Tangents To a Curve
Help Questions
Pre-Calculus › Tangents To a Curve
Find the slope of the line at the point
.
Explanation
First find the slope of the tangent to the line by taking the derivative.
Using the Exponential Rule we get the following,
.
Then plug 1 into the equation as 1 is the point to find the slope at.
.
Find the slope of the line at the point
.
Explanation
First find the slope of the tangent to the line by taking the derivative.
Using the Exponential Rule we get the following,
.
Then plug 1 into the equation as 1 is the point to find the slope at.
.
Consider the function . What is the slope of the line tangent to the graph at the point
?
Explanation
Calculate the derivative of by using the derivative rules. The derivative function determines the slope at any point of the original function.
The derivative is:
With the given point ,
. Substitute this value to the derivative function to determine the slope at that point.
The slope of the tangent line that intersects point is
.
Find the slope of the tangent line of the function at the given value
at
.
Explanation
To find the slope of the tangent line of the function at the given value, evaluate the first derivative for the given value.
The first derivative is
and for this function
and plugging in the specific x value we get,
So the slope is
.
Find the slope of the following expression at the point
.
Explanation
One way of finding the slope at a given point is by finding the derivative. In this case, we can take the derivative of y with respect to x, and plug in the desired value for x.
Using the exponential rule we get the following derivative,
.
Plugging in x=2 from the point 2,3 gives us the final slope,
Thus our slope at the specific point is .
Note that in this case, using the y coordinate was not necessary.
Find the slope of the tangent line of the function at the given value
at
.
Explanation
To find the slope of the tangent line of the function at the given value, evaluate the first derivative for the given value.
The first derivative is
and for this function
and plugging in the specific x value we get,
So the slope is
.
Find the slope of the following expression at the point
.
Explanation
One way of finding the slope at a given point is by finding the derivative. In this case, we can take the derivative of y with respect to x, and plug in the desired value for x.
Using the exponential rule we get the following derivative,
.
Plugging in x=2 from the point 2,3 gives us the final slope,
Thus our slope at the specific point is .
Note that in this case, using the y coordinate was not necessary.
Consider the function . What is the slope of the line tangent to the graph at the point
?
Explanation
Calculate the derivative of by using the derivative rules. The derivative function determines the slope at any point of the original function.
The derivative is:
With the given point ,
. Substitute this value to the derivative function to determine the slope at that point.
The slope of the tangent line that intersects point is
.
Write the equation for the tangent line to at
.
Explanation
First, find the slope of the tangent line by taking the first derivative:
To finish determining the slope, plug in the x-value, 2:
the slope is 6
Now find the y-coordinate where x is 2 by plugging in 2 to the original equation:
To write the equation, start in point-slope form and then use algebra to get it into slope-intercept like the answer choices.
distribute the 6
add 8 to both sides
Find the equation of line tangent to the function
at .
Explanation
The equation of the tangent line at depends on the derivative at that point and the function value.
The derivative at that point of is
using the Power Rule
which means
The derivative is zero, so the tangent line will be horizontal.
It intersects it at since
, so that line is
.