Analyze and Evaluate Scientific Explanations and Predictions
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MCAT Chemical and Physical Foundations of Biological Systems › Analyze and Evaluate Scientific Explanations and Predictions
A thin, nonreactive polymer film separates two aqueous compartments containing KCl at the same concentration (0.10 M) but different temperatures: side 1 at 298 K and side 2 at 310 K. The film is permeable to ions and water, and no external voltage is applied. A student predicts a sustained net electric current will flow from the hot side to the cold side solely due to the temperature difference. Assuming both compartments remain electrically neutral and that diffusion is driven by chemical potential gradients, which evaluation is most consistent with these principles?
Given: For an ideal solute, $\mu = \mu^\circ + RT\ln a$; for dilute solutions, $a\approx$ concentration.
A sustained net current is expected because the hot side has higher $RT$ and therefore higher activity at the same concentration.
No sustained net current is expected because ions cannot diffuse through a polymer film under any conditions.
No sustained net current is expected because equal concentrations imply no chemical potential gradient for KCl at steady state.
A sustained net ionic current is expected because higher temperature always increases ion concentration.
Explanation
This question tests understanding of electrochemical equilibrium and the role of chemical potential gradients. The chemical potential for an ideal solute is μ = μ° + RT ln a, where activity a ≈ concentration for dilute solutions. At the same concentration (0.10 M) on both sides, the activity is identical, so the only difference in chemical potential comes from the RT term. However, for ionic transport to create a sustained current, there must be a net driving force - either a concentration gradient or an applied voltage. While thermal gradients can create transient charge separation (Seebeck effect), they cannot sustain a net ionic current in a closed system at steady state because this would violate electroneutrality. Both compartments must remain electrically neutral, preventing sustained unidirectional ion flow. Choice C incorrectly suggests higher RT creates higher activity at the same concentration, misunderstanding that RT appears outside the logarithm. Choice A wrongly claims temperature increases ion concentration. When evaluating ionic transport, remember that sustained currents require maintained driving forces that don't violate fundamental constraints like electroneutrality.
A researcher tests whether dissolved CO$_2$ (aq) measurably acidifies water in a sealed 1.0 L vessel at 25°C. The vessel initially contains pure water equilibrated with 1.0 atm N$_2$ (no CO$_2$). The headspace gas is then replaced with 0.20 atm CO$_2$ (balance N$_2$) and allowed to re-equilibrate without changing temperature. Assume Henry’s law for CO$_2$: $\text{CO}2(\text{aq})=k_H P{\text{CO}_2}$ with $k_H=3.3\times10^{-2}$ M/atm, and that each dissolved CO$_2$ molecule contributes at most one H$^+$ via $\text{CO}_2+\text{H}_2\text{O}\rightleftharpoons \text{H}^+ + \text{HCO}_3^-$. Which prediction is most consistent with these principles regarding the final pH compared with the initial pH (7.0)?
It decreases, because increasing $P_{\text{CO}_2}$ increases $[\text{CO}_2(\text{aq})]$ and can increase $[\text{H}^+]$.
It increases, because CO$_2$ is a base that consumes H$^+$ when dissolved.
It decreases only if the vessel is open to the atmosphere; in a sealed vessel pH cannot change.
It is unchanged, because Henry’s law affects only gases, not aqueous equilibria.
Explanation
This question tests the ability to analyze and evaluate scientific predictions about pH changes when CO₂ dissolves in water. The key principle is that dissolved CO₂ forms carbonic acid through the equilibrium CO₂ + H₂O ⇌ H⁺ + HCO₃⁻, which releases H⁺ ions and lowers pH. In this sealed vessel system, Henry's law determines that [CO₂(aq)] = kH × PCO₂ = 3.3×10⁻² M/atm × 0.20 atm = 6.6×10⁻³ M. Since each dissolved CO₂ can contribute at most one H⁺, this increases [H⁺] and decreases pH below the initial 7.0. Answer A correctly predicts pH decreases because increasing PCO₂ increases dissolved CO₂ concentration, which increases H⁺ concentration. Answer B incorrectly claims CO₂ is a base - this is a common misconception confusing CO₂ with carbonate ions. To evaluate such predictions, check whether the dissolved species acts as an acid (releases H⁺) or base (consumes H⁺), then apply equilibrium principles to predict pH changes.
A researcher studies osmotic flow across a semipermeable membrane that passes water but not sucrose. Side 1 contains 0.10 M sucrose; Side 2 contains 0.20 M sucrose. Temperature is held at 298 K, and sucrose is treated as a non-electrolyte ($i=1$). The osmotic pressure difference is approximated by $\Delta\pi = iRT\Delta C$, with $R=0.082$ L·atm·mol$^{-1}$·K$^{-1}$. Which prediction is most consistent with the model for the direction of net water movement and the sign of $\Delta\pi$ (defined as $\pi_2-\pi_1$)?
Water moves from Side 1 to Side 2, and $\Delta\pi>0$.
Water moves from Side 2 to Side 1, and $\Delta\pi<0$.
Water moves from Side 1 to Side 2, and $\Delta\pi<0$.
No net water movement occurs because sucrose does not dissociate ($i=1$).
Explanation
This question tests the ability to evaluate predictions about osmotic flow using the osmotic pressure equation Δπ = iRTΔC. The fundamental principle is that water moves from regions of lower solute concentration (lower osmotic pressure) to higher concentration (higher osmotic pressure) across semipermeable membranes. With Side 1 at 0.10 M and Side 2 at 0.20 M sucrose, the concentration difference ΔC = 0.10 M creates an osmotic pressure difference Δπ = π₂ - π₁ = iRT(C₂ - C₁) > 0. Water moves from the dilute Side 1 to the concentrated Side 2 to equalize concentrations. Answer B correctly predicts water movement from Side 1 to Side 2 with Δπ > 0. Answer A reverses both the flow direction and sign - this is a common error confusing which side has higher pressure. To evaluate osmotic predictions, identify the concentration difference, calculate Δπ = iRTΔC, and remember water flows toward higher solute concentration.
A spectrophotometric assay uses Beer–Lambert law: $A = \varepsilon \ell c$. A dye has $\varepsilon=1.0\times10^4$ M$^{-1}$·cm$^{-1}$ at the measurement wavelength. In Trial 1, a 1.0 cm cuvette contains $c=10,\mu$M dye. In Trial 2, the dye concentration is unchanged but a 2.0 cm pathlength cuvette is used. Which prediction is most consistent with the model for the absorbance in Trial 2 relative to Trial 1?
It quadruples, because absorbance is proportional to $\ell^2$.
It is half, because a longer pathlength spreads light over a larger volume.
It is unchanged, because absorbance depends on concentration only.
It doubles, because absorbance is proportional to pathlength at fixed $c$.
Explanation
This question tests the ability to evaluate predictions using Beer-Lambert law A = εℓc. The key principle is that absorbance depends linearly on three factors: molar absorptivity ε (constant for a given compound and wavelength), pathlength ℓ, and concentration c. When only pathlength changes from 1.0 cm to 2.0 cm while keeping ε and c constant, absorbance doubles: A₂ = ε(2ℓ)c = 2(εℓc) = 2A₁. This makes physical sense - light travels through twice as much absorbing solution, encountering twice as many molecules. Answer C correctly predicts doubling because absorbance is proportional to pathlength at fixed concentration. Answer D incorrectly suggests a quadratic relationship - this confusion may arise from intensity relationships but doesn't apply to absorbance. To evaluate spectrophotometry predictions, identify which Beer-Lambert variables change and apply the direct proportionality A ∝ ℓ when ε and c are constant.
A researcher measures the rate of a simple acid-catalyzed hydrolysis in water and proposes the rate law $\text{rate}=k\text{H}^+S$. Two buffered solutions at 25°C contain the same substrate concentration $S$ but different pH values: Solution X has pH 3.0 and Solution Y has pH 4.0. Assuming buffer components do not otherwise affect the reaction, which prediction is most consistent with the proposed rate law for the ratio $\text{rate}_X/\text{rate}_Y$?
