PREDICT direction: Higher probability variant (dark fur) → frequency INCREASES. Lower probability variant (light fur) → frequency DECREASES. (4) ASSESS magnitude: LARGE probability difference (40 percentage points) → RAPID frequency change (strong selection). This violates Hardy-Weinberg equilibrium because we now have differential survival (selection), one of the key forces that causes evolution! Real-world example: the famous peppered moths in England—when industrial pollution darkened tree bark, dark moths had higher survival than light moths (better camouflage), so dark allele frequency increased rapidly from rare to common in just decades!
A rabbit population has two coat colors: white and brown. In a snowy habitat, white rabbits have a 75% chance of surviving to reproduce, while brown rabbits have a 25% chance. If the habitat stays snowy, which outcome is most likely after many generations?
White coat color becomes more common because white rabbits are more likely to survive and reproduce
Brown coat color becomes more common because it is currently less common
Coat color frequencies do not change because survival is not related to reproduction
Individual brown rabbits will turn white during winter, increasing white frequency without selection
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this snowy habitat, white rabbits have 75% survival probability while brown rabbits have only 25% survival probability—this 50 percentage point difference means white rabbits contribute three times as many offspring to future generations, causing white coat color frequency to increase over time. Choice C correctly predicts that white coat color becomes more common because white rabbits are more likely to survive and reproduce in the snowy environment. Choice A incorrectly assumes rare traits increase (selection favors beneficial traits regardless of current frequency), B wrongly claims survival doesn't affect reproduction (survivors are the ones who reproduce!), and D misunderstands evolution (individuals can't change their genes—populations evolve through differential survival). Predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities: White coat: 75% survive to reproduce. Brown coat: 25% survive to reproduce. (2) COMPARE probabilities: White rabbits have 3× higher survival (75% vs 25%). (3) PREDICT direction: Higher probability variant (white) → frequency INCREASES. Lower probability variant (brown) → frequency DECREASES. (4) ASSESS magnitude: LARGE probability difference (50 percentage points) → RAPID frequency change. Real-world example: snowshoe hares change from brown in summer to white in winter, but with climate change reducing snow cover, brown hares now survive better during shorter winters, causing evolutionary change in molt timing—probability of survival drives evolution!
In a population of beetles, color is controlled by one gene with two alleles: $G$ and $g$. After a drought, survival probabilities differ by genotype: $GG$: 80% survive, $Gg$: 70% survive, $gg$: 20% survive. Assuming survivors reproduce, which allele is expected to increase in frequency in the next generation?
Allele $G$ increases because genotypes with $G$ have higher survival probabilities
Neither allele changes because survival only affects individuals, not populations
Allele $g$ increases because recessive alleles are favored under stress
Both alleles increase in frequency because more beetles survive overall
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates predictable changes in allele frequencies: if individuals with allele G have higher survival probabilities (GG: 80%, Gg: 70%) while individuals with gg have 20% survival (large probability difference), then G-carrying individuals contribute disproportionately more offspring to the next generation, causing G allele frequency to increase and g allele frequency to decrease. The direction of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the rate depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). For this beetle population, the survival probabilities show that genotypes with at least one G allele (GG and Gg) have much higher chances of surviving the drought (80% and 70%) compared to gg (20%), so more G alleles will be passed on, leading to an increase in G frequency over generations. Choice B correctly predicts that allele G increases because genotypes with G have higher survival probabilities, accurately connecting the probability differences to frequency shifts. Choice A fails by incorrectly assuming recessive alleles are favored under stress, ignoring that selection here favors the dominant allele due to survival advantages. Predicting frequency changes from probabilities: (1) Identify survival probabilities for each genotype: GG: 80%, Gg: 70%, gg: 20%. (2) Compare probabilities: Genotypes with G have higher survival. (3) Predict direction: G frequency increases, g decreases. (4) Assess magnitude: Large difference (80-70% vs 20%) means rapid change. Real-world example: like peppered moths during industrialization, where darker moths had higher survival probabilities in polluted areas, leading to rapid increase in dark allele frequency!
