Solid Geometry - GRE Quantitative Reasoning
Card 0 of 360
If the dimensions of a rectangular crate are
, which of the following CANNOT be the total surface area of two sides of the crate?
If the dimensions of a rectangular crate are , which of the following CANNOT be the total surface area of two sides of the crate?
Side 1: surface area of the 6 x 7 side is 42
Side 2: surface area of the 7 x 8 side is 56
Side 3: surface area of the 6 x 8 side is 48.
We can add sides 1 and 3 to get 90, so that's not the answer.
We can add sides 1 and 1 to get 84, so that's not the answer.
We can add sides 2 and 3 to get 104, so that's not the answer.
We can add sides 2 and 2 to get 112, so that's not the answer.
This leaves the answer of 92. Any combination of the three sides of the rectangular prism will not give us 92 as the total surface area.
Side 1: surface area of the 6 x 7 side is 42
Side 2: surface area of the 7 x 8 side is 56
Side 3: surface area of the 6 x 8 side is 48.
We can add sides 1 and 3 to get 90, so that's not the answer.
We can add sides 1 and 1 to get 84, so that's not the answer.
We can add sides 2 and 3 to get 104, so that's not the answer.
We can add sides 2 and 2 to get 112, so that's not the answer.
This leaves the answer of 92. Any combination of the three sides of the rectangular prism will not give us 92 as the total surface area.
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Kate wants to paint a cylinder prism.
What is the surface area of her prism if it is
inches tall and has a diameter of
inches? Round to the nearest whole number.
Kate wants to paint a cylinder prism.
What is the surface area of her prism if it is inches tall and has a diameter of
inches? Round to the nearest whole number.
First, find the area of the base of the cyclinder:
and multiply that by two, since there are two sides with this measurement:
.
Then, you find the width of the rectangular portion (label portion) of the prism by finding the circumference of the cylinder:
. This is then multiplied by the height of the cylinder to find the area of the rectanuglar portion of the cylinder:
.
Finally, add all sides together and round:
.
First, find the area of the base of the cyclinder:
and multiply that by two, since there are two sides with this measurement:
.
Then, you find the width of the rectangular portion (label portion) of the prism by finding the circumference of the cylinder:
. This is then multiplied by the height of the cylinder to find the area of the rectanuglar portion of the cylinder:
.
Finally, add all sides together and round: .
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This triangular prism has a height of
feet and a length of
feet.
What is the surface area of the prism? Round to the nearest tenth.
This triangular prism has a height of
feet and a length of
feet.
What is the surface area of the prism? Round to the nearest tenth.
Find the area of the triangular sides first:

Since there are two sides of this area, we multiply the area by 2:

Next find the area of the rectangular regions. Two of them have the width of 3 feet and a length of 7 feet, while the last one has a width measurement of
feet and a length of 7 feet. Multiply and add all other sides:
.
Lastly, add the triangular sides to the rectangular sides and round:
.
Find the area of the triangular sides first:
Since there are two sides of this area, we multiply the area by 2:
Next find the area of the rectangular regions. Two of them have the width of 3 feet and a length of 7 feet, while the last one has a width measurement of feet and a length of 7 feet. Multiply and add all other sides:
.
Lastly, add the triangular sides to the rectangular sides and round:
.
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What is the volume of a rectangular box that is twice as long as it is high, and four times as wide as it is long?
What is the volume of a rectangular box that is twice as long as it is high, and four times as wide as it is long?
The box is 2 times as long as it is high, so H = L/2. It is also 4 times as wide as it is long, so W = 4_L_. Now we need volume = L * W * H = L * 4_L_ * L/2 = 2_L_3.
The box is 2 times as long as it is high, so H = L/2. It is also 4 times as wide as it is long, so W = 4_L_. Now we need volume = L * W * H = L * 4_L_ * L/2 = 2_L_3.
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What is the volume of a cube with a surface area of
?
What is the volume of a cube with a surface area of
?
The surface area of a cube is merely the sum of the surface areas of the
squares that make up its faces. Therefore, the surface area equation understandably is:
, where
is the side length of any one side of the cube. For our values, we know:

Solving for
, we get:
or 
Now, the volume of a cube is defined by the simple equation:

For
, this is:

The surface area of a cube is merely the sum of the surface areas of the squares that make up its faces. Therefore, the surface area equation understandably is:
, where
is the side length of any one side of the cube. For our values, we know:
Solving for , we get:
or
Now, the volume of a cube is defined by the simple equation:
For , this is:
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The volume of a cube is
. If the side length of this cube is tripled, what is the new volume?
The volume of a cube is . If the side length of this cube is tripled, what is the new volume?
Recall that the volume of a cube is defined by the equation:
, where
is the side length of the cube.
Therefore, if we know that
, we can solve:

