Place Value: CCSS.Math.Content.K.NBT.A.1

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Common Core: Kindergarten Math › Place Value: CCSS.Math.Content.K.NBT.A.1

Questions 1 - 10

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}14\ -\ 10\end{array}}{ \ \ \ \ \ \space 4}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}15\ -\ 10\end{array}}{ \ \ \ \ \ \space 5}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}13\ -\ 10\end{array}}{ \ \ \ \ \ \space 3}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}19\ -\ 10\end{array}}{ \ \ \ \ \ \space 9}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}13\ -\ 10\end{array}}{ \ \ \ \ \ \space 3}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}18\ -\ 10\end{array}}{ \ \ \ \ \ \space 8}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}17\ -\ 10\end{array}}{ \ \ \ \ \ \space 7}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}12\ -\ 10\end{array}}{ \ \ \ \ \ \space 2}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}11\ -\ 10\end{array}}{ \ \ \ \ \ \space 1}$

We can start at and count back .

Explanation

To find the missing piece of an addition problem, we can take the biggest number minus the smallest number.

$\frac{\begin{array}[b]{r}11\ -\ 10\end{array}}{ \ \ \ \ \ \space 1}$

We can start at and count back .

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