$\text{rate}_X/\text{rate}_Y = 1$, because pH affects equilibrium but not reaction rate.
$\text{rate}_X/\text{rate}_Y = 10$, because $[\text{H}^+]$ is 10-fold higher at pH 3 than at pH 4.
$\text{rate}_X/\text{rate}_Y = 1/10$, because lower pH means fewer hydroxide ions to drive hydrolysis.
$\text{rate}_X/\text{rate}_Y = 2$, because a 1-unit pH change doubles $[\text{H}^+]$.
Explanation
This question tests the ability to evaluate predictions about pH effects on acid-catalyzed reaction rates. The key principle is that for reactions with rate = k[H+][S], the rate is directly proportional to hydrogen ion concentration. Since pH = -log[H+], a one-unit pH decrease represents a 10-fold increase in [H+]: at pH 3.0, [H+] = 10⁻³ M, while at pH 4.0, [H+] = 10⁻⁴ M. With identical substrate concentrations, the rate ratio equals the [H+] ratio: rateX/rateY = (10⁻³)/(10⁻⁴) = 10. Answer A correctly predicts a 10-fold ratio because [H+] is 10-fold higher at pH 3 than pH 4. Answer C incorrectly suggests only doubling - this misunderstands the logarithmic pH scale where each unit represents a 10-fold change. To evaluate pH-dependent rate predictions, convert pH differences to [H+] ratios using the 10-fold rule per pH unit, then apply the rate law proportionality.
A pulse of monochromatic light (wavelength $\lambda=500$ nm) is directed at a thin metal surface in vacuum to test the photoelectric effect. The measured stopping potential is $V_s=0.20$ V. Using $K_{max}=eV_s$ and photon energy $E=hc/\lambda$, the work function is estimated by $\phi=E-K_{max}$. Constants: $h=6.63\times10^{-34}$ J·s, $c=3.00\times10^8$ m/s, $e=1.60\times10^{-19}$ C. If the wavelength is decreased to 400 nm with all else unchanged, which prediction is most consistent with the model for the stopping potential?
It decreases, because shorter wavelength photons have less energy and eject slower electrons.
It is unchanged, because stopping potential depends only on the metal’s work function.
It increases, because photon energy increases as $\lambda$ decreases, increasing $K_{max}$.
It becomes negative, because higher photon energy reverses electron flow direction.
Explanation
This question tests the ability to evaluate predictions about the photoelectric effect using Einstein's model. The key principle is that photon energy E = hc/λ increases as wavelength decreases, and the maximum kinetic energy of ejected electrons equals photon energy minus work function: Kmax = E - φ = eVs. When wavelength decreases from 500 nm to 400 nm, photon energy increases from 2.48 eV to 3.10 eV (using E = 1240 eV·nm/λ). Since the work function φ remains constant for the same metal, the increased photon energy produces higher Kmax and thus higher stopping potential Vs. Answer B correctly predicts increased stopping potential because photon energy increases as λ decreases. Answer A incorrectly claims shorter wavelengths have less energy - this reverses the E ∝ 1/λ relationship. To evaluate photoelectric predictions, remember that decreasing wavelength means increasing photon energy, which increases the maximum kinetic energy and stopping potential for the same metal.
A team studies diffusion of a neutral solute across a thin membrane. They keep membrane thickness $\Delta x$ constant and measure steady-state flux $J$ while changing the concentration difference $\Delta C$ across the membrane.
Given: Fick’s first law $J = -D,\Delta C/\Delta x$; $D$ is constant over the tested range.
Which explanation is most plausible if a plot of $|J|$ vs. $\Delta C$ is linear through the origin?
