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Common Core: 5th Grade Math : Solve Word Problems Involving Division of Whole Numbers Leading to Answers in the Form of Fractions or Mixed Numbers: CCSS.Math.Content.5.NF.B.3

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #22 : Number & Operations With Fractions

If you bake 374 cookies for your class of 50 people, how many cookies does each student get?

Possible Answers:

Between 10 and 11 cookies

Between 6 and 7 cookies

Between 7 and 8 cookies

Between 8 and 9 cookies

Between 9 and 10 cookies

Correct answer:

Between 7 and 8 cookies

Explanation:

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Example Question #1 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 4$ $\displaystyle \small 4$ people are sharing a $\small 23$ $\displaystyle \small 23$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 6$ $\displaystyle \small 6$ and $\small 7$ $\displaystyle \small 7$

$\small 4$ $\displaystyle \small 4$ and $\small 5$ $\displaystyle \small 5$

$\small 2$ $\displaystyle \small 2$ and $\small 3$ $\displaystyle \small 3$

$\small 3$ $\displaystyle \small 3$ and $\small 4$ $\displaystyle \small 4$

$\displaystyle 5$ and $\small 6$ $\displaystyle \small 6$

Correct answer:

$\displaystyle 5$ and $\small 6$ $\displaystyle \small 6$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{23}{4}=5\frac{3}4{}$ $\displaystyle \small \frac{23}{4}=5\frac{3}4{}$

$\small 4$ $\displaystyle \small 4$ can go into $\small 23$ $\displaystyle \small 23$ only $\small 5$ $\displaystyle \small 5$ times with $\small \frac{3}{4}$ $\displaystyle \small \frac{3}{4}$ left over.

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Example Question #2 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 6$ $\displaystyle \small 6$ people are sharing a $\small \small 37$ $\displaystyle \small \small 37$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 7$ $\displaystyle \small 7$ and $\small 8$ $\displaystyle \small 8$

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

$\small 6$ $\displaystyle \small 6$ and $\small 7$ $\displaystyle \small 7$

$\small 5$ $\displaystyle \small 5$ and $\small 6$ $\displaystyle \small 6$

$\small 4$ $\displaystyle \small 4$ and $\small 5$ $\displaystyle \small 5$

Correct answer:

$\small 6$ $\displaystyle \small 6$ and $\small 7$ $\displaystyle \small 7$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{37}{6}=6\frac{1}{6}$ $\displaystyle \small \frac{37}{6}=6\frac{1}{6}$

$\small 6$ $\displaystyle \small 6$ can go into $\small 37$ $\displaystyle \small 37$ only $\small 6$ $\displaystyle \small 6$ times with $\small \frac{1}{6}$ $\displaystyle \small \frac{1}{6}$ left over.

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Example Question #2 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 5$ $\displaystyle \small 5$ people are sharing a $\small 43$ $\displaystyle \small 43$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 12$ $\displaystyle \small 12$ and $\small 13$ $\displaystyle \small 13$

$\small 10$ $\displaystyle \small 10$ and $\small 11$ $\displaystyle \small 11$

$\small 11$ $\displaystyle \small 11$ and $\small 12$ $\displaystyle \small 12$

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

$\small 9$ $\displaystyle \small 9$ and $\displaystyle 10$

Correct answer:

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{43}{5}=8\frac{3}{5}$ $\displaystyle \small \frac{43}{5}=8\frac{3}{5}$

$\small 5$ $\displaystyle \small 5$ can go into $\small 43$ $\displaystyle \small 43$ only $\small 8$ $\displaystyle \small 8$ times with $\small \frac{3}{5}$ $\displaystyle \small \frac{3}{5}$ left over.

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Example Question #3 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 9$ $\displaystyle \small 9$ people are sharing a $\small 82$ $\displaystyle \small 82$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 6$ $\displaystyle \small 6$ and $\small 7$ $\displaystyle \small 7$

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

$\small 7$ $\displaystyle \small 7$ and $\small 8$ $\displaystyle \small 8$

$\small 10$ $\displaystyle \small 10$ and $\small 11$ $\displaystyle \small 11$

$\small 9$ $\displaystyle \small 9$ and $\small 10$ $\displaystyle \small 10$

Correct answer:

$\small 9$ $\displaystyle \small 9$ and $\small 10$ $\displaystyle \small 10$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{82}{9}=9\frac{1}{9}$ $\displaystyle \small \frac{82}{9}=9\frac{1}{9}$

$\small 9$ $\displaystyle \small 9$ and go into $\small 82$ $\displaystyle \small 82$ only $\small 9$ $\displaystyle \small 9$ times and $\small \frac{1}{9}$ $\displaystyle \small \frac{1}{9}$ will be left over.

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Example Question #2 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 8$ $\displaystyle \small 8$ people are sharing a $\small 42$ $\displaystyle \small 42$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 7$ $\displaystyle \small 7$ and $\small 8$ $\displaystyle \small 8$

$\small 6$ $\displaystyle \small 6$ and $\small 7$ $\displaystyle \small 7$

$\small 9$ $\displaystyle \small 9$ and $\small 10$ $\displaystyle \small 10$

$\small 5$ $\displaystyle \small 5$ and $\small 6$ $\displaystyle \small 6$

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

Correct answer:

$\small 5$ $\displaystyle \small 5$ and $\small 6$ $\displaystyle \small 6$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{42}{8}=5\frac{2}{8}$ $\displaystyle \small \frac{42}{8}=5\frac{2}{8}$

$\small 8$ $\displaystyle \small 8$ can go into $\small 42$ $\displaystyle \small 42$ only $\small 5$ $\displaystyle \small 5$ times with $\small \frac{2}{8}$ $\displaystyle \small \frac{2}{8}$ left over.

