Mass Material Temperature - Middle School Physical Science
Card 1 of 25
Which option warms more for the same $Q$: material with $c=1$ or $c=4$ (same mass)?
Which option warms more for the same $Q$: material with $c=1$ or $c=4$ (same mass)?
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$c=1$ warms more (larger $\Delta T$). Lower specific heat gives larger $\Delta T$ when $Q$ and $m$ are constant.
$c=1$ warms more (larger $\Delta T$). Lower specific heat gives larger $\Delta T$ when $Q$ and $m$ are constant.
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Identify which warms more if both get $Q=300,J$: A has $m=50,g,c=2$; B has $m=150,g,c=2$.
Identify which warms more if both get $Q=300,J$: A has $m=50,g,c=2$; B has $m=150,g,c=2$.
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Sample A warms more (larger $\Delta T$). A: $\Delta T = \frac{300}{100} = 3°C$; B: $\Delta T = \frac{300}{300} = 1°C$
Sample A warms more (larger $\Delta T$). A: $\Delta T = \frac{300}{100} = 3°C$; B: $\Delta T = \frac{300}{300} = 1°C$
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What is the correct evidence-based claim if two samples absorb the same $Q$ but one warms less?
What is the correct evidence-based claim if two samples absorb the same $Q$ but one warms less?
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The sample has greater $m$ and/or greater $c$. Smaller $\Delta T$ with same $Q$ means larger denominator in $\frac{Q}{mc}$.
The sample has greater $m$ and/or greater $c$. Smaller $\Delta T$ with same $Q$ means larger denominator in $\frac{Q}{mc}$.
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Identify the material type that typically changes temperature least: metal or water (same $m$ and $Q$).
Identify the material type that typically changes temperature least: metal or water (same $m$ and $Q$).
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Water changes temperature least (higher $c$). Water has $c \approx 4.2,\frac{J}{g\cdot°C}$, much higher than metals.
Water changes temperature least (higher $c$). Water has $c \approx 4.2,\frac{J}{g\cdot°C}$, much higher than metals.
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What is the correct claim about metals compared with water when heated equally (same $m$ and $Q$)?
What is the correct claim about metals compared with water when heated equally (same $m$ and $Q$)?
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Metals usually have larger $\Delta T$ (lower $c$). Metals have low $c$ values, so $\Delta T = \frac{Q}{mc}$ is larger.
Metals usually have larger $\Delta T$ (lower $c$). Metals have low $c$ values, so $\Delta T = \frac{Q}{mc}$ is larger.
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Identify which warms more if both get $Q=300,J$: A has $m=100,g,c=1$; B has $m=100,g,c=3$.
Identify which warms more if both get $Q=300,J$: A has $m=100,g,c=1$; B has $m=100,g,c=3$.
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Sample A warms more (larger $\Delta T$). A: $\Delta T = \frac{300}{100} = 3°C$; B: $\Delta T = \frac{300}{300} = 1°C$
Sample A warms more (larger $\Delta T$). A: $\Delta T = \frac{300}{100} = 3°C$; B: $\Delta T = \frac{300}{300} = 1°C$
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Find $Q$ if $m=100,g$, $c=4,\frac{J}{g\cdot ^\circ C}$, and $\Delta T=3,^\circ C$.
Find $Q$ if $m=100,g$, $c=4,\frac{J}{g\cdot ^\circ C}$, and $\Delta T=3,^\circ C$.
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$Q = 1200,J$. $Q = 100 \times 4 \times 3 = 1200,J$
$Q = 1200,J$. $Q = 100 \times 4 \times 3 = 1200,J$
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Find $\Delta T$ if $Q=200,J$, $m=50,g$, and $c=2,\frac{J}{g\cdot ^\circ C}$.
Find $\Delta T$ if $Q=200,J$, $m=50,g$, and $c=2,\frac{J}{g\cdot ^\circ C}$.
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$\Delta T = 2,^\circ C$. $\Delta T = \frac{200}{50 \times 2} = \frac{200}{100} = 2$
$\Delta T = 2,^\circ C$. $\Delta T = \frac{200}{50 \times 2} = \frac{200}{100} = 2$
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Choose the correct proportionality for fixed $Q$ and fixed $m$: $\Delta T \propto c$ or $\Delta T \propto \frac{1}{c}$?