Diffusion is driven by pressure gradients, not concentration gradients
The solute is actively transported, producing proportional flux at steady state
The system follows Fickian diffusion with constant $D$ under these conditions
Membrane thickness increases with $\Delta C$, canceling changes in flux
Explanation
This question tests the ability to analyze and evaluate explanations for diffusion behavior using Fick's first law. The observation is that flux (J) varies linearly with concentration difference (ΔC), passing through the origin. According to Fick's first law, J = -D(ΔC/Δx), which predicts exactly this linear relationship when D and Δx are constant. Choice A correctly identifies this as Fickian diffusion with constant diffusion coefficient. Choice D incorrectly invokes active transport, which would not necessarily produce a linear relationship through the origin and contradicts the passive diffusion context. To evaluate diffusion explanations, check whether the proposed mechanism matches the mathematical relationship observed and whether assumptions (like constant D) are reasonable.
A researcher proposes that increasing temperature will increase the rate of an elementary reaction because a larger fraction of molecules exceed the activation energy $E_a$. Two trials are run with identical initial concentrations, but Trial 2 is at higher temperature.
Given: Arrhenius form $k = A e^{-E_a/(RT)}$; $E_a>0$.
Which prediction is most consistent with this explanation?
Both trials have identical $k$ because $A$ is constant
Trial 2 has a larger $k$ only if the reaction is endothermic
Trial 2 has a smaller rate constant $k$ because molecules move too quickly to react
Trial 2 has a larger rate constant $k$ and a faster initial rate
Explanation
This question tests the ability to analyze and evaluate predictions based on the Arrhenius equation for temperature effects on reaction rates. The Arrhenius equation k = A·exp(-Ea/RT) shows that rate constant k increases with temperature because the exponential term becomes less negative. At higher temperature, a larger fraction of molecules have sufficient energy to overcome the activation barrier, increasing both k and the initial reaction rate. Choice A correctly predicts both effects, while choice B incorrectly suggests k decreases with temperature. To evaluate kinetic predictions, verify that higher temperature always increases k for elementary reactions with positive activation energy, regardless of whether the reaction is endothermic or exothermic.
A student claims that doubling the distance between two point charges will double the electrostatic force between them. The setup uses charges $q_1$ and $q_2$ held fixed while separation changes from $r$ to $2r$.
Given: Coulomb’s law $F = k\frac{|q_1q_2|}{r^2}$.
Based on the law, which evaluation is most plausible?
The force is unchanged because the charges are unchanged
The force doubles because $F\propto r$
The force halves because $F\propto 1/r$
The force becomes one-fourth because $F\propto 1/r^2$
Explanation
This question tests the ability to analyze and evaluate claims about electrostatic forces using Coulomb's law. The student's claim that doubling distance doubles force contradicts Coulomb's law F = k|q₁q₂|/r², which shows force varies inversely with the square of distance. When distance doubles from r to 2r, force becomes F' = k|q₁q₂|/(2r)² = F/4, decreasing to one-fourth the original value. Choice C correctly identifies this inverse square relationship, while the student's claim would require a direct proportionality (F ∝ r). When evaluating force laws, verify whether the proposed relationship matches the established physical law, particularly noting whether relationships are direct, inverse, or involve powers.
A metal wire of length $L$ and cross-sectional area $A$ is used as a sensor. The lab increases the wire temperature while keeping its geometry fixed.
Given: for a typical metal, resistivity $\rho$ increases with temperature; resistance $R = \rho L/A$.
Which prediction is most consistent with these principles?
Resistance increases because $\rho$ increases with temperature
Resistance increases only if the wire’s mass increases
Resistance is unchanged because $L$ and $A$ are constant
Resistance decreases because higher temperature increases electron speed
Explanation
This question tests the ability to analyze and evaluate predictions about temperature effects on electrical resistance. For metals, resistivity ρ typically increases with temperature due to increased electron-phonon scattering. Since resistance R = ρL/A and geometry (L, A) is held constant, resistance increases proportionally with resistivity. Choice B correctly predicts this increase, while choice A incorrectly suggests resistance decreases with temperature in metals. Choice C incorrectly assumes resistance depends only on geometry, ignoring the temperature dependence of resistivity. When evaluating resistance predictions, consider both geometric factors and material properties like temperature-dependent resistivity.