Volume of a Pyramid - Pre-Algebra

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A pyramid has height 4 feet. Its base is a square with sidelength 3 feet. Give its volume in cubic inches.

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Convert each measurement from inches to feet by multiplying it by 12:

Height: 4 feet = $4 \times 12 = 48$ inches

Sidelength of the base: 3 feet = $3 \times 12 = 36$ inches

The volume of a pyramid is

$V = $\frac{1}{3}$ Bh$

Since the base is a square, we can replace $B = $s^{2}$$ :

$V = $\frac{1}{3}$ s ^{2}h$

Substitute

$V = $\frac{1}{3}$ \cdot 36 ^{2}\cdot 48$

The pyramid has volume 20,736 cubic inches.

The height of a right pyramid is feet. Its base is a square with sidelength feet. Give its volume in cubic inches.

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Convert each of the measurements from feet to inches by multiplying by .

Height: $2 \times 12 = 24$ inches

Sidelength of base: $3 \times 12 = 36$ inches

The base of the pyramid has area

$B = $s^{2}$ = $36^{2}$ = 1,296$ square inches.

Substitute into the volume formula:

$V = \frac {1}{3} Bh$

$V = \frac {1}{3} \cdot 1,296 \cdot 24 =10,368$ cubic inches

The height of a right pyramid and the sidelength of its square base are equal. The perimeter of the base is 3 feet. Give its volume in cubic inches.

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The perimeter of the square base, feet, is equivalent to $3 \times 12 = 36$ inches; divide by to get the sidelength of the base - and the height: $36 \div 4 = 9$ inches.

The area of the base is therefore $B = $s^{2}$ = $9^{2}$ = 81$ square inches.

In the formula for the volume of a pyramid, substitute :

$V = $\frac{1}{3}$ Bh = $\frac{1}{3}$\cdot 81 \cdot 9 = 243$ cubic inches.

What is the volume of a pyramid with the following measurements?

$length=7; width=6;height=9;slant\ length=11$

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The volume of a pyramid can be determined using the following equation:

$V=\frac{1}{3}$lwh=\frac{1}{3}$(7)(6)(9)=126$

Principal O'Shaughnessy has a paperweight in the shape of a pyramid with a square base. If one side of the base has a length of 4cm and the height of the paperweight is 6cm, what is the volume of the paperweight?

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We begin by recalling the volume of a pyramid.

$V=\frac{1}{3}$Ah$

where is the area of the base and is the height.

Since the base is a square, we can find the area by squaring the length of one of the sides.

Given the height is 6cm, we can now calculate the volume.

$V=\frac{1}{3}$(16)(6)=32$

Since all of the measurements were in centimeters, our volume will be in cubic centimeters.

Therefore, the volume of Principal O'Shaughnessy's paperweight is .

The volume of a square pyramid is $162 $m^{3}$$ . If a side of the square base measures . What is the height of the pyramid?

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The formula for the volume of a pyramid is $\frac{\left( B \times h\right)}{3}$ , where is the area of the base and is the height.

Using this formula,

= Area of the base, which is nothing but area of square with side . $9m \times 9m = 81 $m^{2}$$

Now, when simplified, you get .

Hence, the height of the pyramid is .

The pyramid has a length, width, and height of respectively. What is the volume of the pyramid?

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Write the formula for the volume of a pyramid.

$V=\frac{1}{3}$ (L\times W\times H)$

Substitute the dimensions and solve.

$V=\frac{1}{3}$ (2\times 4\times 6) = $\frac{1}{3}$(48)=16$

If the base area of the pyramid is , and the height is , what is the volume of the pyramid?

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Write the volume formula for the pyramid.

$V=\frac{1}{3}$ (L\times W\times H)$

The base area is represented by $L\times W$ .

Substitute the knowns into the formula.

$V=\frac{1}{3}$ (2\times 3) = $\frac{1}{3}$ (6) =2$

Find the volume of a pyramid with a length of 4, width of 7, and a height of 3.

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Write the formula to find the area of a pyramid.

$V=\frac{1}{3}$ (L\times W \times H)$

Substitute the dimensions.

$V=\frac{1}{3}$ (4\times 7\times 3) = 28$

Find the volume of a pyramid if the length, base, and height are $\textup{10, 20, and 40,}$ respectively.

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Write the formula for the volume of a pyramid.

$V=\frac{1}{3}$ (LWH)$

Substitute the dimensions and solve for the volume.

$V=\frac{1}{3}$ (10)(20)(40) = $\frac{8000}{3}$$

Find the volume of a pyramid with a length of 2, width of 6, and a height of 9.

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Write the formula for the volume of a pyramid.

$V=\frac{1}{3}$ (\textup{ Length} \times\textup{ Width} \times\textup{ Height})$

Substitute the given length, width, and height.