In a population of beetles, color is controlled by two alleles: $G$ (green) and $g$ (brown). After a drought, survival probabilities differ by genotype: $GG$ = 90% survive, $Gg$ = 70% survive, $gg$ = 20% survive. Assuming survivors are the ones that reproduce, which allele’s frequency is expected to increase in the next generation?
Allele $G$ will increase because genotypes with $G$ have higher survival probabilities.
Allele $g$ will increase because rare alleles always increase after selection.
Both alleles will increase because more beetles survive overall.
Neither allele will change because survival affects individuals, not populations.
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this beetle population, the survival probabilities show that genotypes with more G alleles (GG at 90%, Gg at 70%) have higher chances of surviving the drought compared to gg at 20%, so G-carrying individuals are more likely to reproduce and pass on the G allele, leading to an increase in its frequency. Choice B correctly predicts that allele G will increase by recognizing that higher survival probabilities for G-containing genotypes lead to increasing frequencies of G. Choice A fails by incorrectly assuming rare alleles always increase, but actually, selection favors alleles linked to higher survival regardless of rarity, so here G increases even if it wasn't rare. Keep up the great work—remember this strategy for predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities for each genotype: GG 90%, Gg 70%, gg 20%; (2) COMPARE which allele is associated with HIGHER survival (G in GG and Gg); (3) PREDICT direction: G frequency INCREASES, g DECREASES; (4) ASSESS magnitude: large differences (90% vs 20%) mean rapid change, just like in antibiotic resistance where huge survival gaps cause fast evolution!
In a flowering plant, allele $P$ produces purple flowers and allele $p$ produces white flowers. Pollinators visit purple flowers more often, so plants with at least one $P$ allele produce more seeds. Seed production (average offspring) is: $PP$: 40 seeds, $Pp$: 40 seeds, $pp$: 10 seeds. Over time, what is the most likely outcome for allele frequencies?
Allele $P$ will increase because genotypes with $P$ contribute more offspring to the next generation.
Allele $P$ will decrease because selection always favors recessive alleles.
Allele frequencies will not change because reproduction differences do not affect evolution.
Allele $p$ will increase because white flowers produce fewer seeds and therefore face less competition.
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if plants with allele P produce 40 seeds (both PP and Pp) while pp plants produce only 10 seeds, then P-carrying plants contribute disproportionately more offspring to next generation, causing P allele frequency to INCREASE and p allele frequency to DECREASE. The mechanism here is differential reproduction rather than survival, but the probability logic is identical—higher reproductive output means more genetic contribution to future generations. Choice C correctly predicts that allele P will increase because genotypes with P contribute more offspring (40 seeds vs 10 seeds) to the next generation. Choice A incorrectly reasons that producing fewer seeds means less competition (missing that fewer seeds means fewer genetic contributions); B wrongly claims reproduction differences don't affect evolution when they're a primary driver; D falsely states selection favors recessive alleles when selection actually favors traits that increase fitness regardless of dominance. Predicting frequency changes from reproduction: (1) IDENTIFY reproductive output: PP: 40 seeds, Pp: 40 seeds, pp: 10 seeds. (2) COMPARE: P-containing plants produce 4× more offspring! (3) PREDICT: P frequency INCREASES, p frequency DECREASES. (4) ASSESS magnitude: 4-fold reproduction difference = STRONG selection, expect rapid frequency change. This pollinator-mediated selection is common in flowering plants!
A bird population has two beak types: thick (T) and thin (t). Thick-beaked birds produce an average of 4 offspring that survive to adulthood, while thin-beaked birds produce an average of 2 such offspring. If these differences continue, what will happen to the frequency of the thick-beak trait over generations?
