How to divide variables - SSAT Middle Level Quantitative

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Solve for the variable:

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In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{4x}{4}$=\frac{16}{4}$

If and , then $\frac{y}{z}$ is equal to:

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If and , then when plugging the variables into the fractional form of $\frac{y}{z}$ , the result is $\frac{12}{3}$ , which is equal to 4, which is therefore the correct answer.

Solve for the variable:

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In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{3x}{3}$=\frac{9}{3}$

If and , then $\frac{y}{x}$ is equal to:

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If and , then when plugging the variables into the fractional form of:

$$\frac{y}{x}$=\frac{30}$5$

$$\frac{30}{5}$=\frac{6}{1}$=6$

Simpify the expression.

$\frac{24abcdefg}{24abcdefgh}$

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To solve this problem you can cancel out like terms in the numerator and denominator. For example,

$$\frac{24}{24}$=1$

$$\frac{a}{a}$=1$

So,

$\frac{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g}{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g\cdot h}$=\frac{1}{h}$

All the other terms cancel each other out because they are equal to one.

Solve for the variable:

Tap to see back →

In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{4x}{4}$=\frac{16}{4}$

If and , then $\frac{y}{z}$ is equal to:

Tap to see back →

If and , then when plugging the variables into the fractional form of $\frac{y}{z}$ , the result is $\frac{12}{3}$ , which is equal to 4, which is therefore the correct answer.

Solve for the variable:

Tap to see back →

In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{3x}{3}$=\frac{9}{3}$

If and , then $\frac{y}{x}$ is equal to:

Tap to see back →

If and , then when plugging the variables into the fractional form of:

$$\frac{y}{x}$=\frac{30}$5$

$$\frac{30}{5}$=\frac{6}{1}$=6$

Simpify the expression.

$\frac{24abcdefg}{24abcdefgh}$

Tap to see back →

To solve this problem you can cancel out like terms in the numerator and denominator. For example,

$$\frac{24}{24}$=1$

$$\frac{a}{a}$=1$

So,

$\frac{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g}{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g\cdot h}$=\frac{1}{h}$

All the other terms cancel each other out because they are equal to one.

Solve for the variable:

Tap to see back →

In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{4x}{4}$=\frac{16}{4}$

If and , then $\frac{y}{z}$ is equal to:

Tap to see back →

If and , then when plugging the variables into the fractional form of $\frac{y}{z}$ , the result is $\frac{12}{3}$ , which is equal to 4, which is therefore the correct answer.

Solve for the variable:

Tap to see back →

In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{3x}{3}$=\frac{9}{3}$

If and , then $\frac{y}{x}$ is equal to:

Tap to see back →

If and , then when plugging the variables into the fractional form of:

$$\frac{y}{x}$=\frac{30}$5$

$$\frac{30}{5}$=\frac{6}{1}$=6$

Simpify the expression.

$\frac{24abcdefg}{24abcdefgh}$

Tap to see back →

To solve this problem you can cancel out like terms in the numerator and denominator. For example,

$$\frac{24}{24}$=1$

$$\frac{a}{a}$=1$

So,

$\frac{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g}{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g\cdot h}$=\frac{1}{h}$

All the other terms cancel each other out because they are equal to one.

Solve for the variable:

Tap to see back →

In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{4x}{4}$=\frac{16}{4}$

If and , then $\frac{y}{z}$ is equal to:

Tap to see back →

If and , then when plugging the variables into the fractional form of $\frac{y}{z}$ , the result is $\frac{12}{3}$ , which is equal to 4, which is therefore the correct answer.

Solve for the variable:

Tap to see back →

In order to answer this question, you must isolate on one side of the equation.

(Subtract from both sides.)

$\frac{3x}{3}$=\frac{9}{3}$

If and , then $\frac{y}{x}$ is equal to:

Tap to see back →

If and , then when plugging the variables into the fractional form of:

$$\frac{y}{x}$=\frac{30}$5$

$$\frac{30}{5}$=\frac{6}{1}$=6$

Simpify the expression.

$\frac{24abcdefg}{24abcdefgh}$

Tap to see back →

To solve this problem you can cancel out like terms in the numerator and denominator. For example,

$$\frac{24}{24}$=1$

$$\frac{a}{a}$=1$

So,

$\frac{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g}{24\cdot a\cdot b\cdot c\cdot d\cdot e\cdot f\cdot g\cdot h}$=\frac{1}{h}$

All the other terms cancel each other out because they are equal to one.