Midpoint of line segments - HiSET

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Give the coordinates of the midpoint of the line segment whose endpoints are the intercepts of the line of the equation

.

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The x-intercept and y-intercept of the line of an equation can be found by substituting 0 for and , respectively, as follows:

x-intercept:

Substitute and simplify:

Solve for by dividing by 2 on both sides:

$2x \div 2 = 40 \div 2$

The x-intercept of the line is located at

The y-intercept can be found by setting and solving for in a similar fashion:

$5y \div 5 = 40 \div 5$

The y-intercept is located at .

The midpoint of a line segment, given its endpoints and , is located at

$\left ( $$\frac{x_{1}$$$+x_{2}$}{2}, $$\frac{y_{1}$$$+y_{2}$}{2} \right )$ ;

substituting accordingly,

The midpoint is located at .

What is the midpoint of the line segment created by the points and ?

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The midpoint of the line segment between two points

and

is given by the formula

.

Thus, since the line segment is generated by

and

applying the midpoint formula we have

$($\frac{-2+3}{2}$,$\frac{16+7}{2}$)= ($\frac{1}{2}$,$\frac{23}{2}$)$

as the midpoint.

What is the midpoint between and ?

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Step 1: Recall the midpoint Formula....

$(\dfrac {x_1+x_2}{2},\dfrac {y_1+y_2}{2})$ , where is the first point and is the second point

Step 2: Identify the points and their specific terms...

Step 3: Plug in the values into the midpoint formula...

$(\dfrac {-12+14}{2},\dfrac {10-6}{2})$

Simplify...

$(\dfrac {2}{2},\dfrac {4}{2})=(1,2)$

Give the coordinates of the midpoint of the line segment whose endpoints are the intercepts of the line of the equation

.

Tap to see back →

The x-intercept and y-intercept of the line of an equation can be found by substituting 0 for and , respectively, as follows:

x-intercept:

Substitute and simplify:

Solve for by dividing by 2 on both sides:

$2x \div 2 = 40 \div 2$

The x-intercept of the line is located at

The y-intercept can be found by setting and solving for in a similar fashion:

$5y \div 5 = 40 \div 5$

The y-intercept is located at .

The midpoint of a line segment, given its endpoints and , is located at

$\left ( $$\frac{x_{1}$$$+x_{2}$}{2}, $$\frac{y_{1}$$$+y_{2}$}{2} \right )$ ;

substituting accordingly,

The midpoint is located at .

What is the midpoint of the line segment created by the points and ?

Tap to see back →

The midpoint of the line segment between two points

and

is given by the formula

.

Thus, since the line segment is generated by

and

applying the midpoint formula we have

$($\frac{-2+3}{2}$,$\frac{16+7}{2}$)= ($\frac{1}{2}$,$\frac{23}{2}$)$

as the midpoint.

What is the midpoint between and ?

Tap to see back →

Step 1: Recall the midpoint Formula....

$(\dfrac {x_1+x_2}{2},\dfrac {y_1+y_2}{2})$ , where is the first point and is the second point

Step 2: Identify the points and their specific terms...

Step 3: Plug in the values into the midpoint formula...

$(\dfrac {-12+14}{2},\dfrac {10-6}{2})$

Simplify...

$(\dfrac {2}{2},\dfrac {4}{2})=(1,2)$

Give the coordinates of the midpoint of the line segment whose endpoints are the intercepts of the line of the equation

.

Tap to see back →

The x-intercept and y-intercept of the line of an equation can be found by substituting 0 for and , respectively, as follows:

x-intercept:

Substitute and simplify:

Solve for by dividing by 2 on both sides:

$2x \div 2 = 40 \div 2$

The x-intercept of the line is located at

The y-intercept can be found by setting and solving for in a similar fashion:

$5y \div 5 = 40 \div 5$

The y-intercept is located at .

The midpoint of a line segment, given its endpoints and , is located at

$\left ( $$\frac{x_{1}$$$+x_{2}$}{2}, $$\frac{y_{1}$$$+y_{2}$}{2} \right )$ ;

substituting accordingly,

The midpoint is located at .

What is the midpoint of the line segment created by the points and ?

Tap to see back →

The midpoint of the line segment between two points

and

is given by the formula

.

Thus, since the line segment is generated by

and

applying the midpoint formula we have

$($\frac{-2+3}{2}$,$\frac{16+7}{2}$)= ($\frac{1}{2}$,$\frac{23}{2}$)$

as the midpoint.

What is the midpoint between and ?

Tap to see back →

Step 1: Recall the midpoint Formula....

$(\dfrac {x_1+x_2}{2},\dfrac {y_1+y_2}{2})$ , where is the first point and is the second point

Step 2: Identify the points and their specific terms...

Step 3: Plug in the values into the midpoint formula...

$(\dfrac {-12+14}{2},\dfrac {10-6}{2})$

Simplify...

$(\dfrac {2}{2},\dfrac {4}{2})=(1,2)$

Give the coordinates of the midpoint of the line segment whose endpoints are the intercepts of the line of the equation

.

Tap to see back →

The x-intercept and y-intercept of the line of an equation can be found by substituting 0 for and , respectively, as follows:

x-intercept:

Substitute and simplify:

Solve for by dividing by 2 on both sides:

$2x \div 2 = 40 \div 2$

The x-intercept of the line is located at

The y-intercept can be found by setting and solving for in a similar fashion:

$5y \div 5 = 40 \div 5$

The y-intercept is located at .

The midpoint of a line segment, given its endpoints and , is located at

$\left ( $$\frac{x_{1}$$$+x_{2}$}{2}, $$\frac{y_{1}$$$+y_{2}$}{2} \right )$ ;

substituting accordingly,

The midpoint is located at .

What is the midpoint of the line segment created by the points and ?

Tap to see back →

The midpoint of the line segment between two points

and

is given by the formula

.

Thus, since the line segment is generated by

and

applying the midpoint formula we have

$($\frac{-2+3}{2}$,$\frac{16+7}{2}$)= ($\frac{1}{2}$,$\frac{23}{2}$)$

as the midpoint.

What is the midpoint between and ?

Tap to see back →

Step 1: Recall the midpoint Formula....

$(\dfrac {x_1+x_2}{2},\dfrac {y_1+y_2}{2})$ , where is the first point and is the second point

Step 2: Identify the points and their specific terms...

Step 3: Plug in the values into the midpoint formula...

$(\dfrac {-12+14}{2},\dfrac {10-6}{2})$

Simplify...

$(\dfrac {2}{2},\dfrac {4}{2})=(1,2)$