It will decrease because producing more offspring reduces survival of the trait
It will change randomly because reproduction differences do not create predictable patterns
It will increase because thick-beaked birds contribute more offspring to the next generation
It will stay the same because traits do not affect evolution, only allele frequencies do
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this bird population, thick-beaked birds produce 4 surviving offspring while thin-beaked birds produce only 2—this 2× reproduction advantage means thick-beaked birds contribute twice as many individuals to the next generation, causing thick-beak trait frequency to increase over time. Choice B correctly predicts that thick-beak frequency will increase because thick-beaked birds contribute more offspring to the next generation through higher reproductive success. Choice A incorrectly suggests the trait decreases (opposite of what happens with higher reproduction), C wrongly claims traits don't affect evolution (they do through differential reproduction!), and D incorrectly states changes are random when reproduction differences create predictable patterns. Predicting frequency changes from probabilities: (1) IDENTIFY reproduction differences: Thick beak: 4 offspring survive. Thin beak: 2 offspring survive. (2) COMPARE reproductive success: Thick-beaked birds have 2× higher reproductive output (4 vs 2). (3) PREDICT direction: Higher reproduction variant (thick beak) → frequency INCREASES. Lower reproduction variant (thin beak) → frequency DECREASES. (4) ASSESS magnitude: 2× difference in offspring = strong selection → relatively rapid change. Example: if generation starts 50:50, and each thick-beak produces 4 offspring while each thin-beak produces 2, next generation has ~67% thick-beak (4/(4+2)) and ~33% thin-beak! Real-world example: Darwin's finches during drought—birds with beaks matching available seeds produced more surviving offspring, rapidly shifting beak size frequencies in the population!
A population of insects has genotypes $BB$, $Bb$, and $bb$ for a gene affecting toxin resistance. In an environment with the toxin, survival probabilities are: $BB$: 85%, $Bb$: 40%, $bb$: 10%. Which statement best predicts what happens to allele $B$?
Allele $B$ stays the same because selection affects individuals, not allele frequencies
Allele $B$ increases because genotypes with $B$ (especially $BB$) survive much more often than $bb$
Allele $B$ increases only if the toxin causes new mutations to create more $B$ alleles
Allele $B$ decreases because $Bb$ has lower survival than $BB$
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). In this insect population exposed to toxin, survival probabilities are BB: 85%, Bb: 40%, bb: 10%—while Bb has intermediate survival, BB has much higher survival than both other genotypes, and overall, B-containing genotypes survive better than bb, so B allele frequency will increase over time. Choice B correctly predicts that allele B increases because genotypes with B (especially BB at 85%) survive much more often than bb (only 10%), even though Bb is intermediate. Choice A incorrectly focuses only on Bb being lower than BB (missing that both are higher than bb), C wrongly claims selection doesn't affect allele frequencies, and D incorrectly requires new mutations rather than selection on existing variation. Predicting frequency changes from probabilities: (1) IDENTIFY survival probabilities: BB: 85%, Bb: 40%, bb: 10%. (2) ANALYZE allele representation: B appears in BB (85% survival) and Bb (40% survival). b appears in Bb (40% survival) and bb (10% survival). (3) CALCULATE weighted average: B allele "sees" average survival of ~62.5% (averaging BB and Bb). b allele "sees" average survival of ~25% (averaging Bb and bb). (4) PREDICT: B has higher average survival → B frequency INCREASES. This shows even with heterozygote disadvantage (Bb lower than both homozygotes), B still increases because BB survival is so high! Real-world example: sickle cell and malaria—even though sickle cell heterozygotes have some health issues, the allele persists in malaria regions because homozygotes for normal hemoglobin die from malaria at high rates!
Two populations of the same species experience different levels of selection for a camouflage trait. In Population 1, camouflaged individuals survive at 55% and non-camouflaged at 50%. In Population 2, camouflaged survive at 95% and non-camouflaged at 20%. Which statement best compares how quickly the camouflage trait frequency will change?
