The hundredth place is the 2nd number after the decimal. Because the thousandth place is great than 5, we will need to round up to $\displaystyle 178.02$

1. Round 145 to the nearest 10:

Since there is a 5 in the ones place, 145 rounds up to 150.

2. Divide the rounded number of baseballs by 10 since they come in packages of 10:

150/10=15 packages

To round to the nearest ten, you need to take a look at the ones' place. Since the ones' place is greater than $\displaystyle 5$, you will need to round the tens' place up.

So then $\displaystyle 127$ is rounded up to $\displaystyle 130$.

To figure out how to round the ones' place, we need to first look at the digit that's to the right of it. If the digit to the right of the ones' place is less than 5, then we leave the ones' place alone.

Since the tenths place is 1, we will leave the ones place alone.

To figure out how to round any number, look at the digit to the right of the place you're supposed to be rounding.

Since we want to round the hundreds place, look to the tens place first. If the tens place is greater than 5, then we round up. If the tens place is less than five, then leave the hundreds place alone.

Because the tens place is 7, we will need to round to 900.

An important thing to remember when rounding is knowing which place you're rounding to. In this problem, we our rounding to the ten-thousands place, therefore we need to take a look at two things: 1) which number appears in that place, and 2) what number appears immediately after it:

$\displaystyle \small 5,384,981$

With this number, an $\displaystyle \small 8$ appears in the ten-thousands place and a $\displaystyle \small 4$ appears immediately thereafter. When rounding, we take a look at the number after the place we're rounding to see whether we are rounding up or down. If we have a $\displaystyle \small 0,1,2,3,$ or $\displaystyle \small 4$ in that place, we will round down, but if we have a $\displaystyle \small 5,6,7,8$ or $\displaystyle \small 9$, we will round up. Since in this number we have a $\displaystyle \small 4$ in that place, we will round down to $\displaystyle \small 8$. All the places now to the right of the $\displaystyle \small 8$ can be written as $\displaystyle \small 0$s, and our final answer is:

$\displaystyle \small 5,384,981\Rightarrow5,380,000$

1. Add the ones places:

$\displaystyle 6+3=9$

2. Add the tens places:

$\displaystyle 4+9=13$

***don't forget to put the 3 down and carry the one to the hundreds place***

3. Add the hundreds place:

$\displaystyle 4+1+5$

This makes your total:

$\displaystyle \$539$

First add the digits in the ones colume, this would be $\displaystyle 8+9=17$. Make sure to carry the 1 from the 17 to the tens colume.

Then add the digits in the tens colume, this would be $\displaystyle 1+2+1=4$.

Lastly, add the digits in the hundrends colume, this would be $\displaystyle 1$

Therefore the result is as follows:

$\displaystyle 2 + 5 = 7$

We can see this because if we had 5 (represented by $\displaystyle x$) and add another 2 objects (represented by $\displaystyle y$) we should get 7 objects ($\displaystyle x$ and $\displaystyle y$) total.

 $\displaystyle (x+x+x+x+x)+(y+y) = (x+x+x+x+x+y+y)$

We have 7 objects total!

$\displaystyle 5+6=11$

If x represents objects.

For 5:

$\displaystyle 5=(x+x+x+x+x)$

For 6:

$\displaystyle 6=(y+y+y+y+y+y)$

$\displaystyle (x+x+x+x+x)+(y+y+y+y+y+y)=(y+y+y+y+y+y+x+x+x+x+x)$

We can see that 11 objects result.