Electrophoresis and Protein Separation (5C)
Help Questions
MCAT Chemical and Physical Foundations of Biological Systems › Electrophoresis and Protein Separation (5C)
A lab separated two recombinant proteins by SDS-PAGE (denaturing) using a 10% polyacrylamide gel at pH 8.3 and 200 V for 30 min. Both proteins were fully reduced and treated with excess SDS. Bands were detected by Coomassie staining.
Table 1. Observed migration distance Protein | Mass (kDa) | Observed migration (mm) R | 20 | 41 S | 60 | 18
Which protein is most likely to migrate faster under these SDS-PAGE conditions, consistent with electrophoresis principles?
Protein S, because SDS makes proteins migrate toward the cathode and S is closer to neutral pH.
Protein R, because SDS largely normalizes charge-to-mass ratio and smaller proteins move more easily through the gel.
Protein R, because its native pI is likely lower, giving it a more negative charge at pH 8.3.
Protein S, because its larger size experiences greater electrophoretic force at fixed voltage.
Explanation
This question tests comprehension of protein separation by SDS-PAGE, focusing on denaturing conditions and size-based migration. In electrophoresis, proteins migrate based on charge and size, but SDS denatures them, binds proportionally to mass, and imparts a uniform negative charge-to-mass ratio, making separation primarily by size through the gel sieve. The setup uses SDS-PAGE at pH 8.3, where proteins migrate to the anode, with smaller proteins moving faster due to easier passage through gel pores. Answer B is correct because Protein R (20 kDa) migrates farther (41 mm) than S (60 kDa, 18 mm), as SDS normalizes charge and smaller size allows faster migration, aligning with principles. Distractor D fails by referencing native pI, misconstruing that SDS overrides native charge, making pI irrelevant under denaturing conditions. To verify, run a ladder of known masses and plot log(mass) vs. migration for linearity, confirming size-based separation. Additionally, compare non-SDS native runs where charge differences could alter migration order despite sizes.
A researcher performed SDS-PAGE (pH 8.3) on two proteins D1 and D2 that differ in MW (D1: 15 kDa; D2: 150 kDa). At 120 V for 50 min, D1 migrated 6.5 cm and D2 migrated 1.8 cm. The researcher then doubled the voltage but kept run time the same; both proteins migrated farther, but the distance between their bands (in cm) decreased.
Which factor most likely contributed to the decreased band spacing at higher voltage?
Increased heating and diffusion at higher voltage broadened bands and compressed apparent spacing.
Higher voltage eliminated the sieving effect by enlarging gel pores during the run.
Higher voltage caused large proteins to become positively charged and reverse direction.
Higher voltage decreased the negative charge provided by SDS, equalizing mobilities.
Explanation
This question evaluates voltage's effect on band spacing in SDS-PAGE, considering heating and diffusion. In electrophoresis, higher voltage increases speed but causes heating, broadening bands and compressing apparent spacing, especially for disparate MW. In this pH 8.3 setup, doubled voltage decreased spacing between 15 and 150 kDa despite farther migration. The correct answer A is consistent as heating broadened bands, reducing effective separation. Distractor D is incorrect, claiming voltage enlarges pores and eliminates sieving, a misconception since voltage doesn't alter gel structure. A check is to run with constant current to minimize heating and preserve spacing. Monitoring band widths at varying voltages can verify diffusion's role in resolution loss.
A lab ran isoelectric focusing (IEF) on a serum fraction, then cut a lane and ran it in a second dimension SDS-PAGE (2D electrophoresis). In IEF, proteins focused at positions corresponding to pH values. Four spots were identified:
Spot | IEF position (pH) | SDS-PAGE MW (kDa) 1 | 4.9 | 66 2 | 6.8 | 66 3 | 8.9 | 66 4 | 6.8 | 25
Which statement is most consistent with the electrophoresis data?
Spots 1–3 differ only in size because IEF separates primarily by MW.
Spots 1–3 must be the same protein because identical MW implies identical pI.
Spot 4 must have the highest pI because it has the lowest MW.
Spots 1–3 likely represent proteins of identical MW but different pI values (e.g., isoforms or post-translational modifications).