This means that
.
Now, if we triple
to
, the new volume of our cube will be:

Recall that the volume of a cube is defined by the equation:
, where
is the side length of the cube.
Therefore, if we know that , we can solve:
This means that .
Now, if we triple to
, the new volume of our cube will be:
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What is the volume of a cube with surface area of
?
What is the volume of a cube with surface area of ?
Recall that the equation for the surface area of a cube is merely derived from the fact that the cube's faces are made up of
squares. It is therefore:

For our values, this is:

Solving for
, we get:
, so 
Now, the volume of a cube is merely:

Therefore, for
, this value is:

Recall that the equation for the surface area of a cube is merely derived from the fact that the cube's faces are made up of squares. It is therefore:
For our values, this is:
Solving for , we get:
, so
Now, the volume of a cube is merely:
Therefore, for , this value is:
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A cube has a volume of 64, what would it be if you doubled its side lengths?
A cube has a volume of 64, what would it be if you doubled its side lengths?
To find the volume of a cube, you multiple your side length 3 times (s*s*s).
To find the side length from the volume, you find the cube root which gives you 4
.
Doubling the side gives you 8
.
The volume of the new cube would then be 512
.
To find the volume of a cube, you multiple your side length 3 times (s*s*s).
To find the side length from the volume, you find the cube root which gives you 4
.
Doubling the side gives you 8
.
The volume of the new cube would then be 512
.
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What is the radius of a sphere with volume
cubed units?
What is the radius of a sphere with volume cubed units?
The volume of a sphere is represented by the equation
. Set this equation equal to the volume given and solve for r:





Therefore, the radius of the sphere is 3.
The volume of a sphere is represented by the equation . Set this equation equal to the volume given and solve for r:
Therefore, the radius of the sphere is 3.
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If a sphere has a volume of
cubic inches, what is the approximate radius of the sphere?
If a sphere has a volume of cubic inches, what is the approximate radius of the sphere?
The formula for the volume of a sphere is
where
is the radius of the sphere.
Therefore,
![r=\sqrt[3]{\frac{3v}{(4\pi)}}](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/345687/gif.latex)
, giving us
.
The formula for the volume of a sphere is
where
is the radius of the sphere.
Therefore,
, giving us
.
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A rectangular prism has the dimensions
. What is the volume of the largest possible sphere that could fit within this solid?
A rectangular prism has the dimensions . What is the volume of the largest possible sphere that could fit within this solid?
For a sphere to fit into the rectangular prism, its dimensions are constrained by the prism's smallest side, which forms its diameter. Therefore, the largest sphere will have a diameter of
, and a radius of
.
The volume of a sphere is given as:

And thus the volume of the largest possible sphere to fit into this prism is

For a sphere to fit into the rectangular prism, its dimensions are constrained by the prism's smallest side, which forms its diameter. Therefore, the largest sphere will have a diameter of , and a radius of
.
The volume of a sphere is given as:
And thus the volume of the largest possible sphere to fit into this prism is
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What is the surface area of a cylinder with a radius of 6 and a height of 9?
What is the surface area of a cylinder with a radius of 6 and a height of 9?
surface area of a cylinder
= 2_πr_2 + 2_πrh_
= 2_π_ * 62 + 2_π_ * 6 *9
= 180_π_
surface area of a cylinder
= 2_πr_2 + 2_πrh_
= 2_π_ * 62 + 2_π_ * 6 *9
= 180_π_
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Quantitative Comparison
Quantity A: The volume of a cylinder with a radius of 3 and a height of 4
Quantity B: 3 times the volume of a cone with a radius of 3 and a height of 4
Quantitative Comparison
Quantity A: The volume of a cylinder with a radius of 3 and a height of 4
Quantity B: 3 times the volume of a cone with a radius of 3 and a height of 4
There is no need to do the actual computations here to find the two volumes. The volume of a cone is exactly 1/3 the volume of a cylinder with the same height and radius. That means the two quantities are equal. The formulas show this relationship as well: volume of a cone = πr_2_h/3 and volume of a cylinder = πr_2_h.
There is no need to do the actual computations here to find the two volumes. The volume of a cone is exactly 1/3 the volume of a cylinder with the same height and radius. That means the two quantities are equal. The formulas show this relationship as well: volume of a cone = πr_2_h/3 and volume of a cylinder = πr_2_h.
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The area of the base of a circular right cylinder is quadrupled. By what percentage is the outer face increased by this change?
The area of the base of a circular right cylinder is quadrupled. By what percentage is the outer face increased by this change?
The base of the original cylinder would have been πr2, and the outer face would have been 2πrh, where h is the height of the cylinder.
Let's represent the original area with A, the original radius with r, and the new radius with R: therefore, we know πR2 = 4A, or πR2 = 4πr2. Solving for R, we get R = 2r; therefore, the new outer face of the cylinder will have an area of 2πRh or 2π2rh or 4πrh, which is double the original face area; thus the percentage of increase is 100%. (Don't be tricked into thinking it is 200%. That is not the percentage of increase.)
The base of the original cylinder would have been πr2, and the outer face would have been 2πrh, where h is the height of the cylinder.
Let's represent the original area with A, the original radius with r, and the new radius with R: therefore, we know πR2 = 4A, or πR2 = 4πr2. Solving for R, we get R = 2r; therefore, the new outer face of the cylinder will have an area of 2πRh or 2π2rh or 4πrh, which is double the original face area; thus the percentage of increase is 100%. (Don't be tricked into thinking it is 200%. That is not the percentage of increase.)
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A cylinder has a radius of 4 and a height of 8. What is its surface area?
A cylinder has a radius of 4 and a height of 8. What is its surface area?
This problem is simple if we remember the surface area formula!