Choose the correct proportionality for fixed $Q$ and fixed $m$: $\Delta T \propto c$ or $\Delta T \propto \frac{1}{c}$?
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$\Delta T \propto \frac{1}{c}$. Temperature change is inversely proportional to specific heat.
$\Delta T \propto \frac{1}{c}$. Temperature change is inversely proportional to specific heat.
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Choose the correct proportionality for fixed $Q$ and fixed $c$: $\Delta T \propto m$ or $\Delta T \propto \frac{1}{m}$?
Choose the correct proportionality for fixed $Q$ and fixed $c$: $\Delta T \propto m$ or $\Delta T \propto \frac{1}{m}$?
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$\Delta T \propto \frac{1}{m}$. Temperature change is inversely proportional to mass.
$\Delta T \propto \frac{1}{m}$. Temperature change is inversely proportional to mass.
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Which option warms more for the same $Q$: $m=100,g$ or $m=200,g$ of the same material?
Which option warms more for the same $Q$: $m=100,g$ or $m=200,g$ of the same material?
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$100,g$ warms more (larger $\Delta T$). Smaller mass gives larger $\Delta T$ when $Q$ and $c$ are constant.
$100,g$ warms more (larger $\Delta T$). Smaller mass gives larger $\Delta T$ when $Q$ and $c$ are constant.
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Identify which sample has the greater mass if both have same material and $Q$ but A has smaller $\Delta T$ than B.
Identify which sample has the greater mass if both have same material and $Q$ but A has smaller $\Delta T$ than B.
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Sample A has the greater mass ($m$). Same material and $Q$ but smaller $\Delta T$ means larger $m$ in denominator.
Sample A has the greater mass ($m$). Same material and $Q$ but smaller $\Delta T$ means larger $m$ in denominator.
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What is the relationship between mass and temperature change when the same heat energy is added?
What is the relationship between mass and temperature change when the same heat energy is added?
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Greater mass causes a smaller temperature change ($\Delta T$). More mass means heat energy is distributed among more particles.
Greater mass causes a smaller temperature change ($\Delta T$). More mass means heat energy is distributed among more particles.
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What is the relationship between specific heat capacity and temperature change for the same heat added?
What is the relationship between specific heat capacity and temperature change for the same heat added?
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Higher specific heat ($c$) causes a smaller $\Delta T$. Materials with high $c$ need more energy per degree of warming.
Higher specific heat ($c$) causes a smaller $\Delta T$. Materials with high $c$ need more energy per degree of warming.
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What formula relates heat energy, mass, specific heat, and temperature change?
What formula relates heat energy, mass, specific heat, and temperature change?
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$Q = mc\Delta T$. Fundamental equation relating heat to temperature change.
$Q = mc\Delta T$. Fundamental equation relating heat to temperature change.
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Which option has the smaller $\Delta T$ for the same $Q$: low $c$ material or high $c$ material?
Which option has the smaller $\Delta T$ for the same $Q$: low $c$ material or high $c$ material?
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High $c$ material has the smaller $\Delta T$. From $\Delta T = \frac{Q}{mc}$, larger $c$ gives smaller $\Delta T$.
High $c$ material has the smaller $\Delta T$. From $\Delta T = \frac{Q}{mc}$, larger $c$ gives smaller $\Delta T$.
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Identify which sample has the greater specific heat if both have same $m$ and $Q$ but A has smaller $\Delta T$ than B.
Identify which sample has the greater specific heat if both have same $m$ and $Q$ but A has smaller $\Delta T$ than B.
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Sample A has the greater specific heat ($c$). Same $m$ and $Q$ but smaller $\Delta T$ means larger $c$ in denominator.
Sample A has the greater specific heat ($c$). Same $m$ and $Q$ but smaller $\Delta T$ means larger $c$ in denominator.
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Which option has the smaller $\Delta T$ for the same $Q$: small mass or large mass?
Which option has the smaller $\Delta T$ for the same $Q$: small mass or large mass?
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Large mass has the smaller $\Delta T$. From $\Delta T = \frac{Q}{mc}$, larger $m$ gives smaller $\Delta T$.
