How to use FOIL with Exponents - PSAT Math

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If , which of the following could be the value of ?

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Take the square root of both sides.

$x-3=\pm 5$

$x-3=5\ $\text{or}$\ x-3=-5$

Add 3 to both sides of each equation.

$x=5+3\ $\text{or}$\ x=-5+3$

$x=8\ $\text{or}$\ x=-2$

Which of the following is equivalent to 4c(3d)3 – 8c3d + 2(cd)4?

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First calculate each section to yield 4c(27d3) – 8c3d + 2c4d4 = 108cd3 – 8c3d + 2c4d4. Now let's factor out the greatest common factor of the three terms, 2cd, in order to get: 2cd(54d2 – 4c2 + c3d3).

Simplify:

$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

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$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

= _x_3_y_3_z_3 + x_2_y + _x_0_y_0 + x_2_y

= _x_3_y_3_z_3 + x_2_y + 1 + x_2_y

= x_3_y_3_z_3 + 2_x_2_y + 1

Square the binomial.

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We will need to FOIL.

First:

Inside:

Outside:

Last:

Sum all of the terms and simplify.

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Use the FOIL method to find the product. Remember to add the exponents when multiplying.

First:

Outside:

Inside:

Last:

Add all the terms:

If , which of the following could be the value of ?

Tap to see back →

Take the square root of both sides.

$x-3=\pm 5$

$x-3=5\ $\text{or}$\ x-3=-5$

Add 3 to both sides of each equation.

$x=5+3\ $\text{or}$\ x=-5+3$

$x=8\ $\text{or}$\ x=-2$

Which of the following is equivalent to 4c(3d)3 – 8c3d + 2(cd)4?

Tap to see back →

First calculate each section to yield 4c(27d3) – 8c3d + 2c4d4 = 108cd3 – 8c3d + 2c4d4. Now let's factor out the greatest common factor of the three terms, 2cd, in order to get: 2cd(54d2 – 4c2 + c3d3).

Simplify:

$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

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$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

= _x_3_y_3_z_3 + x_2_y + _x_0_y_0 + x_2_y

= _x_3_y_3_z_3 + x_2_y + 1 + x_2_y

= x_3_y_3_z_3 + 2_x_2_y + 1

Square the binomial.

Tap to see back →

We will need to FOIL.

First:

Inside:

Outside:

Last:

Sum all of the terms and simplify.

Tap to see back →

Use the FOIL method to find the product. Remember to add the exponents when multiplying.

First:

Outside:

Inside:

Last:

Add all the terms:

If , which of the following could be the value of ?

Tap to see back →

Take the square root of both sides.

$x-3=\pm 5$

$x-3=5\ $\text{or}$\ x-3=-5$

Add 3 to both sides of each equation.

$x=5+3\ $\text{or}$\ x=-5+3$

$x=8\ $\text{or}$\ x=-2$

Which of the following is equivalent to 4c(3d)3 – 8c3d + 2(cd)4?

Tap to see back →

First calculate each section to yield 4c(27d3) – 8c3d + 2c4d4 = 108cd3 – 8c3d + 2c4d4. Now let's factor out the greatest common factor of the three terms, 2cd, in order to get: 2cd(54d2 – 4c2 + c3d3).

Simplify:

$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

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$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

= _x_3_y_3_z_3 + x_2_y + _x_0_y_0 + x_2_y

= _x_3_y_3_z_3 + x_2_y + 1 + x_2_y

= x_3_y_3_z_3 + 2_x_2_y + 1

Square the binomial.

Tap to see back →

We will need to FOIL.

First:

Inside:

Outside:

Last:

Sum all of the terms and simplify.

Tap to see back →

Use the FOIL method to find the product. Remember to add the exponents when multiplying.

First:

Outside:

Inside:

Last:

Add all the terms:

If , which of the following could be the value of ?

Tap to see back →

Take the square root of both sides.

$x-3=\pm 5$

$x-3=5\ $\text{or}$\ x-3=-5$

Add 3 to both sides of each equation.

$x=5+3\ $\text{or}$\ x=-5+3$

$x=8\ $\text{or}$\ x=-2$

Which of the following is equivalent to 4c(3d)3 – 8c3d + 2(cd)4?

Tap to see back →

First calculate each section to yield 4c(27d3) – 8c3d + 2c4d4 = 108cd3 – 8c3d + 2c4d4. Now let's factor out the greatest common factor of the three terms, 2cd, in order to get: 2cd(54d2 – 4c2 + c3d3).

Simplify:

$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

Tap to see back →

$\left ( xyz \right $)^{3}$$+x^{2}$y+\left( xy \right $)^{0}$+\left( $xy^{$\frac{1}${2}$} \right $)^{2}$$

= _x_3_y_3_z_3 + x_2_y + _x_0_y_0 + x_2_y

= _x_3_y_3_z_3 + x_2_y + 1 + x_2_y

= x_3_y_3_z_3 + 2_x_2_y + 1

Square the binomial.

Tap to see back →

We will need to FOIL.

First:

Inside:

Outside:

Last:

Sum all of the terms and simplify.

Tap to see back →

Use the FOIL method to find the product. Remember to add the exponents when multiplying.

First:

Outside:

Inside:

Last:

Add all the terms: