Algebraic Concepts - ISEE Middle Level Quantitative Reasoning
Card 0 of 4052
Which of the following is equivalent to
?
Which of the following is equivalent to ?
The expression is the sum of two unlike terms, and therefore cannot be further simplified. None of these responses is correct.
The expression is the sum of two unlike terms, and therefore cannot be further simplified. None of these responses is correct.
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Which quantity is greater if
?


Which quantity is greater if ?
We know that
is always positive for all values of
. Therefore
would be negative for all values of
. From this conclusion, we know:

So we have:


is the greater quantity.
We know that is always positive for all values of
. Therefore
would be negative for all values of
. From this conclusion, we know:
So we have:
is the greater quantity.
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Which quantity is greater if
?


Which quantity is greater if ?
A positive number raised to the third power will be positive, while a negative number raised to the third power will remain negative.
If
, then
and
.
If
, then
and
.
Since we do not know if
is positive or negative, we cannot draw a conclusion about which option is greater.
If
, then
is greater.
If
, then
is greater.
A positive number raised to the third power will be positive, while a negative number raised to the third power will remain negative.
If , then
and
.
If , then
and
.
Since we do not know if is positive or negative, we cannot draw a conclusion about which option is greater.
If , then
is greater.
If , then
is greater.
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Which quantity is greater if
?


Which quantity is greater if ?
When
we can write:

We know that
and
. Based on this, we can compare the two given quantities.


is the greater quantity.
When we can write:
We know that and
. Based on this, we can compare the two given quantities.
is the greater quantity.
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Which quantity is greater if
?


Which quantity is greater if ?
We know that
is greater than
. We can easily test a few values for
to determine if the values are increasing or decreasing.
If
:

If
:

If
:

The value of
is increasing, with the smallest possible value being
. From this, we know that
, so
.
We know that is greater than
. We can easily test a few values for
to determine if the values are increasing or decreasing.
If :
If :
If :
The value of is increasing, with the smallest possible value being
. From this, we know that
, so
.
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Which of the following is equivalent to
?
Which of the following is equivalent to ?
Using the distributive property:

and

Using the associative property of multiplication:

We can rewrite
as
; using the commutative and associative properties of multiplication:

is the sum of unlike terms and cannot be simplified.
is the correct choice.
Using the distributive property:
and
Using the associative property of multiplication:
We can rewrite as
; using the commutative and associative properties of multiplication:
is the sum of unlike terms and cannot be simplified.
is the correct choice.
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is a positive integer.
Which is the greater quantity?
(A) 
(B) 
is a positive integer.
Which is the greater quantity?
(A)
(B)
Depending on the value of
, it is possible for either expression to be greater or for both to be equal.
Case 1: 

and

So the two are equal.
Case 2: 

and

So (B) is greater.
The correct response is that it cannot be determined which is greater.
Depending on the value of , it is possible for either expression to be greater or for both to be equal.
Case 1:
and
So the two are equal.
Case 2:
and
So (B) is greater.
The correct response is that it cannot be determined which is greater.
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is a positive integer.
Which is the greater quantity?
(A) 
(B) 
is a positive integer.
Which is the greater quantity?
(A)
(B)


Since
,
, so (A) is greater regardless of the value of
.
Since ,
, so (A) is greater regardless of the value of
.
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is a positive integer.
Which is the greater quantity?
(A) 
(B) 
is a positive integer.
Which is the greater quantity?
(A)
(B)


Since
, and
is positive,
then by the multiplication property of inequality,

making (A) greater regardless of the value of
.
Since , and
is positive,
then by the multiplication property of inequality,
making (A) greater regardless of the value of .
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is a positive integer.
Which is the greater quantity?
(A) 
(B) 
is a positive integer.
Which is the greater quantity?
(A)
(B)


Regardless of the value of
, the expressions are equal.
Regardless of the value of , the expressions are equal.
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Define an operation on the real numbers as follows:
For all real values of
and
,

is a positive number. Which is the greater quantity?
(a) 
(b) 
Define an operation on the real numbers as follows:
For all real values of and
,
is a positive number. Which is the greater quantity?
(a)
(b)

so

and




The two are equal regardless of the value of
.
so
and
The two are equal regardless of the value of .
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Which is the greater quantity?
(a) 
(b) 18
Which is the greater quantity?
(a)
(b) 18
The information is insufficient, as we see by exploring two cases:
Case 1: 

Case 2: 