Explanation
This question tests interpretation of 2D electrophoresis data, combining isoelectric focusing (IEF) and SDS-PAGE for separation by pI and MW. Electrophoresis separates by charge in IEF (proteins stop at their pI) and by size in SDS-PAGE, allowing identification of isoforms with same MW but different pI. In this 2D setup, horizontal IEF positions reflect pI, and vertical SDS-PAGE reflects MW. The correct answer A is supported as spots 1–3 share MW (66 kDa) but differ in pI (4.9, 6.8, 8.9), likely isoforms from modifications. Distractor D fails by stating IEF separates by MW, a misconception since IEF is charge-based, not size-based. To verify, re-run individual spots in 1D IEF to confirm pI differences. Comparing with unmodified proteins can check if modifications alter pI without changing MW.
A lab compared native PAGE migration of a 40 kDa enzyme at two buffer pH values. The enzyme has pI 7.4. The gel was run at 140 V for 30 min, loaded at the cathode (−).
Results: at pH 6.8 the enzyme band remained near the well (0.5 cm). At pH 9.0 the band migrated 4.7 cm toward the anode (+).
Which explanation is most consistent with electrophoresis principles?
At pH 6.8 the enzyme is net positive and is repelled by the cathode; at pH 9.0 it is neutral.
The change in migration is primarily due to MW changing with pH rather than charge.
At pH 6.8 the enzyme is near neutral net charge; at pH 9.0 it is net negative and migrates toward the anode.
At pH 6.8 the enzyme is net negative; at pH 9.0 it becomes net positive and migrates toward the anode.
Explanation
This question assesses how pH affects protein charge and migration in native PAGE, testing understanding of isoelectric point (pI) influence. In electrophoresis, proteins' net charge depends on pH relative to pI: negative above pI, positive below, with charge magnitude affecting migration speed and direction. In this native PAGE setup loaded at the cathode, migration toward the anode at higher pH indicates net negative charge. The correct answer A is consistent because at pH 6.8 (below pI 7.4), the enzyme is near neutral or positive with little migration (0.5 cm), while at pH 9.0 (above pI), it is net negative and migrates far (4.7 cm). Distractor D is incorrect as it attributes migration change to MW variation with pH, a misconception since MW is constant and charge drives the difference. To verify, test at pH equal to pI to confirm zero migration. Comparing migration at multiple pH values can map charge transitions around pI for similar proteins.
A protein engineering team compared a wild-type enzyme (WT) and a mutant (Mut) using native gel electrophoresis at constant 110 V for 28 min. Both proteins had similar size by SEC (≈60 kDa). The gel was run in either pH 7.4 or pH 5.5 buffer with wells near the cathode (−). Migration distance toward the anode (+) is shown.
Data (cm):
- pH 7.4: WT 2.8; Mut 4.1
- pH 5.5: WT 0.6; Mut 0.7
Which conclusion about the mutation is most supported by the results?
The mutation likely raised the WT pI above 7.4, causing the mutant to become net positive and migrate faster to the anode.
The mutation likely increased net negative charge at pH 7.4, producing greater anode-directed migration without a size change.
The mutation likely increased molecular size, which increased migration distance at pH 7.4 by reducing gel friction.
The mutation changed the buffer pH during the run, reversing electrode polarity at pH 5.5 and collapsing separation.
Explanation
This question tests understanding of how mutations affect protein charge and electrophoretic mobility in native gels. In native electrophoresis, proteins migrate based on their net charge at the running pH, and mutations that alter charged amino acids can significantly change migration patterns without affecting protein size. At pH 7.4, the wild-type migrated 2.8 cm while the mutant migrated 4.1 cm toward the anode, indicating the mutant has a more negative charge - this suggests the mutation either added negative charges (like Asp or Glu) or removed positive charges (like Lys or Arg). At pH 5.5, both proteins showed minimal migration (0.6-0.7 cm), suggesting both are near their pI values at this pH, which explains the loss of separation - when proteins approach their pI, net charge approaches zero regardless of mutations. The mutation likely increased net negative charge at pH 7.4 without changing molecular size, as confirmed by SEC showing similar sizes. Choice C incorrectly suggests the mutation raised the pI above 7.4, which would make the mutant positive and reduce anode migration, opposite to what's observed. To identify charge-altering mutations by electrophoresis, compare migration at multiple pH values - mutations affecting charge will show different migration patterns at pH values away from the pI but similar patterns near the pI.
