How to multiply square roots - PSAT Math
Card 0 of 28
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent, 
, multiplied by the answer acquired by multiplying the terms under the radican, 
.
The final answer is 
.
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent,
The final answer is
Compare your answer with the correct one above
Mulitply and simplify. Assume all integers are positive real numbers.
Mulitply and simplify. Assume all integers are positive real numbers.
Order of operations, first distributing the 
to all terms inside the parentheses.
The final answer is 
.
Order of operations, first distributing the
The final answer is
Compare your answer with the correct one above
The square root(s) of 36 is/are ________.
The square root(s) of 36 is/are ________.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
Compare your answer with the correct one above
Simplify:
Simplify:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two 
s. (Note, that it would be even easier to do this problem if you factor immediately instead of finding out that 
.)
After pulling out the 
s, you get:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two
After pulling out the
Compare your answer with the correct one above
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent, , multiplied by the answer acquired by multiplying the terms under the radican, .
The final answer is .
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent,
The final answer is
Compare your answer with the correct one above
Mulitply and simplify. Assume all integers are positive real numbers.
Mulitply and simplify. Assume all integers are positive real numbers.
Order of operations, first distributing the to all terms inside the parentheses.
The final answer is .
Order of operations, first distributing the
The final answer is
Compare your answer with the correct one above
The square root(s) of 36 is/are ________.
The square root(s) of 36 is/are ________.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
Compare your answer with the correct one above
Simplify:
Simplify:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two s. (Note, that it would be even easier to do this problem if you factor immediately instead of finding out that .)
After pulling out the s, you get:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two
After pulling out the
Compare your answer with the correct one above
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent, , multiplied by the answer acquired by multiplying the terms under the radican, .
The final answer is .
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent,
The final answer is
Compare your answer with the correct one above
Mulitply and simplify. Assume all integers are positive real numbers.
Mulitply and simplify. Assume all integers are positive real numbers.
Order of operations, first distributing the to all terms inside the parentheses.
The final answer is .
Order of operations, first distributing the
The final answer is
Compare your answer with the correct one above
The square root(s) of 36 is/are ________.
The square root(s) of 36 is/are ________.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
Compare your answer with the correct one above
Simplify:
Simplify:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two s. (Note, that it would be even easier to do this problem if you factor immediately instead of finding out that .)
After pulling out the s, you get:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two
After pulling out the
Compare your answer with the correct one above
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent, , multiplied by the answer acquired by multiplying the terms under the radican, .
The final answer is .
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent,
The final answer is
Compare your answer with the correct one above
Mulitply and simplify. Assume all integers are positive real numbers.
Mulitply and simplify. Assume all integers are positive real numbers.
Order of operations, first distributing the to all terms inside the parentheses.
The final answer is .
Order of operations, first distributing the
The final answer is
Compare your answer with the correct one above
The square root(s) of 36 is/are ________.
The square root(s) of 36 is/are ________.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
Compare your answer with the correct one above
Simplify:
Simplify:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two s. (Note, that it would be even easier to do this problem if you factor immediately instead of finding out that .)
After pulling out the s, you get:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two
After pulling out the
Compare your answer with the correct one above
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply and simplify. Assuming all integers are positive real numbers.
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent, , multiplied by the answer acquired by multiplying the terms under the radican, .
The final answer is .
Multiply the coefficents outside of the radicals.
Then multiply the radicans. Simplify by checking for a perfect square.
Final answer is your leading coefficent,
The final answer is
Compare your answer with the correct one above
Mulitply and simplify. Assume all integers are positive real numbers.
Mulitply and simplify. Assume all integers are positive real numbers.
Order of operations, first distributing the to all terms inside the parentheses.
The final answer is .
Order of operations, first distributing the
The final answer is
Compare your answer with the correct one above
The square root(s) of 36 is/are ________.
The square root(s) of 36 is/are ________.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
To square a number is to multiply that number by itself. Because 6 x 6 = 36 AND -6 x -6 = 36, both 6 and -6 are square roots of 36.
Compare your answer with the correct one above
Simplify:
Simplify:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two s. (Note, that it would be even easier to do this problem if you factor immediately instead of finding out that .)
After pulling out the s, you get:
Multiplication of square roots is easy! You just have to multiply their contents by each other. Just don't forget to put the result "under" a square root! Therefore:
becomes
Now, you need to simplify this:
You can "pull out" two
After pulling out the
Compare your answer with the correct one above