How to find the solution for a system of equations - PSAT Math
Card 0 of 98
Solve for
.


Solve for .
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For the second equation, solve for
in terms of
.


Plug this value of y into the first equation.



For the second equation, solve for in terms of
.
Plug this value of y into the first equation.


Solve the system for
and
.
Solve the system for and
.
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The most simple method for solving systems of equations is to transform one of the equations so it allows for the canceling out of a variable. In this case, we can multiply
by
to get
.
Then, we can add
to this equation to yield
, so
.
We can plug that value into either of the original equations; for example,
.
So,
as well.
The most simple method for solving systems of equations is to transform one of the equations so it allows for the canceling out of a variable. In this case, we can multiply by
to get
.
Then, we can add to this equation to yield
, so
.
We can plug that value into either of the original equations; for example, .
So, as well.
Solve for
in the system of equations:


Solve for in the system of equations:
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In the second equation, you can substitute
for
from the first.







Now, substitute 2 for
in the first equation:




The solution is 
In the second equation, you can substitute for
from the first.
Now, substitute 2 for in the first equation:
The solution is
What is the solution to the following system of equations:


What is the solution to the following system of equations:
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By solving one equation for
, and replacing
in the other equation with that expression, you generate an equation of only 1 variable which can be readily solved.
By solving one equation for , and replacing
in the other equation with that expression, you generate an equation of only 1 variable which can be readily solved.
What is the sum of
and
for the following system of equations?


What is the sum of and
for the following system of equations?
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Add the equations together.



Put the terms together to see that
.
Substitute this value into one of the original equaitons and solve for
.




Now we know that
, thus we can find the sum of
and
.

Add the equations together.
Put the terms together to see that .
Substitute this value into one of the original equaitons and solve for .
Now we know that , thus we can find the sum of
and
.
Without drawing a graph of either equation, find the point where the two lines intersect.
Line 1 : 
Line 2 : 
Without drawing a graph of either equation, find the point where the two lines intersect.
Line 1 :
Line 2 :
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To find the point where these two lines intersect, set the equations equal to each other, such that
is substituted with the
side of the second equation. Solving this new equation for
will give the
-coordinate of the point of intersection.

Subtract
from both sides.


Divide both sides by 2.


Now substitute
into either equation to find the
-coordinate of the point of intersection.



With both coordinates, we know the point of intersection is
. One can plug in
for
and
for
in both equations to verify that this is correct.
To find the point where these two lines intersect, set the equations equal to each other, such that is substituted with the
side of the second equation. Solving this new equation for
will give the
-coordinate of the point of intersection.
Subtract from both sides.
Divide both sides by 2.
Now substitute into either equation to find the
-coordinate of the point of intersection.
With both coordinates, we know the point of intersection is . One can plug in
for
and
for
in both equations to verify that this is correct.
Give the solution to the system of equations below.


Give the solution to the system of equations below.
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Solve the second equation for
, allowing us to solve using the substitution method.


Substitute for
in the first equation, and solve for
.





Now, substitute for
in either equation; we will choose the second. This allows us to solve for
.




Now we can write the solution in the notation
, or
.
Solve the second equation for , allowing us to solve using the substitution method.
Substitute for in the first equation, and solve for
.
Now, substitute for in either equation; we will choose the second. This allows us to solve for
.
Now we can write the solution in the notation , or
.
Jeff, the barista at Moonbucks Coffee, is having a problem. He needs to make fifty pounds of Premium Blend coffee by mixing together some Kona beans, which cost $24 per pound, with some Ethiopian Delight beans, which cost $10 per pound. The Premium Blend coffee will cost $14.20 per pound. Also, the coffee will sell for the same price mixed as it would separately.
How many pounds of Kona beans will be in the mixture?
Jeff, the barista at Moonbucks Coffee, is having a problem. He needs to make fifty pounds of Premium Blend coffee by mixing together some Kona beans, which cost $24 per pound, with some Ethiopian Delight beans, which cost $10 per pound. The Premium Blend coffee will cost $14.20 per pound. Also, the coffee will sell for the same price mixed as it would separately.
How many pounds of Kona beans will be in the mixture?
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The number of pounds of coffee beans totals 50, so one of the equations would be
.
The total price of the Kona beans, is its unit price, $24 per pound, multiplied by its quantity,
pounds. This is
dollars. Similarly, the total price of the Ethiopian delight beans is
dollars, and the price of the mixture is
dollars. Add the prices of the Kona and Ethiopian Delight beans to get the price of the mixture:

We are trying to solve for
in the system


Multiply the second equation by
, then add to the first:





The mixture includes 15 pounds of Kona beans.
The number of pounds of coffee beans totals 50, so one of the equations would be
.
The total price of the Kona beans, is its unit price, $24 per pound, multiplied by its quantity, pounds. This is
dollars. Similarly, the total price of the Ethiopian delight beans is
dollars, and the price of the mixture is
dollars. Add the prices of the Kona and Ethiopian Delight beans to get the price of the mixture:
We are trying to solve for in the system
Multiply the second equation by , then add to the first:
The mixture includes 15 pounds of Kona beans.
If
and
, what is the value of
?
If and
, what is the value of
?
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To solve this problem, you must first solve the system of equations for both
and
, then plug the values of
and
into the final equation.
In order to solve a system of equations, you must add the equations in a way that gets rid of one of the variables so you can solve for one variable, then for the other. One example of how to do so is as follows:
Take the equations. Multiply the first equation by two so that there is
(this will cancel out the
in the second equation).

Add the equations:


Find the sum (notice that the variable
has disappeared entirely):

Solve for
.

Plug this value of
back into one of the original equations to solve for
:



Now, plug the values of
and
into the final expression:

The answer is
.
To solve this problem, you must first solve the system of equations for both and
, then plug the values of
and
into the final equation.
In order to solve a system of equations, you must add the equations in a way that gets rid of one of the variables so you can solve for one variable, then for the other. One example of how to do so is as follows:
Take the equations. Multiply the first equation by two so that there is (this will cancel out the
in the second equation).
Add the equations:
Find the sum (notice that the variable has disappeared entirely):
Solve for .
Plug this value of back into one of the original equations to solve for
:
Now, plug the values of and
into the final expression:
The answer is .


What is the solution of
that satisfies both equations?
What is the solution of that satisfies both equations?
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Reduce the second system by dividing by 3.
Second Equation:
We this by 3.


Then we subtract the first equation from our new equation.
First Equation:

First Equation - Second Equation:
Left Hand Side:

Right Hand Side:

Our result is:

Reduce the second system by dividing by 3.
Second Equation:
We this by 3.
Then we subtract the first equation from our new equation.
First Equation:
First Equation - Second Equation:
Left Hand Side:
Right Hand Side:
Our result is:


What is the solution of
for the systems of equations?
What is the solution of for the systems of equations?
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We add the two systems of equations:
For the Left Hand Side:

For the Right Hand Side:

So our resulting equation is:

Divide both sides by 10:
For the Left Hand Side:

For the Right Hand Side:

Our result is:

We add the two systems of equations:
For the Left Hand Side:
For the Right Hand Side:
So our resulting equation is:
Divide both sides by 10:
For the Left Hand Side:
For the Right Hand Side:
Our result is:


What is the solution of
for the two systems?
What is the solution of for the two systems?
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We first multiply the second equation by 4.
So our resulting equation is:


Then we subtract the first equation from the second new equation.
Left Hand Side:

Right Hand Side:

Resulting Equation:

We divide both sides by -15
Left Hand Side:

Right Hand Side:

Our result is:

We first multiply the second equation by 4.
So our resulting equation is:
Then we subtract the first equation from the second new equation.
Left Hand Side:
Right Hand Side:
Resulting Equation:
We divide both sides by -15
Left Hand Side:
Right Hand Side:
Our result is:


What is the solution of
for the two systems of equations?
What is the solution of for the two systems of equations?
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We first add both systems of equations.
Left Hand Side:

Right Hand Side:

Our resulting equation is:

We divide both sides by 3.
Left Hand Side:

Right Hand Side:

Our resulting equation is:

We first add both systems of equations.
Left Hand Side:
Right Hand Side:
Our resulting equation is:
We divide both sides by 3.
Left Hand Side:
Right Hand Side:
Our resulting equation is:
Find the solutions for the following set of equations:


Find the solutions for the following set of equations:
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If we multiply both sides of our bottom equation by
, we get
. We can now add our two equations, and eliminate
, leaving only one variable. When we add the equations, we get
. Therefore,
. Finally, we go back to either of our equations, and plug in
so we can solve for
.




If we multiply both sides of our bottom equation by , we get
. We can now add our two equations, and eliminate
, leaving only one variable. When we add the equations, we get
. Therefore,
. Finally, we go back to either of our equations, and plug in
so we can solve for
.
Solve for
.


Solve for .
Tap to see back →


For the second equation, solve for
in terms of
.


Plug this value of y into the first equation.



For the second equation, solve for in terms of
.
Plug this value of y into the first equation.


Solve the system for
and
.
Solve the system for and
.
Tap to see back →
The most simple method for solving systems of equations is to transform one of the equations so it allows for the canceling out of a variable. In this case, we can multiply
by
to get
.
Then, we can add
to this equation to yield
, so
.
We can plug that value into either of the original equations; for example,
.
So,
as well.
The most simple method for solving systems of equations is to transform one of the equations so it allows for the canceling out of a variable. In this case, we can multiply by
to get
.
Then, we can add to this equation to yield
, so
.
We can plug that value into either of the original equations; for example, .
So, as well.
Solve for
in the system of equations:


Solve for in the system of equations:
Tap to see back →
In the second equation, you can substitute
for
from the first.







Now, substitute 2 for
in the first equation:




The solution is 
In the second equation, you can substitute for
from the first.
Now, substitute 2 for in the first equation:
The solution is
What is the solution to the following system of equations:


What is the solution to the following system of equations:
Tap to see back →
By solving one equation for
, and replacing
in the other equation with that expression, you generate an equation of only 1 variable which can be readily solved.
By solving one equation for , and replacing
in the other equation with that expression, you generate an equation of only 1 variable which can be readily solved.
What is the sum of
and
for the following system of equations?


What is the sum of and
for the following system of equations?
Tap to see back →


Add the equations together.



Put the terms together to see that
.
Substitute this value into one of the original equaitons and solve for
.




Now we know that
, thus we can find the sum of
and
.

Add the equations together.
Put the terms together to see that .
Substitute this value into one of the original equaitons and solve for .
Now we know that , thus we can find the sum of
and
.
Without drawing a graph of either equation, find the point where the two lines intersect.
Line 1 : 
Line 2 : 
Without drawing a graph of either equation, find the point where the two lines intersect.
Line 1 :
Line 2 :
Tap to see back →
To find the point where these two lines intersect, set the equations equal to each other, such that
is substituted with the
side of the second equation. Solving this new equation for
will give the
-coordinate of the point of intersection.

Subtract
from both sides.


Divide both sides by 2.


Now substitute
into either equation to find the
-coordinate of the point of intersection.



With both coordinates, we know the point of intersection is
. One can plug in
for
and
for
in both equations to verify that this is correct.
To find the point where these two lines intersect, set the equations equal to each other, such that is substituted with the
side of the second equation. Solving this new equation for
will give the
-coordinate of the point of intersection.
Subtract from both sides.
Divide both sides by 2.
Now substitute into either equation to find the
-coordinate of the point of intersection.
With both coordinates, we know the point of intersection is . One can plug in
for
and
for
in both equations to verify that this is correct.