Large mass has the smaller $\Delta T$. From $\Delta T = \frac{Q}{mc}$, larger $m$ gives smaller $\Delta T$.
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Find $m$ if $q=1000,\text{J}$, $c=250,\text{J/(kg}\cdot^{\circ}\text{C)}$, and $\Delta T=4,^{\circ}\text{C}$.
Find $m$ if $q=1000,\text{J}$, $c=250,\text{J/(kg}\cdot^{\circ}\text{C)}$, and $\Delta T=4,^{\circ}\text{C}$.
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$m = 1,\text{kg}$. Using $m = \frac{q}{c\Delta T} = \frac{1000}{250 \times 4} = 1$.
$m = 1,\text{kg}$. Using $m = \frac{q}{c\Delta T} = \frac{1000}{250 \times 4} = 1$.
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Find $q$ if $m=0.5,\text{kg}$, $c=400,\text{J/(kg}\cdot^{\circ}\text{C)}$, and $\Delta T=3,^{\circ}\text{C}$.
Find $q$ if $m=0.5,\text{kg}$, $c=400,\text{J/(kg}\cdot^{\circ}\text{C)}$, and $\Delta T=3,^{\circ}\text{C}$.
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$q = 600,\text{J}$. Using $q = mc\Delta T = 0.5 \times 400 \times 3 = 600$.
$q = 600,\text{J}$. Using $q = mc\Delta T = 0.5 \times 400 \times 3 = 600$.
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Find $\Delta T$ if $q=600,\text{J}$, $m=2,\text{kg}$, and $c=300,\text{J/(kg}\cdot^{\circ}\text{C)}$.
Find $\Delta T$ if $q=600,\text{J}$, $m=2,\text{kg}$, and $c=300,\text{J/(kg}\cdot^{\circ}\text{C)}$.
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$\Delta T = 1,^{\circ}\text{C}$. Using $\Delta T = \frac{q}{mc} = \frac{600}{2 \times 300} = 1$.
$\Delta T = 1,^{\circ}\text{C}$. Using $\Delta T = \frac{q}{mc} = \frac{600}{2 \times 300} = 1$.
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Choose the correct comparison: for fixed $q$ and $m$, how does $\Delta T$ change as $c$ increases?
Choose the correct comparison: for fixed $q$ and $m$, how does $\Delta T$ change as $c$ increases?
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$\Delta T$ decreases as $c$ increases ($\Delta T \propto \frac{1}{c}$). Temperature change is inversely proportional to specific heat.
$\Delta T$ decreases as $c$ increases ($\Delta T \propto \frac{1}{c}$). Temperature change is inversely proportional to specific heat.
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Choose the correct comparison: for fixed $q$ and $c$, how does $\Delta T$ change as mass increases?
Choose the correct comparison: for fixed $q$ and $c$, how does $\Delta T$ change as mass increases?
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$\Delta T$ decreases as $m$ increases ($\Delta T \propto \frac{1}{m}$). Temperature change is inversely proportional to mass.
$\Delta T$ decreases as $m$ increases ($\Delta T \propto \frac{1}{m}$). Temperature change is inversely proportional to mass.
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Identify which has the larger temperature change: a material with low $c$ or high $c$ given equal $q$ and $m$.
Identify which has the larger temperature change: a material with low $c$ or high $c$ given equal $q$ and $m$.
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The material with lower $c$ has the larger $\Delta T$. From $\Delta T = \frac{q}{mc}$, smaller $c$ gives larger temperature change.
The material with lower $c$ has the larger $\Delta T$. From $\Delta T = \frac{q}{mc}$, smaller $c$ gives larger temperature change.
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Identify which has the larger temperature change: $1,\text{kg}$ or $2,\text{kg}$ of the same material given equal $q$.
Identify which has the larger temperature change: $1,\text{kg}$ or $2,\text{kg}$ of the same material given equal $q$.
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$1,\text{kg}$ has the larger $\Delta T$. From $\Delta T = \frac{q}{mc}$, smaller mass gives larger temperature change.
$1,\text{kg}$ has the larger $\Delta T$. From $\Delta T = \frac{q}{mc}$, smaller mass gives larger temperature change.
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