How to find the next term in an arithmetic sequence - PSAT Math
Card 0 of 28
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
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The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
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The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
Tap to see back →
Each term in the sequence is one less than twice the previous term.
So, 
Each term in the sequence is one less than twice the previous term.
So,
Find the 
term in the sequence
Find the
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Notice that in the sequence
each term increases by 
.
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The 
term is 
The 
term is 
The 
term is 
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the 
term.
Notice that in the sequence
each term increases by
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The
The
The
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
Tap to see back →
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
Tap to see back →
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
Tap to see back →
Each term in the sequence is one less than twice the previous term.
So,
Each term in the sequence is one less than twice the previous term.
So,
Find the term in the sequence
Find the
Tap to see back →
Notice that in the sequence
each term increases by .
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The term is
The term is
The term is
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the term.
Notice that in the sequence
each term increases by
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The
The
The
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
Tap to see back →
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
Tap to see back →
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
Tap to see back →
Each term in the sequence is one less than twice the previous term.
So,
Each term in the sequence is one less than twice the previous term.
So,
Find the term in the sequence
Find the
Tap to see back →
Notice that in the sequence
each term increases by .
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The term is
The term is
The term is
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the term.
Notice that in the sequence
each term increases by
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The
The
The
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
Tap to see back →
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
Tap to see back →
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
Tap to see back →
Each term in the sequence is one less than twice the previous term.
So,
Each term in the sequence is one less than twice the previous term.
So,
Find the term in the sequence
Find the
Tap to see back →
Notice that in the sequence
each term increases by .
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The term is
The term is
The term is
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the term.
Notice that in the sequence
each term increases by
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The
The
The
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
A sequence of numbers is as follows:
What is the sum of the first seven numbers in the sequence?
Tap to see back →
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
The pattern of the sequence is (x+1) * 2.
We have the first 5 terms, so we need terms 6 and 7:
(78+1) * 2 = 158
(158+1) * 2 = 318
3 + 8 + 18 +38 + 78 + 158 + 318 = 621
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
What is the next number in the following series: 0, 3, 8, 15, 24 . . . ?
Tap to see back →
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
The series is defined by n2 – 1 starting at n = 1. The sixth number in the series then equal to 62 – 1 = 35.
Tap to see back →
Each term in the sequence is one less than twice the previous term.
So,
Each term in the sequence is one less than twice the previous term.
So,
Find the term in the sequence
Find the
Tap to see back →
Notice that in the sequence
each term increases by .
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The term is
The term is
The term is
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the term.
Notice that in the sequence
each term increases by
It is always good strategy when attempting to find a pattern in a sequence to examine the difference between each term.
We continue the pattern to find:
The
The
The
It is useful to note that the sequence is defined by,
where n is the number of any one term.
We can solve
to find the