Understanding Negative Exponents - Math

Card 0 of 8

Question

Solve for :

$(x+5)^{-3} = -1$

Answer

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Compare your answer with the correct one above

Question

Which of the following is equivalent to $3^{-2}$ ?

Answer

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Compare your answer with the correct one above

Question

Solve for :

$(x+5)^{-3} = -1$

Answer

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Compare your answer with the correct one above

Question

Which of the following is equivalent to $3^{-2}$ ?

Answer

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Compare your answer with the correct one above

Question

Solve for :

$(x+5)^{-3} = -1$

Answer

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Compare your answer with the correct one above

Question

Which of the following is equivalent to $3^{-2}$ ?

Answer

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Compare your answer with the correct one above

Question

Solve for :

$(x+5)^{-3} = -1$

Answer

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Compare your answer with the correct one above

Question

Which of the following is equivalent to $3^{-2}$ ?

Answer

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Compare your answer with the correct one above

Tap the card to reveal the answer

Understanding Negative Exponents - Math

Solve for :

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation. Subtract from both sides:

Which of the following is equivalent to ?

By definition, . In our problem, and . Then, we have .

Solve for :

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation. Subtract from both sides:

Which of the following is equivalent to ?

By definition, . In our problem, and . Then, we have .

Solve for :

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation. Subtract from both sides:

Which of the following is equivalent to ?

By definition, . In our problem, and . Then, we have .

Solve for :

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation. Subtract from both sides:

Which of the following is equivalent to ?

By definition, . In our problem, and . Then, we have .

Solve for :

$(x+5)^{-3} = -1$

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Which of the following is equivalent to $3^{-2}$ ?

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Solve for :

$(x+5)^{-3} = -1$

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Which of the following is equivalent to $3^{-2}$ ?

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Solve for :

$(x+5)^{-3} = -1$

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Which of the following is equivalent to $3^{-2}$ ?

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .

Solve for :

$(x+5)^{-3} = -1$

Raise both sides of the equation to the inverse power of to cancel the exponent on the left hand side of the equation.

$\rightarrow ((x+5)^{-3})^{-\frac{1}{3}} = (-1)^{-\frac{1}{3}}$

$\rightarrow x+5 = -1$

Subtract from both sides:

$\rightarrow (x+5) - 5 = (-1)-5$

$\rightarrow x = -6$

Which of the following is equivalent to $3^{-2}$ ?

By definition,

$b^{-x} = \frac{1}{b^{x}}$ .

In our problem, and .

Then, we have $\frac{1}{3^{2}} = \frac{1}{9}$ .