This problem is simple if we remember the surface area formula!
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What is the surface area of a cylinder with a radius of 17 and a height of 3?
What is the surface area of a cylinder with a radius of 17 and a height of 3?
We need the formula for the surface area of a cylinder: SA = 2_πr_2 + 2_πrh_. This formula has π in it, but the answer choices don't. This means we must approximate π. None of the answers are too close to each other so we could really even use 3 here, but it is safest to use 3.14 as an approximate value of π.
Then SA = 2 * 3.14 * 172 + 2 * 3.14 * 17 * 3 ≈ 2137
We need the formula for the surface area of a cylinder: SA = 2_πr_2 + 2_πrh_. This formula has π in it, but the answer choices don't. This means we must approximate π. None of the answers are too close to each other so we could really even use 3 here, but it is safest to use 3.14 as an approximate value of π.
Then SA = 2 * 3.14 * 172 + 2 * 3.14 * 17 * 3 ≈ 2137
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Quantitative Comparison
Quantity A: Surface area of a cylinder that is 2 feet high and has a radius of 4 feet
Quantity B: Surface area of a box that is 3 feet wide, 2 feet high, and 4 feet long
Quantitative Comparison
Quantity A: Surface area of a cylinder that is 2 feet high and has a radius of 4 feet
Quantity B: Surface area of a box that is 3 feet wide, 2 feet high, and 4 feet long
Quantity A: SA of a cylinder = 2_πr_2 + 2_πrh_ = 2_π *_ 16 + 2_π_ * 4 * 2 = 48_π_
Quantity B: SA of a rectangular solid = 2_ab_ + 2_bc_ + 2_ac_ = 2 * 3 * 2 + 2 * 2 * 4 + 2 * 3 * 4 = 52
48_π_ is much larger than 52, because π is approximately 3.14.
Quantity A: SA of a cylinder = 2_πr_2 + 2_πrh_ = 2_π *_ 16 + 2_π_ * 4 * 2 = 48_π_
Quantity B: SA of a rectangular solid = 2_ab_ + 2_bc_ + 2_ac_ = 2 * 3 * 2 + 2 * 2 * 4 + 2 * 3 * 4 = 52
48_π_ is much larger than 52, because π is approximately 3.14.
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What is the surface area of a cylinder that has a diameter of 6 inches and is 4 inches tall?
What is the surface area of a cylinder that has a diameter of 6 inches and is 4 inches tall?
The formula for the surface area of a cylinder is
,
where
is the radius and
is the height.


The formula for the surface area of a cylinder is ,
where is the radius and
is the height.
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A right circular cylinder of volume
has a height of 8.
Quantity A: 10
Quantity B: The circumference of the base
A right circular cylinder of volume has a height of 8.
Quantity A: 10
Quantity B: The circumference of the base
The volume of any solid figure is
. In this case, the volume of the cylinder is
and its height is
, which means that the area of its base must be
. Working backwards, you can figure out that the radius of a circle of area
is
. The circumference of a circle with a radius of
is
, which is greater than
.
The volume of any solid figure is . In this case, the volume of the cylinder is
and its height is
, which means that the area of its base must be
. Working backwards, you can figure out that the radius of a circle of area
is
. The circumference of a circle with a radius of
is
, which is greater than
.
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A cylinder has a height of 4 and a circumference of 16π. What is its volume
A cylinder has a height of 4 and a circumference of 16π. What is its volume
circumference = πd
d = 2r
volume of cylinder = πr2h
r = 8, h = 4
volume = 256π
circumference = πd
d = 2r
volume of cylinder = πr2h
r = 8, h = 4
volume = 256π
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