Remember, the three variables need not stand for whole numbers.
The information is insufficient, as we see by exploring two cases:
Case 1:
Case 2:
Remember, the three variables need not stand for whole numbers.
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and
are both negative numbers. Which is the greater quantity?
(a) 
(b) 
and
are both negative numbers. Which is the greater quantity?
(a)
(b)
The two quantities are equal regardless of the values of
and
. To see this, we note that

and

Therefore, by the addition property of equality,

The two quantities are equal regardless of the values of and
. To see this, we note that
and
Therefore, by the addition property of equality,
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Billy is at the store purchasing flowers for his mother, his grandmother, and his friend. He finds roses on sale by the half dozen (6), tulips selling by the dozen (12), and daisies selling groups of 18.
Billy wants to have the same number of flowers in each bouquet, so that he is able to give everyone the same number of each flower. How many bundles of roses, tulips, and daisies will he have to buy so he has the same amount of each? (Please answer by roses, tulips, then daisies.)
Billy is at the store purchasing flowers for his mother, his grandmother, and his friend. He finds roses on sale by the half dozen (6), tulips selling by the dozen (12), and daisies selling groups of 18.
Billy wants to have the same number of flowers in each bouquet, so that he is able to give everyone the same number of each flower. How many bundles of roses, tulips, and daisies will he have to buy so he has the same amount of each? (Please answer by roses, tulips, then daisies.)
This is a least common multiple problem because we want to have the same number of each flower; meaning if I have 10 roses in each bouquet I should have 10 tulips and 10 daisies as well. In order to solve this problem we should break down the story problem. Let's look at the numbers we are having to work with: 6, 12, 18.
To do least common multiple we must look at the prime factors of each number and we can list them out. A factor is simply a number multiplied by a number to give us a product. A prime number is a number that contains only two factors, one of them being 1 and the other its own number.
So lets list the prime factors of 6, 12, and 18
(2 and 3 are both prime numbers, and factors of 6)
(2 x 2 = 4. 4x3=12 We have to say 2 x 2 because 4 is not a prime number).

Now we have the prime factors listed out for each of our numbers. Next is a fun trick. We must choose which number contains the most of each prime factor. In this case which number contains the most 2's? (12; because 12 has two 2 prime factors). Which number contains the most 3's? (18; because 18 has two 3 prime factors).
Our next step is to multiply the most of our prime factors so in this case: 
36 is our least common multiple. So now what do you think we can do with this number? Well the 36 means that is the lowest number of flowers we need of each type in order to have an equal amount of each for the boquets.
Knowing this, if we need 36 roses, and we are able to buy 6 roses per bundle. We need 6 bundles of roses, because 36 divided by 6 is 6. If we get 12 tulips by the bundle, we take 36 divided by 12 to give us 3 bundles of tulips needed. Lastly we can buy 18 daisies per bundle, 36 divided by 18 gives us 2 bundles needed giving us our answers 6, 3, 2 (bundles of roses, tulips, and daisies).
This is a least common multiple problem because we want to have the same number of each flower; meaning if I have 10 roses in each bouquet I should have 10 tulips and 10 daisies as well. In order to solve this problem we should break down the story problem. Let's look at the numbers we are having to work with: 6, 12, 18.
To do least common multiple we must look at the prime factors of each number and we can list them out. A factor is simply a number multiplied by a number to give us a product. A prime number is a number that contains only two factors, one of them being 1 and the other its own number.
So lets list the prime factors of 6, 12, and 18
(2 and 3 are both prime numbers, and factors of 6)
(2 x 2 = 4. 4x3=12 We have to say 2 x 2 because 4 is not a prime number).
Now we have the prime factors listed out for each of our numbers. Next is a fun trick. We must choose which number contains the most of each prime factor. In this case which number contains the most 2's? (12; because 12 has two 2 prime factors). Which number contains the most 3's? (18; because 18 has two 3 prime factors).
Our next step is to multiply the most of our prime factors so in this case:
36 is our least common multiple. So now what do you think we can do with this number? Well the 36 means that is the lowest number of flowers we need of each type in order to have an equal amount of each for the boquets.
Knowing this, if we need 36 roses, and we are able to buy 6 roses per bundle. We need 6 bundles of roses, because 36 divided by 6 is 6. If we get 12 tulips by the bundle, we take 36 divided by 12 to give us 3 bundles of tulips needed. Lastly we can buy 18 daisies per bundle, 36 divided by 18 gives us 2 bundles needed giving us our answers 6, 3, 2 (bundles of roses, tulips, and daisies).
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First find the exponent value for each number:

Then divide accordingly. The answer is 128.
First find the exponent value for each number:
Then divide accordingly. The answer is 128.
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First, following order of operations, multiply:

Then, divide:

First, following order of operations, multiply:
Then, divide:
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Multiply: 
Answer: 
Multiply:
Answer:
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First, solve the square root:

Then, solve the equation accordingly:

First, solve the square root:
Then, solve the equation accordingly:
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Angelina leaves her home at 6 AM. If she drives 65 miles per hour, what time will she arrive to her grandfather's home, 195 miles away?
Angelina leaves her home at 6 AM. If she drives 65 miles per hour, what time will she arrive to her grandfather's home, 195 miles away?
First, divide
.
Then, calculate what time Angelina will arrive by adding 3 hours to 6:00.

The answer is 9:00 AM.
First, divide .
Then, calculate what time Angelina will arrive by adding 3 hours to 6:00.
The answer is 9:00 AM.
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First, convert each fraction into an improper fraction. Then, change the operation to multiplication and flip the second fraction. Reduce and multiply.

First, convert each fraction into an improper fraction. Then, change the operation to multiplication and flip the second fraction. Reduce and multiply.
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