A lab tested the effect of voltage on band resolution in SDS-PAGE (10% gel) for two proteins: A (50 kDa) and B (55 kDa). Samples were denatured with SDS and run in identical buffer at either 80 V for 60 min or 200 V for 24 min (same approximate run length). Band separation (distance between band centers) and band broadening were measured.
Results:
- 80 V: separation 0.35 cm; average band width 0.18 cm
- 200 V: separation 0.30 cm; average band width 0.34 cm
Based on the data, which factor most likely reduced separation efficiency at 200 V?
Higher voltage increased protein molecular mass by promoting aggregation, reducing migration differences.
Higher voltage decreased the electric field strength, lowering protein velocity and increasing overlap.
At higher voltage, SDS no longer binds uniformly, making smaller proteins less negatively charged than larger proteins.
Increased Joule heating at higher voltage increased diffusion and band broadening.
Explanation
This question tests understanding of how voltage affects band resolution in SDS-PAGE through Joule heating effects. In gel electrophoresis, applying voltage generates heat (Joule heating) proportional to the square of the voltage, and excessive heating can reduce separation quality by increasing molecular diffusion and band broadening. The data shows that at 200V, despite similar total migration distance, band separation decreased (0.35 to 0.30 cm) while band width nearly doubled (0.18 to 0.34 cm), indicating significant band broadening that reduced resolution between the two proteins. Increased Joule heating at higher voltage causes uneven temperature distribution in the gel, leading to increased diffusion of protein bands and loss of sharpness, which explains the observed reduction in separation efficiency. Choice B incorrectly states higher voltage decreases electric field strength, when voltage directly increases field strength; the issue is the thermal effects, not field strength. For optimal SDS-PAGE resolution, balance voltage to achieve reasonable run times while minimizing Joule heating - lower voltage with longer run times often provides sharper bands than high voltage with shorter times.
A researcher optimized separation of three similarly sized enzymes using native PAGE (8% gel) in pH 8.0 buffer. Wells were near the cathode (−). The enzymes had the same mass (50 kDa) but different pI values: E1 pI 5.0, E2 pI 7.8, E3 pI 9.5. The gel was run for 18 min at different voltages.
Migration distance toward the anode (cm):
- 75 V: E1 1.8, E2 0.3, E3 0.0
- 150 V: E1 3.6, E2 0.6, E3 0.0
Based on the data, which factor most influences separation efficiency between E1 and E2 under these conditions?
Direction of the electric field, because reversing the leads would increase the distance between E1 and E2.
Molecular size, because proteins of identical mass separate primarily by sieving through the gel.
Net charge at the running pH, because E1 is farther from its pI than E2 and migrates more.
Voltage, because increasing voltage changes the proteins’ pI values and increases their charge difference.
Explanation
This question tests understanding of factors affecting protein separation in native PAGE, specifically the role of net charge versus other parameters. In native electrophoresis, proteins separate based on their charge-to-mass ratio and size, with net charge being the primary factor when proteins have similar sizes. At pH 8.0, E1 (pI 5.0) is 3.0 pH units above its pI, giving it a large negative charge, while E2 (pI 7.8) is only 0.2 pH units above its pI, resulting in a very small negative charge - this large difference in net charge explains why E1 migrates much farther (3.6 cm at 150V) than E2 (0.6 cm). The separation efficiency between E1 and E2 is determined by their different net charges at the running pH, not by voltage (which affects migration speed but not relative separation), molecular size (they're identical), or field direction. Choice A incorrectly suggests voltage changes pI values, when pI is an intrinsic protein property independent of applied voltage. To optimize protein separation in native PAGE, choose a pH that maximizes the difference in net charge between proteins by considering their pI values - proteins far from their pI at the running pH will have larger net charges and migrate more.
A clinical lab analyzed a plasma protein mixture by native agarose gel electrophoresis to assess inflammatory status. The gel was run in 25 mM Tris-glycine buffer at pH 8.6 with the wells placed near the cathode (−) and the anode (+) at the far end. A constant 120 V was applied for 25 min. Four purified proteins (each 1 mg/mL) were run in adjacent lanes: albumin (66 kDa, pI 4.7), transferrin (80 kDa, pI 5.9), IgG (150 kDa, pI 7.4), and lysozyme (14 kDa, pI 11.0). Migration distances from the wells were recorded.
