How to find the amount of rational numbers between two numbers - PSAT Math
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Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
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The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is 
. For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because 
divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with 
and 4. If we give a 5 to one and a 2 to the other, we end up with 
and 
.
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Tap to see back →
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is . For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with and 4. If we give a 5 to one and a 2 to the other, we end up with and .
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Tap to see back →
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is . For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with and 4. If we give a 5 to one and a 2 to the other, we end up with and .
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Tap to see back →
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is . For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with and 4. If we give a 5 to one and a 2 to the other, we end up with and .
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Tap to see back →
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is . For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with and 4. If we give a 5 to one and a 2 to the other, we end up with and .
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Tap to see back →
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is . For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with and 4. If we give a 5 to one and a 2 to the other, we end up with and .
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Two numbers have a greatest common divisor of 4 and a least common multiple of 40. How many different pairs of numbers are there that satisfy these properties?
Tap to see back →
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is . For a number to divide 40, it must therefore be composed of (at most) three 2's and one 5. Because divides both numbers, we also know that they must both have at least two 2's.
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with and 4. If we give a 5 to one and a 2 to the other, we end up with and .
Thus our two pairs are:
4,40 and 8,20
The greatest common divisor is 4. This means that both numbers must be divisible by 4. Furthermore, the least common multiple is 40, so both must divide 40.
The prime factorization of 40 is
Now each number will have either two or three 2's and zero or one 5's. However, we also know that they can't both have three 2's, (since then the greatest common divisor would have three 2's as well). Similarly, only one can have a 5.
In essence, our problem becomes one of choice. We have 2 places with value 4. We choose to give a 5 to one of the two. We then give a 2 to one of the two. If we give a 5 and a 2 to the same side, we end up with
Thus our two pairs are:
4,40 and 8,20