Other Decimals - SAT Math
Card 0 of 344
simplify: 0.2 ÷ 0.04
simplify: 0.2 ÷ 0.04
0.2 ÷ 0.04 <- easiest way to approach is to move the decimal to the right (the same amount of spaces on each side) so that the decimal disappears
since 0.04 has 2 spaces and 0.2 only has 1, move the decimal 2 spaces to the right on each side
0.2 ÷ 0.04 = 20 ÷ 4 = 5
0.2 ÷ 0.04 <- easiest way to approach is to move the decimal to the right (the same amount of spaces on each side) so that the decimal disappears
since 0.04 has 2 spaces and 0.2 only has 1, move the decimal 2 spaces to the right on each side
0.2 ÷ 0.04 = 20 ÷ 4 = 5
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If the cost of 20 equally priced pencils cost \$5.80, then at the same rate what is the greatest number of pencils you can purchase for \$50?
If the cost of 20 equally priced pencils cost \$5.80, then at the same rate what is the greatest number of pencils you can purchase for \$50?
Remeber for this problem that you cannot spend more than \$50. First find the price of each pencil by 5.80/20 = 29 cents. And then use this to do 50/0.29 = 172.41. So the greatest number of pencils you can purchase for \$50 is 172 pencils.
Remeber for this problem that you cannot spend more than \$50. First find the price of each pencil by 5.80/20 = 29 cents. And then use this to do 50/0.29 = 172.41. So the greatest number of pencils you can purchase for \$50 is 172 pencils.
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Simplify:
Simplify:
Multiply both the numerator and denominator by some power of 10 to get rid of the decimals; in this case, multiply both by 10,000.
Multiply both the numerator and denominator by some power of 10 to get rid of the decimals; in this case, multiply both by 10,000.
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Charlie has charges on his credit card of \$63.70, \$37.32, and \$81.78. If he pays down half his bill at once, and then pays the rest in four equal monthly installments, how much is each monthly installment?
Charlie has charges on his credit card of \$63.70, \$37.32, and \$81.78. If he pays down half his bill at once, and then pays the rest in four equal monthly installments, how much is each monthly installment?
Adding all the charges together and dividing by 2 yields \$91.40. Dividing this by 4 yields a monthly installment of \$22.85.
Adding all the charges together and dividing by 2 yields \$91.40. Dividing this by 4 yields a monthly installment of \$22.85.
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If Johnny buys two comic books, priced at \$1.50 each, and a candy bar, priced at \$0.75, he'll have three quarters and two dimes left over. How much money does he have right now?
If Johnny buys two comic books, priced at \$1.50 each, and a candy bar, priced at \$0.75, he'll have three quarters and two dimes left over. How much money does he have right now?
Add what he can purchase to what he has left over:
Two comic books and the candy bar: $1.50 + $1.0 + $0.75 = $3.75
Three quarters and two dimes: $0.75 + $0.20 = \$0.95
Therefore his total amount of money is \$3.75 + $0.95 = $4.70.
Add what he can purchase to what he has left over:
Two comic books and the candy bar: $1.50 + $1.0 + $0.75 = $3.75
Three quarters and two dimes: $0.75 + $0.20 = \$0.95
Therefore his total amount of money is \$3.75 + $0.95 = $4.70.
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Add: 
Add:
In order to add the decimals, add placeholders to the decimal 
.
Be careful not to add the wrong digits!
Add the thousandths places.
Add the hundredths places.
Add the tenths places.
Combine the numbers and put a decimal before the tenths place.
The correct answer is: 
In order to add the decimals, add placeholders to the decimal
Be careful not to add the wrong digits!
Add the thousandths places.
Add the hundredths places.
Add the tenths places.
Combine the numbers and put a decimal before the tenths place.
The correct answer is:
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A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them. How many routes will only require them to drive 40 miles or fewer:
A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them. How many routes will only require them to drive 40 miles or fewer:
There are three routes from Point A to Point B, and three from Point B to Point C, for a total of 
routes total. The total distance traveled is the distance of one of the first three routes added to that of one of the last three; we can take all nine possibilities and add the distances:
Five of these routes require driving a distance 40 miles or fewer.
There are three routes from Point A to Point B, and three from Point B to Point C, for a total of
Five of these routes require driving a distance 40 miles or fewer.
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A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them.
Give the range for the driving distance 
for the trip.
A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them.
Give the range for the driving distance
Each route includes one path from Point A to Point B and one path from Point B o Point C.
