How to subtract fractions - PSAT Math

Card 0 of 49

Question

Subtract and simplify the fractions:

$\small \frac{7}{5} - \frac{3}{6}$

Answer

First we need to give them common denominators. Remember, whatever you do to the denominator you must do to the numerator:

$\small \small \frac{6}{6} \times \frac{7}{5} -\frac{5}{5} \times \frac{3}{6}$

$\small = \frac{42}{30}- \frac{15}{30}$

From here, we do algebraic operations to subtract and simplify.

$\small = \frac{42 - 15}{30}$

$\small = \frac{27}{30}$

$\small = \frac{9}{10}$

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Question

Define an operation $\Cup$ as follows:

For all real ,

$a \Cup b = \frac{3}{5} a -b$

Evaluate $\frac{1}{3 }\Cup \frac{1}{10}$

Answer

$a \Cup b = \frac{3}{5} a -b$

$\frac{1}{3 }\Cup \frac{1}{10} = \frac{3}{5}\left (\frac{1}{3} \right ) - \frac{1}{10}$

$= \frac{1}{5}\left (\frac{1}{1} \right ) - \frac{1}{10}$

$= \frac{1}{5} - \frac{1}{10}$

$= \frac{2}{10} - \frac{1}{10}$

$= \frac{1}{10}$

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Question

Define an operation $\bigstar$ as follows:

For all real ,

$a \bigstar b = 2a - 3b$ .

Evaluate $\frac{4}{5} \bigstar \frac{3}{10}$ .

Answer

$a \bigstar b = 2a - 3b$

$\frac{4}{5} \bigstar \frac{3}{10} = 2 \cdot \frac{4}{5} - 3 \cdot \frac{3}{10}$

$= \frac{2}{1} \cdot \frac{4}{5} - \frac{3}{1} \cdot \frac{3}{10}$

$= \frac{8}{5} - \frac{9}{10}$

$= \frac{16}{10} - \frac{9}{10}$

$= \frac{7}{10}$

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Question

Define an operation $\triangleright$ as follows:

For all real ,

$a \triangleright b = 7 - ab$ .

Evaluate $5 \triangleright \left ( - \frac{5}{3}\right )$ .

Answer

$a \triangleright b = 7 - ab$

$5 \triangleright \left ( - \frac{5}{3}\right ) = 7 - 5 \left ( - \frac{5}{3}\right )$

$= 7 - \frac{5}{1} \left ( - \frac{5}{3}\right )$

$= 7 - \left ( - \frac{25}{3}\right )$

$= \frac{21}{3} + \frac{25}{3}$

$= \frac{46}{3}$

$=15 \frac{1}{3}$

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Question

Define an operation $\Cup$ as follows:

For all real ,

$a \Cup b = a - b^{2}$

Evaluate $5\frac{1}{2} \Cup 1 \frac{1}{3}$ .

Answer

$a \Cup b = a - b^{2}$

$5\frac{1}{2} \Cup 1 \frac{1}{3} = 5\frac{1}{2} -\left ( 1 \frac{1}{3} \right )^{2}$

$= \frac{11}{2} -\left ( \frac{4}{3} \right )^{2}$

$= \frac{11}{2} -\left ( \frac{4^{2}}{3^{2}} \right )$

$= \frac{11}{2} - \frac{16}{9}$

$= \frac{99}{18} - \frac{32}{18}$

$= \frac{67}{18}$

$=3 \frac{13}{18}$

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Question

Define an operation $\bigstar$ as follows:

For all real ,

$a \bigstar b = \frac{1}{2} a - \frac{1}{3} b$ .

Evaluate $15 \bigstar 10$ .

Answer

$a \bigstar b = \frac{1}{2} a - \frac{1}{3} b$

$15 \bigstar 10 = \frac{1}{2} \cdot 15 - \frac{1}{3} \cdot 10$

$= \frac{1}{2} \cdot \frac{15 }{1}- \frac{1}{3} \cdot \frac{10}{1}$

$= \frac{15}{2} - \frac{10}{3}$

$= \frac{45}{6} - \frac{20}{6}$

$= \frac{25}{6}$

$= 4 \frac{1}{6}$

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Question

Define an operation $\triangleright$ as follows:

For all real ,

$a \triangleright b = a^{2}- b^{3}$ .

Evaluate $\frac{4}{5} \triangleright \frac{4}{5}$ .

