How to find a line on a coordinate plane - SSAT Middle Level Quantitative

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Give the slope of the line that passes through and .

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Use the slope formula, substituting :

$m =\frac{ $y_{2}$$- $y_{1}$ $}{x_{2}$ - $x_{1}$}=\frac{ -3-2 }{-8-4}$ = $\frac{ -5 }{-12}$ = $\frac{5 }{12}$$

Billy set up a ramp for his toy cars. He did this by taking a wooden plank and putting one end on top of a brick that was 3 inches high. He then put the other end on top of a box that was 9 inches high. The bricks were 18 inches apart. What is the slope of the plank?

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The value of the slope (m) is rise over run, and can be calculated with the formula below:

$m = $$\frac{y_{2}$$$-y_{1}$$}{x_{2}$$-x_{1}$}$

The coordinates of the first end of the plank would be (0,3), given that this is the starting point of the plank (so x would be 0), and y would be 3 since the brick is 3 inches tall.

The coordinates of the second end of the plank would be (18,9) since the plank is 18 inches long (so x would be 18) and y would be 9 since the box was 9 inches tall at the other end.

From this information we know that we can assign the following coordinates for the equation:

and

Below is the solution we would get from plugging this information into the equation for slope:

$m = $\frac{9-3}{18-0}$}$

This reduces to $\frac{6}{18}$ =\frac{1}{3}$

Give the slope of a line that passes through and .

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Using the slope formula, substituting , , , and :

$m=\frac{4-5}{2-5}$$

Subtract to get:

$m=\frac{-1}{-3}$$

Cancel out the negative signs to get:

$m=\frac{1}{3}$$

Give the slope of a line that passes through and .

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Using the slope formula with , , , :

$m=\frac{5-4}{2-(-7)}$$

Subtract to get:

$m=\frac{1}{9}$$

Give the slope of the line that passes through and .

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Using the slope formula for

, , , and :

$m=\frac{9-3}{1-(-5)}$$

Combine the negative signs to get:

$m=\frac{9-3}{1+5}$$

Subtract and add to get:

$m=\frac{6}{6}$$

Reduce to get:

Give the slope of a line that passes through and .

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Using the slope formula, where is the slope, , and :

$m=\frac{3-7}{2-4}$$

$m=\frac{-4}{-2}$$

Find the slope of a line with points and .

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Using the slope formula, where is the slope, , and :

$m=\frac{5-0}{-10-(-1)}$$

$m=\frac{5}{-10+1}$$

$m=-$\frac{5}{9}$$

Find the slope of the line that passes through the points and

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Using the slope formula, where is the slope, , and :

$m=\frac{-4-(-4)}{-5-5}$$

$m=\frac{-4+4}{-10}$$

$m=\frac{0}{-10}$$

Give the slope of the line that passes through and .

Tap to see back →

Use the slope formula, substituting :

$m =\frac{ $y_{2}$$- $y_{1}$ $}{x_{2}$ - $x_{1}$}=\frac{ -3-2 }{-8-4}$ = $\frac{ -5 }{-12}$ = $\frac{5 }{12}$$

Billy set up a ramp for his toy cars. He did this by taking a wooden plank and putting one end on top of a brick that was 3 inches high. He then put the other end on top of a box that was 9 inches high. The bricks were 18 inches apart. What is the slope of the plank?

Tap to see back →

The value of the slope (m) is rise over run, and can be calculated with the formula below:

$m = $$\frac{y_{2}$$$-y_{1}$$}{x_{2}$$-x_{1}$}$

The coordinates of the first end of the plank would be (0,3), given that this is the starting point of the plank (so x would be 0), and y would be 3 since the brick is 3 inches tall.

The coordinates of the second end of the plank would be (18,9) since the plank is 18 inches long (so x would be 18) and y would be 9 since the box was 9 inches tall at the other end.

From this information we know that we can assign the following coordinates for the equation:

and

Below is the solution we would get from plugging this information into the equation for slope:

$m = $\frac{9-3}{18-0}$}$

This reduces to $\frac{6}{18}$ =\frac{1}{3}$

Give the slope of a line that passes through and .

Tap to see back →

Using the slope formula, substituting , , , and :

$m=\frac{4-5}{2-5}$$

Subtract to get:

$m=\frac{-1}{-3}$$

Cancel out the negative signs to get:

$m=\frac{1}{3}$$

Give the slope of a line that passes through and .

Tap to see back →

Using the slope formula with , , , :

$m=\frac{5-4}{2-(-7)}$$

Subtract to get:

$m=\frac{1}{9}$$

Give the slope of the line that passes through and .

Tap to see back →

Using the slope formula for

, , , and :

$m=\frac{9-3}{1-(-5)}$$

Combine the negative signs to get:

$m=\frac{9-3}{1+5}$$

Subtract and add to get:

$m=\frac{6}{6}$$

Reduce to get:

Give the slope of a line that passes through and .

Tap to see back →

Using the slope formula, where is the slope, , and :

$m=\frac{3-7}{2-4}$$

$m=\frac{-4}{-2}$$

Find the slope of a line with points and .

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Using the slope formula, where is the slope, , and :

$m=\frac{5-0}{-10-(-1)}$$

$m=\frac{5}{-10+1}$$

$m=-$\frac{5}{9}$$

Find the slope of the line that passes through the points and

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Using the slope formula, where is the slope, , and :

$m=\frac{-4-(-4)}{-5-5}$$

$m=\frac{-4+4}{-10}$$

$m=\frac{0}{-10}$$

Give the slope of the line that passes through and .

Tap to see back →

Use the slope formula, substituting :

$m =\frac{ $y_{2}$$- $y_{1}$ $}{x_{2}$ - $x_{1}$}=\frac{ -3-2 }{-8-4}$ = $\frac{ -5 }{-12}$ = $\frac{5 }{12}$$

Billy set up a ramp for his toy cars. He did this by taking a wooden plank and putting one end on top of a brick that was 3 inches high. He then put the other end on top of a box that was 9 inches high. The bricks were 18 inches apart. What is the slope of the plank?

Tap to see back →

The value of the slope (m) is rise over run, and can be calculated with the formula below:

$m = $$\frac{y_{2}$$$-y_{1}$$}{x_{2}$$-x_{1}$}$

The coordinates of the first end of the plank would be (0,3), given that this is the starting point of the plank (so x would be 0), and y would be 3 since the brick is 3 inches tall.

The coordinates of the second end of the plank would be (18,9) since the plank is 18 inches long (so x would be 18) and y would be 9 since the box was 9 inches tall at the other end.

From this information we know that we can assign the following coordinates for the equation:

and

Below is the solution we would get from plugging this information into the equation for slope:

$m = $\frac{9-3}{18-0}$}$

This reduces to $\frac{6}{18}$ =\frac{1}{3}$

Give the slope of a line that passes through and .

Tap to see back →

Using the slope formula, substituting , , , and :

$m=\frac{4-5}{2-5}$$

Subtract to get:

$m=\frac{-1}{-3}$$

Cancel out the negative signs to get:

$m=\frac{1}{3}$$

Give the slope of a line that passes through and .

Tap to see back →

Using the slope formula with , , , :

$m=\frac{5-4}{2-(-7)}$$

Subtract to get:

$m=\frac{1}{9}$$