The shortest possible drive is the sum of the shortest paths for each leg of the trip:
The longest possible drive is the sum of the longest paths for each leg of the trip:
The correct response is that 
.
Each route includes one path from Point A to Point B and one path from Point B o Point C.
The shortest possible drive is the sum of the shortest paths for each leg of the trip:
The longest possible drive is the sum of the longest paths for each leg of the trip:
The correct response is that
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Above is a simplified map of the routes from Town A to Town B, and the routes from Town B to Town C.
A family wants to travel from Town A to Town C by way of Town B, then back to Town A by way of Town B. Since all routes are scenic, the family does not want to take any route twice.
Give the range for the distance 
in miles that the family will travel.
Above is a simplified map of the routes from Town A to Town B, and the routes from Town B to Town C.
A family wants to travel from Town A to Town C by way of Town B, then back to Town A by way of Town B. Since all routes are scenic, the family does not want to take any route twice.
Give the range for the distance
The family's trip will be designed so that the family will take two different routes of the three that connect Town A and Town B, and two different routes of the three that connect Town B and Town C.
The minimum distance that the family will travel is therefore the sum of the lengths of the two shortest routes from Town A to Town B, and those of the two shortest routes from Town B to Town C:
miles
The maximum distance that the family will travel is, similarly, the sum of the lengths of the two longest routes from Town A to Town B, and those of the two longest routes from Town B to Town C:
miles
The correct choice is therefore 
.
The family's trip will be designed so that the family will take two different routes of the three that connect Town A and Town B, and two different routes of the three that connect Town B and Town C.
The minimum distance that the family will travel is therefore the sum of the lengths of the two shortest routes from Town A to Town B, and those of the two shortest routes from Town B to Town C:
The maximum distance that the family will travel is, similarly, the sum of the lengths of the two longest routes from Town A to Town B, and those of the two longest routes from Town B to Town C:
The correct choice is therefore
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Round the answer to the nearest tenth.
Round the answer to the nearest tenth.
0.57 - 2.657 = -2.087
Don't forget the negative sign!
This number then rounds to -2.1.
0.57 - 2.657 = -2.087
Don't forget the negative sign!
This number then rounds to -2.1.
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45.728 x 3.2 = ?
45.728 x 3.2 = ?
Multiply the numbers out in long format, then move the decimal point over the total number of decimal points in the two numbers (3 in the first, 1 in the second, so 4 total):
45.728 * 3.2 = 91456
91456 + 1371840 = 1,463,296 → 146.3296
Or just count the decimal points in the answer and make sure it's 4.
Multiply the numbers out in long format, then move the decimal point over the total number of decimal points in the two numbers (3 in the first, 1 in the second, so 4 total):
45.728 * 3.2 = 91456
91456 + 1371840 = 1,463,296 → 146.3296
Or just count the decimal points in the answer and make sure it's 4.
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If 
is 25% of 
, what is the closest integer to the value of __
_?
If
We can approximate the value of y pretty quickly:
y ≈ 1(0.50)(52) = 26
Since y = 0.25x = (1/4)x we know that x = 4y ≈ 4(26) = 104
We can approximate the value of y pretty quickly:
y ≈ 1(0.50)(52) = 26
Since y = 0.25x = (1/4)x we know that x = 4y ≈ 4(26) = 104
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It's much easier to work with whole numbers, so we'll ignore the decimals for the first step: 5 x 12 = 60
Now look at the decimals. To add them back in, think of 60 as 60.0. Now move the decimal point four places to the left: 0.5 x 0.012 = .0060 = .006
It's much easier to work with whole numbers, so we'll ignore the decimals for the first step: 5 x 12 = 60
Now look at the decimals. To add them back in, think of 60 as 60.0. Now move the decimal point four places to the left: 0.5 x 0.012 = .0060 = .006
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At the farmer's market, oranges are \$0.30 each, apples are \$0.25 each, bananas are \$0.40 each, and tomatoes are \$0.60 each. If Scott buys 3 oranges, 7 apples, 4 bananas, and 8 tomatoes, how much does he spend?
At the farmer's market, oranges are \$0.30 each, apples are \$0.25 each, bananas are \$0.40 each, and tomatoes are \$0.60 each. If Scott buys 3 oranges, 7 apples, 4 bananas, and 8 tomatoes, how much does he spend?
To find out how much Scott spends, we need to multiply the quantity of each fruit by its price and add them all up.
3 * $0.30 + 7 * $0.25 + 4 * $0.40 + 8 * $0.60 = \$9.05
To find out how much Scott spends, we need to multiply the quantity of each fruit by its price and add them all up.
3 * $0.30 + 7 * $0.25 + 4 * $0.40 + 8 * $0.60 = \$9.05
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You bought a dozen eggs marked at 
and received 
change from 
. What is the percent of sales tax?
You bought a dozen eggs marked at
Set the equation up as
Solve for 
, which equals 
or
Therefore the percent sales tax is:
Set the equation up as
Solve for
or
Therefore the percent sales tax is:
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If Johnny buys two comic books, priced at \$1.50 each, and a candy bar, priced at \$0.75, he'll have three quarters and two dimes left over. How much money does he have right now?
If Johnny buys two comic books, priced at \$1.50 each, and a candy bar, priced at \$0.75, he'll have three quarters and two dimes left over. How much money does he have right now?
Add what he can purchase to what he has left over:
Two comic books and the candy bar: $1.50 + $1.0 + $0.75 = $3.75
Three quarters and two dimes: $0.75 + $0.20 = \$0.95
Therefore his total amount of money is \$3.75 + $0.95 = $4.70.
Add what he can purchase to what he has left over:
Two comic books and the candy bar: $1.50 + $1.0 + $0.75 = $3.75
Three quarters and two dimes: $0.75 + $0.20 = \$0.95
Therefore his total amount of money is \$3.75 + $0.95 = $4.70.
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Add:
Add:
In order to add the decimals, add placeholders to the decimal .
Be careful not to add the wrong digits!
Add the thousandths places.
Add the hundredths places.
Add the tenths places.
Combine the numbers and put a decimal before the tenths place.
The correct answer is:
In order to add the decimals, add placeholders to the decimal
Be careful not to add the wrong digits!
Add the thousandths places.
Add the hundredths places.
Add the tenths places.
Combine the numbers and put a decimal before the tenths place.
The correct answer is:
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A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them. How many routes will only require them to drive 40 miles or fewer:
A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them. How many routes will only require them to drive 40 miles or fewer:
There are three routes from Point A to Point B, and three from Point B to Point C, for a total of routes total. The total distance traveled is the distance of one of the first three routes added to that of one of the last three; we can take all nine possibilities and add the distances:
Five of these routes require driving a distance 40 miles or fewer.
There are three routes from Point A to Point B, and three from Point B to Point C, for a total of
Five of these routes require driving a distance 40 miles or fewer.
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A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them.
Give the range for the driving distance for the trip.
A family is taking a trip from Town A to Town B, then to Town C. Above is a diagram of the routes available to them.
Give the range for the driving distance
Each route includes one path from Point A to Point B and one path from Point B o Point C.
The shortest possible drive is the sum of the shortest paths for each leg of the trip:
The longest possible drive is the sum of the longest paths for each leg of the trip:
The correct response is that .
Each route includes one path from Point A to Point B and one path from Point B o Point C.
The shortest possible drive is the sum of the shortest paths for each leg of the trip:
The longest possible drive is the sum of the longest paths for each leg of the trip:
The correct response is that
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Above is a simplified map of the routes from Town A to Town B, and the routes from Town B to Town C.
A family wants to travel from Town A to Town C by way of Town B, then back to Town A by way of Town B. Since all routes are scenic, the family does not want to take any route twice.
Give the range for the distance in miles that the family will travel.
Above is a simplified map of the routes from Town A to Town B, and the routes from Town B to Town C.
A family wants to travel from Town A to Town C by way of Town B, then back to Town A by way of Town B. Since all routes are scenic, the family does not want to take any route twice.
Give the range for the distance
The family's trip will be designed so that the family will take two different routes of the three that connect Town A and Town B, and two different routes of the three that connect Town B and Town C.
The minimum distance that the family will travel is therefore the sum of the lengths of the two shortest routes from Town A to Town B, and those of the two shortest routes from Town B to Town C:
miles
The maximum distance that the family will travel is, similarly, the sum of the lengths of the two longest routes from Town A to Town B, and those of the two longest routes from Town B to Town C:
miles
The correct choice is therefore .
The family's trip will be designed so that the family will take two different routes of the three that connect Town A and Town B, and two different routes of the three that connect Town B and Town C.
The minimum distance that the family will travel is therefore the sum of the lengths of the two shortest routes from Town A to Town B, and those of the two shortest routes from Town B to Town C:
The maximum distance that the family will travel is, similarly, the sum of the lengths of the two longest routes from Town A to Town B, and those of the two longest routes from Town B to Town C:
The correct choice is therefore
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