Answer

$a \triangleright b = a^{2}- b^{3}$

$\frac{4}{5} \triangleright \frac{4}{5} =\left ( \frac{4}{5} \right )^{2} - \left ( \frac{4}{5} \right )^{3}$

$=\left ( \frac{4^{2}}{5^{2}} \right ) - \left ( \frac{4^{3}}{5^{3}} \right )$

$= \frac{16}{25} - \frac{64}{125}$

$= \frac{80}{125} - \frac{64}{125}$

$= \frac{16}{125}$

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Question

Subtract and simplify the fractions:

$\small \frac{7}{5} - \frac{3}{6}$

Answer

First we need to give them common denominators. Remember, whatever you do to the denominator you must do to the numerator:

$\small \small \frac{6}{6} \times \frac{7}{5} -\frac{5}{5} \times \frac{3}{6}$

$\small = \frac{42}{30}- \frac{15}{30}$

From here, we do algebraic operations to subtract and simplify.

$\small = \frac{42 - 15}{30}$

$\small = \frac{27}{30}$

$\small = \frac{9}{10}$

Compare your answer with the correct one above

Question

Define an operation $\Cup$ as follows:

For all real ,

$a \Cup b = \frac{3}{5} a -b$

Evaluate $\frac{1}{3 }\Cup \frac{1}{10}$

Answer

$a \Cup b = \frac{3}{5} a -b$

$\frac{1}{3 }\Cup \frac{1}{10} = \frac{3}{5}\left (\frac{1}{3} \right ) - \frac{1}{10}$

$= \frac{1}{5}\left (\frac{1}{1} \right ) - \frac{1}{10}$

$= \frac{1}{5} - \frac{1}{10}$

$= \frac{2}{10} - \frac{1}{10}$

$= \frac{1}{10}$

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Question

Define an operation $\bigstar$ as follows:

For all real ,

$a \bigstar b = 2a - 3b$ .

Evaluate $\frac{4}{5} \bigstar \frac{3}{10}$ .

Answer

$a \bigstar b = 2a - 3b$

$\frac{4}{5} \bigstar \frac{3}{10} = 2 \cdot \frac{4}{5} - 3 \cdot \frac{3}{10}$

$= \frac{2}{1} \cdot \frac{4}{5} - \frac{3}{1} \cdot \frac{3}{10}$

$= \frac{8}{5} - \frac{9}{10}$

$= \frac{16}{10} - \frac{9}{10}$

$= \frac{7}{10}$

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Question

Define an operation $\triangleright$ as follows:

For all real ,

$a \triangleright b = 7 - ab$ .

Evaluate $5 \triangleright \left ( - \frac{5}{3}\right )$ .

Answer

$a \triangleright b = 7 - ab$

$5 \triangleright \left ( - \frac{5}{3}\right ) = 7 - 5 \left ( - \frac{5}{3}\right )$

$= 7 - \frac{5}{1} \left ( - \frac{5}{3}\right )$

$= 7 - \left ( - \frac{25}{3}\right )$

$= \frac{21}{3} + \frac{25}{3}$

$= \frac{46}{3}$

$=15 \frac{1}{3}$

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Question

Define an operation $\Cup$ as follows:

For all real ,

$a \Cup b = a - b^{2}$

Evaluate $5\frac{1}{2} \Cup 1 \frac{1}{3}$ .

Answer

$a \Cup b = a - b^{2}$

$5\frac{1}{2} \Cup 1 \frac{1}{3} = 5\frac{1}{2} -\left ( 1 \frac{1}{3} \right )^{2}$

$= \frac{11}{2} -\left ( \frac{4}{3} \right )^{2}$

$= \frac{11}{2} -\left ( \frac{4^{2}}{3^{2}} \right )$

$= \frac{11}{2} - \frac{16}{9}$

$= \frac{99}{18} - \frac{32}{18}$

$= \frac{67}{18}$

$=3 \frac{13}{18}$

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Question

Define an operation $\bigstar$ as follows:

For all real ,

$a \bigstar b = \frac{1}{2} a - \frac{1}{3} b$ .

Evaluate $15 \bigstar 10$ .

Answer

$a \bigstar b = \frac{1}{2} a - \frac{1}{3} b$

$15 \bigstar 10 = \frac{1}{2} \cdot 15 - \frac{1}{3} \cdot 10$

$= \frac{1}{2} \cdot \frac{15 }{1}- \frac{1}{3} \cdot \frac{10}{1}$

$= \frac{15}{2} - \frac{10}{3}$

$= \frac{45}{6} - \frac{20}{6}$

$= \frac{25}{6}$

$= 4 \frac{1}{6}$

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Question

Define an operation $\triangleright$ as follows:

For all real ,

$a \triangleright b = a^{2}- b^{3}$ .

Evaluate $\frac{4}{5} \triangleright \frac{4}{5}$ .