It will change at the same rate in both populations because selection always works at the same speed
It will change faster in Population 1 because survival is closer to 50%, which increases randomness
It will not change in either population because survival probabilities do not affect trait frequencies
It will change faster in Population 2 because the survival probability difference is much larger (stronger selection)
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). Comparing the two populations: Population 1 has only a 5 percentage point survival difference (55% vs 50%), while Population 2 has a massive 75 percentage point difference (95% vs 20%)—this means Population 2 experiences MUCH stronger selection and will show rapid frequency changes, while Population 1's weak selection produces very slow changes. Choice B correctly predicts that camouflage frequency will change faster in Population 2 because the survival probability difference is much larger, indicating stronger selection. Choice A incorrectly relates speed to being near 50% (that affects drift, not selection strength), C wrongly claims selection always works at the same speed, and D incorrectly states survival probabilities don't affect trait frequencies. Predicting frequency changes from probabilities: (1) IDENTIFY survival differences: Population 1: 55% - 50% = 5 percentage points (weak selection). Population 2: 95% - 20% = 75 percentage points (strong selection). (2) COMPARE selection strength: 75-point difference is 15× larger than 5-point difference! (3) PREDICT rate: Population 1: VERY SLOW change (many generations for noticeable shift). Population 2: RAPID change (big shifts in few generations). (4) The probability difference determines evolutionary speed! Real-world example: pesticide resistance in insects—if Pesticide A kills 52% of susceptible insects but 48% of resistant ones (4-point difference), resistance evolves slowly. If Pesticide B kills 99% of susceptible but 10% of resistant (89-point difference), resistance evolves extremely fast, making the pesticide useless within a few seasons!
Two genotypes of a plant differ in drought survival. In a dry year, genotype $AA$ has a 92% survival probability and genotype $aa$ has an 88% survival probability. Compared with a situation where $AA$ survives at 92% and $aa$ survives at 12%, which statement best describes how fast allele frequencies will change in the dry year?
Allele frequencies will change at the same rate in both situations because selection is always equally strong
Allele frequencies will change faster in the dry year because both genotypes have high survival
Allele frequencies will not change at all in the dry year because any difference under 10% cannot cause evolution
Allele frequencies will change more slowly in the dry year because the survival difference (92% vs 88%) is small (weak selection)
Explanation
This question tests your ability to use probability and differential survival/reproduction data to predict how trait and allele frequencies change in populations over time through natural selection. Probability reasoning for evolution: when different variants have different survival or reproduction probabilities, this creates PREDICTABLE changes in allele frequencies: if individuals with allele A have 90% survival probability while individuals with allele a have 30% survival probability (large probability difference), then A individuals contribute disproportionately more offspring to next generation, causing A allele frequency to INCREASE and a allele frequency to DECREASE. The DIRECTION of change is predictable (higher survival/reproduction → increase frequency, lower survival/reproduction → decrease frequency), and the RATE depends on probability differences (larger differences = stronger selection = faster change, smaller differences = weaker selection = slower change). This question compares two selection scenarios: in the dry year, AA survives at 92% and aa at 88% (only 4 percentage point difference), while the comparison scenario has AA at 92% and aa at 12% (80 percentage point difference)—the tiny 4-point difference in the dry year means WEAK selection and SLOW frequency change, while the huge 80-point difference means STRONG selection and RAPID change. Choice C correctly recognizes that allele frequencies will change more slowly in the dry year because the survival difference (92% vs 88%) is small, indicating weak selection. Choice A gets it backwards (small differences = slow change, not fast), B incorrectly claims selection is always equally strong, and D wrongly suggests no evolution occurs with small differences (evolution still happens, just slowly). Predicting frequency changes from probabilities: (1) IDENTIFY survival differences: Dry year: 92% - 88% = 4 percentage points. Comparison: 92% - 12% = 80 percentage points. (2) COMPARE selection strength: 4-point difference = WEAK selection. 80-point difference = STRONG selection. (3) PREDICT rate: Weak selection → SLOW frequency change (many generations for noticeable change). Strong selection → RAPID frequency change (big changes in few generations). (4) Both cause evolution, but at very different speeds! Real-world example: antibiotic resistance with different drugs—if Drug A kills 99% of susceptible bacteria but 1% of resistant (98-point difference), resistance evolves FAST. If Drug B kills 55% of susceptible but 50% of resistant (5-point difference), resistance still evolves but MUCH more slowly!