Understanding Magnetic Fields - Physics

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Question

A current of runs through a straight wire. If the resulting magnetic field is , what is the radius of the field?

$\small \mu_0=4\pi*10^{-7}\frac{T\cdot m}{A}$

Answer

Ampere's law states:

$B=\frac{\mu_0 I}{2\pi r}$ .

In other words, the magnetic field (), is equal to a constant ( $\mu_0$ ) times the current () divided by the circumference of the magnetic field it is creating.

We are given the current, the constant, and the magnetic field strength. Using these values, we can solve for the magnetic field radius.

$B=\frac{\mu_0 I}{2\pi r}$

$150T=\frac{(4\pi10^{-7}\frac{T\cdot m}{A})(6.610^8A)}{2\pi r}$

Notice that the $\pi$ cancels out.

$150T=\frac{(410^{-7}\frac{T\cdot m}{A}) (6.610^8A)}{2r}$

$150T=\frac{264T\cdot m}{2r}$

$150T=\frac{132T\cdot m}{r}$

$r=\frac{132T\cdot m}{150T}$

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Question

A current of runs through a straight wire. If the resulting magnetic field is , what is the radius of the field?

$\small \mu_0=4\pi*10^{-7}\frac{T\cdot m}{A}$

Answer

Ampere's law states:

$B=\frac{\mu_0 I}{2\pi r}$ .

In other words, the magnetic field (), is equal to a constant ( $\mu_0$ ) times the current () divided by the circumference of the magnetic field it is creating.

We are given the current, the constant, and the magnetic field strength. Using these values, we can solve for the magnetic field radius.

$B=\frac{\mu_0 I}{2\pi r}$

$150T=\frac{(4\pi10^{-7}\frac{T\cdot m}{A})(6.610^8A)}{2\pi r}$

Notice that the $\pi$ cancels out.

$150T=\frac{(410^{-7}\frac{T\cdot m}{A}) (6.610^8A)}{2r}$

$150T=\frac{264T\cdot m}{2r}$

$150T=\frac{132T\cdot m}{r}$

$r=\frac{132T\cdot m}{150T}$

Compare your answer with the correct one above

Question

A current of runs through a straight wire. If the resulting magnetic field is , what is the radius of the field?

$\small \mu_0=4\pi*10^{-7}\frac{T\cdot m}{A}$

Answer

Ampere's law states:

$B=\frac{\mu_0 I}{2\pi r}$ .

In other words, the magnetic field (), is equal to a constant ( $\mu_0$ ) times the current () divided by the circumference of the magnetic field it is creating.

We are given the current, the constant, and the magnetic field strength. Using these values, we can solve for the magnetic field radius.

$B=\frac{\mu_0 I}{2\pi r}$

$150T=\frac{(4\pi10^{-7}\frac{T\cdot m}{A})(6.610^8A)}{2\pi r}$

Notice that the $\pi$ cancels out.

$150T=\frac{(410^{-7}\frac{T\cdot m}{A}) (6.610^8A)}{2r}$

$150T=\frac{264T\cdot m}{2r}$

$150T=\frac{132T\cdot m}{r}$

$r=\frac{132T\cdot m}{150T}$

Compare your answer with the correct one above

Question

A current of runs through a straight wire. If the resulting magnetic field is , what is the radius of the field?

$\small \mu_0=4\pi*10^{-7}\frac{T\cdot m}{A}$

Answer

Ampere's law states:

$B=\frac{\mu_0 I}{2\pi r}$ .

In other words, the magnetic field (), is equal to a constant ( $\mu_0$ ) times the current () divided by the circumference of the magnetic field it is creating.

We are given the current, the constant, and the magnetic field strength. Using these values, we can solve for the magnetic field radius.

$B=\frac{\mu_0 I}{2\pi r}$

$150T=\frac{(4\pi10^{-7}\frac{T\cdot m}{A})(6.610^8A)}{2\pi r}$

Notice that the $\pi$ cancels out.

$150T=\frac{(410^{-7}\frac{T\cdot m}{A}) (6.610^8A)}{2r}$

$150T=\frac{264T\cdot m}{2r}$

$150T=\frac{132T\cdot m}{r}$

$r=\frac{132T\cdot m}{150T}$

Compare your answer with the correct one above

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