Answer

$a \triangleright b = a^{2}- b^{3}$

$\frac{4}{5} \triangleright \frac{4}{5} =\left ( \frac{4}{5} \right )^{2} - \left ( \frac{4}{5} \right )^{3}$

$=\left ( \frac{4^{2}}{5^{2}} \right ) - \left ( \frac{4^{3}}{5^{3}} \right )$

$= \frac{16}{25} - \frac{64}{125}$

$= \frac{80}{125} - \frac{64}{125}$

$= \frac{16}{125}$

This answer is not among the choices given.

Compare your answer with the correct one above

Question

Subtract and simplify the fractions:

$\small \frac{7}{5} - \frac{3}{6}$

Answer

First we need to give them common denominators. Remember, whatever you do to the denominator you must do to the numerator:

$\small \small \frac{6}{6} \times \frac{7}{5} -\frac{5}{5} \times \frac{3}{6}$

$\small = \frac{42}{30}- \frac{15}{30}$

From here, we do algebraic operations to subtract and simplify.

$\small = \frac{42 - 15}{30}$

$\small = \frac{27}{30}$

$\small = \frac{9}{10}$

Compare your answer with the correct one above

Question

Define an operation $\Cup$ as follows:

For all real ,

$a \Cup b = \frac{3}{5} a -b$

Evaluate $\frac{1}{3 }\Cup \frac{1}{10}$

Answer

$a \Cup b = \frac{3}{5} a -b$

$\frac{1}{3 }\Cup \frac{1}{10} = \frac{3}{5}\left (\frac{1}{3} \right ) - \frac{1}{10}$

$= \frac{1}{5}\left (\frac{1}{1} \right ) - \frac{1}{10}$

$= \frac{1}{5} - \frac{1}{10}$

$= \frac{2}{10} - \frac{1}{10}$

$= \frac{1}{10}$

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Question

Define an operation $\bigstar$ as follows:

For all real ,

$a \bigstar b = 2a - 3b$ .

Evaluate $\frac{4}{5} \bigstar \frac{3}{10}$ .

Answer

$a \bigstar b = 2a - 3b$

$\frac{4}{5} \bigstar \frac{3}{10} = 2 \cdot \frac{4}{5} - 3 \cdot \frac{3}{10}$

$= \frac{2}{1} \cdot \frac{4}{5} - \frac{3}{1} \cdot \frac{3}{10}$

$= \frac{8}{5} - \frac{9}{10}$

$= \frac{16}{10} - \frac{9}{10}$

$= \frac{7}{10}$

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Question

Define an operation $\triangleright$ as follows:

For all real ,

$a \triangleright b = 7 - ab$ .

Evaluate $5 \triangleright \left ( - \frac{5}{3}\right )$ .

Answer

$a \triangleright b = 7 - ab$

$5 \triangleright \left ( - \frac{5}{3}\right ) = 7 - 5 \left ( - \frac{5}{3}\right )$

$= 7 - \frac{5}{1} \left ( - \frac{5}{3}\right )$

$= 7 - \left ( - \frac{25}{3}\right )$

$= \frac{21}{3} + \frac{25}{3}$

$= \frac{46}{3}$

$=15 \frac{1}{3}$

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Question

Define an operation $\Cup$ as follows:

For all real ,

$a \Cup b = a - b^{2}$

Evaluate $5\frac{1}{2} \Cup 1 \frac{1}{3}$ .

Answer

$a \Cup b = a - b^{2}$

$5\frac{1}{2} \Cup 1 \frac{1}{3} = 5\frac{1}{2} -\left ( 1 \frac{1}{3} \right )^{2}$

$= \frac{11}{2} -\left ( \frac{4}{3} \right )^{2}$

$= \frac{11}{2} -\left ( \frac{4^{2}}{3^{2}} \right )$

$= \frac{11}{2} - \frac{16}{9}$

$= \frac{99}{18} - \frac{32}{18}$

$= \frac{67}{18}$

$=3 \frac{13}{18}$

Compare your answer with the correct one above

Question

Define an operation $\bigstar$ as follows:

For all real ,

$a \bigstar b = \frac{1}{2} a - \frac{1}{3} b$ .

Evaluate $15 \bigstar 10$ .

Answer

$a \bigstar b = \frac{1}{2} a - \frac{1}{3} b$

$15 \bigstar 10 = \frac{1}{2} \cdot 15 - \frac{1}{3} \cdot 10$

$= \frac{1}{2} \cdot \frac{15 }{1}- \frac{1}{3} \cdot \frac{10}{1}$

$= \frac{15}{2} - \frac{10}{3}$

$= \frac{45}{6} - \frac{20}{6}$

$= \frac{25}{6}$

$= 4 \frac{1}{6}$

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