Rational numbers - HiSET

Card 0 of 4

Solve the following problem:

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

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In order to solve this problem we need to follow the correct order of operations. Order of operations are outlined by the acronym PEMDAS: parenthesis, exponents, multiplication, division, addition, and subtraction. These operations should be performed in this order from the left to the right.

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Let's start by solving the innermost parenthesis remember to work on exponents first.

$=\frac{(3+2-4)}{4}$ +\left( 5\times2 \right)-(24-8+2)$

Simplify.

$=\frac{1}{4}$ +10-18$

$=10\t$\frac{1}{4}$-18$

$=-7\t$\frac{3}{4}$$

Solve the following problem:

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Tap to see back →

In order to solve this problem we need to follow the correct order of operations. Order of operations are outlined by the acronym PEMDAS: parenthesis, exponents, multiplication, division, addition, and subtraction. These operations should be performed in this order from the left to the right.

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Let's start by solving the innermost parenthesis remember to work on exponents first.

$=\frac{(3+2-4)}{4}$ +\left( 5\times2 \right)-(24-8+2)$

Simplify.

$=\frac{1}{4}$ +10-18$

$=10\t$\frac{1}{4}$-18$

$=-7\t$\frac{3}{4}$$

Solve the following problem:

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Tap to see back →

In order to solve this problem we need to follow the correct order of operations. Order of operations are outlined by the acronym PEMDAS: parenthesis, exponents, multiplication, division, addition, and subtraction. These operations should be performed in this order from the left to the right.

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Let's start by solving the innermost parenthesis remember to work on exponents first.

$=\frac{(3+2-4)}{4}$ +\left( 5\times2 \right)-(24-8+2)$

Simplify.

$=\frac{1}{4}$ +10-18$

$=10\t$\frac{1}{4}$-18$

$=-7\t$\frac{3}{4}$$

Solve the following problem:

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Tap to see back →

In order to solve this problem we need to follow the correct order of operations. Order of operations are outlined by the acronym PEMDAS: parenthesis, exponents, multiplication, division, addition, and subtraction. These operations should be performed in this order from the left to the right.

$\left ( $\frac{(3+2-1\times4)}{4}$ \right )+\left ( (2+3)\times(4-2) \right )-((8\times $3)-2^3$+(1+1))$

Let's start by solving the innermost parenthesis remember to work on exponents first.

$=\frac{(3+2-4)}{4}$ +\left( 5\times2 \right)-(24-8+2)$

Simplify.

$=\frac{1}{4}$ +10-18$

$=10\t$\frac{1}{4}$-18$

$=-7\t$\frac{3}{4}$$