Based on the data, which conclusion about protein net charge at pH 8.6 is most supported by the electrophoresis results?
Data (distance toward anode, cm): albumin 4.8; transferrin 3.6; IgG 1.1; lysozyme 0.0.
Albumin is net negative at pH 8.6, consistent with its strong migration toward the anode.
Transferrin is net positive at pH 8.6 because proteins with higher pI values migrate farther toward the anode.
Lysozyme is net negative at pH 8.6 because it is the smallest protein and should migrate farthest toward the anode.
IgG is net positive at pH 8.6 because it migrates only a short distance toward the anode.
Explanation
This question tests understanding of protein net charge and migration in native gel electrophoresis at a specific pH. In electrophoresis, proteins migrate based on their net charge - negatively charged proteins move toward the positive anode, while positively charged proteins move toward the negative cathode. At pH 8.6, proteins with pI values below 8.6 will be negatively charged (pH > pI), while those with pI values above 8.6 will be positively charged (pH < pI). The data shows albumin (pI 4.7) migrated 4.8 cm toward the anode, confirming it is negatively charged at pH 8.6, which is consistent with its pI being well below the running pH. Choice A incorrectly relates size to charge, as lysozyme's lack of migration (0.0 cm) indicates it's positively charged (pI 11.0 > pH 8.6), not negative. To verify protein charge in electrophoresis, always compare the running pH to the protein's pI: if pH > pI, the protein is negative; if pH < pI, the protein is positive.
Two purified enzymes (P1 and P2) were compared by native PAGE (no SDS) at constant size marker calibration. Runs were performed at 150 V for 20 min in buffers of different pH. The gel was oriented with cathode at the top and anode at the bottom.
Migration distance toward anode (mm):
- pH 6.0: P1 = 6, P2 = 24
- pH 8.5: P1 = 20, P2 = 8
Which conclusion about relative isoelectric points ($pI$) is most supported by the data?
P1 has a higher $pI$ than P2.
P2 has a higher $pI$ than P1.
Neither protein has a $pI$ because only nucleic acids have $pI$ values.
Both proteins have the same $pI$ because they swap migration distances.
Explanation
This question tests understanding of how protein migration changes with pH relative to pI in native PAGE. In electrophoresis, proteins are positively charged below their pI and negatively charged above their pI. At pH 6.0, P2 migrates farther toward the anode (24 mm vs 6 mm), indicating it has more negative charge. At pH 8.5, P1 migrates farther (20 mm vs 8 mm), showing P1 is more negative at higher pH. This reversal indicates P2's pI lies between pH 6.0 and 8.5, while P1's pI is below pH 6.0. Since P2 transitions from more negative to less negative as pH increases from 6.0 to 8.5, P2 must have the higher pI. A useful check is that proteins become less negative as pH approaches their pI from above.
A lab compared two proteins of similar mass (~50 kDa) by native PAGE at pH 7.0. The gel was run at 140 V for 18 min. Protein Q migrated 26 mm toward the anode, while Protein R migrated 5 mm toward the anode.
Which statement is most consistent with electrophoresis principles under these conditions?
Protein Q likely has a more negative net charge than Protein R at pH 7.0.
Protein Q likely has a larger hydrodynamic radius, causing faster migration.
Protein R likely has a more negative net charge than Protein Q at pH 7.0.
Protein R must be positively charged because it migrated toward the anode.
Explanation
This question tests understanding of how net charge affects migration in native PAGE. In native electrophoresis at pH 7.0, proteins migrate toward the anode based on their net negative charge - more negative proteins migrate farther. Since Protein Q migrated 26 mm while Protein R only migrated 5 mm (both toward the anode), Protein Q must have a more negative net charge at pH 7.0. The similar masses (~50 kDa) rule out size as the primary factor differentiating their migration. Choice A reverses the charge relationship, while Choice D incorrectly states that anode-migrating proteins are positive (they're actually negative). A key check is that in native PAGE, migration distance directly correlates with net charge magnitude when sizes are similar.