$V=\frac{1}{3}$ (2\times6\times9)$

Rewrite the inside the parentheses as a factor of .

$V=\frac{1}{3}$ (2\times (3 \times 2)\times9)$

Cancel the fraction with the three and multiply the terms to get the volume.

$V=2\times 2\times 9 = 36$

Find the volume of a pyramid if the dimensions of the length, width, and height are , respectively.

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Write the volume formula for a pyramid.

$V=\frac{1}{3}$( \textup{Length} \times \textup{Width } \times \textup{Height})$

Plug in the dimensions.

$V=\frac{1}{3}$( 3\times5 \times 10)=\frac{3\times5 \times 10}{3}$$

Cancel out the three on the numerator and denominator.

$V=5\times 10$

Multiply.

Find the volume of a pyramid with a length of 6cm, a width that is half the length, and a height that is two times the length.

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The formula for volume of a pyramid is

$V =\frac{ l \cdot w \cdot h}{3}$$

where l is the length, w is the width, and h is the height. We know the length is 6cm. The width is half the length, so the width is 3cm. The height is two times the length, so the height is 12cm. Using this information, we substitute. We get

$V =\frac{ 6\text{cm}$ \cdot 3$\text{cm}$ \cdot 12$\text{cm}$}{3}$

$V =\frac{ $216}{3}$$\text{cm}$^3$=72 $$\text{cm}$^3$$

A pyramid has height 4 feet. Its base is a square with sidelength 3 feet. Give its volume in cubic inches.

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Convert each measurement from inches to feet by multiplying it by 12:

Height: 4 feet = $4 \times 12 = 48$ inches

Sidelength of the base: 3 feet = $3 \times 12 = 36$ inches

The volume of a pyramid is

$V = $\frac{1}{3}$ Bh$

Since the base is a square, we can replace $B = $s^{2}$$ :

$V = $\frac{1}{3}$ s ^{2}h$

Substitute

$V = $\frac{1}{3}$ \cdot 36 ^{2}\cdot 48$

The pyramid has volume 20,736 cubic inches.

The height of a right pyramid is feet. Its base is a square with sidelength feet. Give its volume in cubic inches.

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Convert each of the measurements from feet to inches by multiplying by .

Height: $2 \times 12 = 24$ inches

Sidelength of base: $3 \times 12 = 36$ inches

The base of the pyramid has area

$B = $s^{2}$ = $36^{2}$ = 1,296$ square inches.

Substitute into the volume formula:

$V = \frac {1}{3} Bh$

$V = \frac {1}{3} \cdot 1,296 \cdot 24 =10,368$ cubic inches

The height of a right pyramid and the sidelength of its square base are equal. The perimeter of the base is 3 feet. Give its volume in cubic inches.

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The perimeter of the square base, feet, is equivalent to $3 \times 12 = 36$ inches; divide by to get the sidelength of the base - and the height: $36 \div 4 = 9$ inches.

The area of the base is therefore $B = $s^{2}$ = $9^{2}$ = 81$ square inches.

In the formula for the volume of a pyramid, substitute :

$V = $\frac{1}{3}$ Bh = $\frac{1}{3}$\cdot 81 \cdot 9 = 243$ cubic inches.

What is the volume of a pyramid with the following measurements?

$length=7; width=6;height=9;slant\ length=11$

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The volume of a pyramid can be determined using the following equation:

$V=\frac{1}{3}$lwh=\frac{1}{3}$(7)(6)(9)=126$

Principal O'Shaughnessy has a paperweight in the shape of a pyramid with a square base. If one side of the base has a length of 4cm and the height of the paperweight is 6cm, what is the volume of the paperweight?

Tap to see back →

We begin by recalling the volume of a pyramid.

$V=\frac{1}{3}$Ah$

where is the area of the base and is the height.

Since the base is a square, we can find the area by squaring the length of one of the sides.

Given the height is 6cm, we can now calculate the volume.

$V=\frac{1}{3}$(16)(6)=32$

Since all of the measurements were in centimeters, our volume will be in cubic centimeters.

Therefore, the volume of Principal O'Shaughnessy's paperweight is .

The volume of a square pyramid is $162 $m^{3}$$ . If a side of the square base measures . What is the height of the pyramid?

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The formula for the volume of a pyramid is $\frac{\left( B \times h\right)}{3}$ , where is the area of the base and is the height.

Using this formula,

= Area of the base, which is nothing but area of square with side . $9m \times 9m = 81 $m^{2}$$

Now, when simplified, you get .

Hence, the height of the pyramid is .

The pyramid has a length, width, and height of respectively. What is the volume of the pyramid?

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Write the formula for the volume of a pyramid.

$V=\frac{1}{3}$ (L\times W\times H)$

Substitute the dimensions and solve.

$V=\frac{1}{3}$ (2\times 4\times 6) = $\frac{1}{3}$(48)=16$