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Example Question #3 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 3$ $\displaystyle \small 3$ people are sharing a $\small 34$ $\displaystyle \small 34$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 9$ $\displaystyle \small 9$ and $\small 10$ $\displaystyle \small 10$

$\small 11$ $\displaystyle \small 11$ and $\small 12$ $\displaystyle \small 12$

$\small 12$ $\displaystyle \small 12$ and $\small 13$ $\displaystyle \small 13$

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

$\small 10$ $\displaystyle \small 10$ and $\small 11$ $\displaystyle \small 11$

Correct answer:

$\small 11$ $\displaystyle \small 11$ and $\small 12$ $\displaystyle \small 12$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{34}{3}=11\frac{1}{3}$ $\displaystyle \small \frac{34}{3}=11\frac{1}{3}$

$\small 3$ $\displaystyle \small 3$ can go into $\small 34$ $\displaystyle \small 34$ only $\small 11$ $\displaystyle \small 11$ times with $\small \frac{1}{3}$ $\displaystyle \small \frac{1}{3}$ left over.

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Example Question #3 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 4$ $\displaystyle \small 4$ people are sharing a $\small 39$ $\displaystyle \small 39$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 8$ $\displaystyle \small 8$ and $\small 9$ $\displaystyle \small 9$

$\small 11$ $\displaystyle \small 11$ and $\small 12$ $\displaystyle \small 12$

$\small 7$ $\displaystyle \small 7$ and $\small 8$ $\displaystyle \small 8$

$\small 9$ $\displaystyle \small 9$ and $\small 10$ $\displaystyle \small 10$

$\small 10$ $\displaystyle \small 10$ and $\small 11$ $\displaystyle \small 11$

Correct answer:

$\small 9$ $\displaystyle \small 9$ and $\small 10$ $\displaystyle \small 10$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{39}{4}=9\frac{3}{4}$ $\displaystyle \small \frac{39}{4}=9\frac{3}{4}$

$\small 4$ $\displaystyle \small 4$ can go into $\small 39$ $\displaystyle \small 39$ only $\small 9$ $\displaystyle \small 9$ times with $\small \frac{3}{4}$ $\displaystyle \small \frac{3}{4}$ left over.

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Example Question #4 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

$\small 5$ $\displaystyle \small 5$ people are sharing a $\small 72$ $\displaystyle \small 72$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 13$ $\displaystyle \small 13$ and $\small 14$ $\displaystyle \small 14$

$\small 10$ $\displaystyle \small 10$ and $\small 11$ $\displaystyle \small 11$

$\small 12$ $\displaystyle \small 12$ and $\small 13$ $\displaystyle \small 13$

$\small 14$ $\displaystyle \small 14$ and $\small 15$ $\displaystyle \small 15$

$\small 11$ $\displaystyle \small 11$ and $\small 12$ $\displaystyle \small 12$

Correct answer:

$\small 14$ $\displaystyle \small 14$ and $\small 15$ $\displaystyle \small 15$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{72}{5}=14\frac{2}{5}$ $\displaystyle \small \frac{72}{5}=14\frac{2}{5}$

$\small 5$ $\displaystyle \small 5$ cand go into $\small 72$ $\displaystyle \small 72$ only $\small 14$ $\displaystyle \small 14$ times with $\small \frac{2}{5}$ $\displaystyle \small \frac{2}{5}$ left over.

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Example Question #36 : Number & Operations With Fractions

$\small 7$ $\displaystyle \small 7$ people are sharing a $\small 40$ $\displaystyle \small 40$ pound bag of peanuts. How much will each person get? Select the answer with the pair of numbers that the answer will be between.

Possible Answers:

$\small 6$ $\displaystyle \small 6$ and $\small 7$ $\displaystyle \small 7$

$\small 5$ $\displaystyle \small 5$ and $\small 6$ $\displaystyle \small 6$

$\small 7$ $\displaystyle \small 7$ and $\small 8$ $\displaystyle \small 8$

$\small 4$ $\displaystyle \small 4$ and $\small 5$ $\displaystyle \small 5$

$\small 3$ $\displaystyle \small 3$ and $\small 4$ $\displaystyle \small 4$

Correct answer:

$\small 5$ $\displaystyle \small 5$ and $\small 6$ $\displaystyle \small 6$

Explanation:

We can think of this problem as an improper fraction and solve for the mixed number.

$\small \frac{40}{7}=5\frac{5}{7}$ $\displaystyle \small \frac{40}{7}=5\frac{5}{7}$

$\small 7$ $\displaystyle \small 7$ can be divided into $\small 40$ $\displaystyle \small 40$ only $\small 5$ $\displaystyle \small 5$ times, with $\small \frac{5}{7}$ $\displaystyle \small \frac{5}{7}$ left over.

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Common Core: 5th Grade Math : Solve Word Problems Involving Division of Whole Numbers Leading to Answers in the Form of Fractions or Mixed Numbers: CCSS.Math.Content.5.NF.B.3

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #22 : Number & Operations With Fractions

Example Question #1 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #2 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #2 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #3 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #2 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #3 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #3 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #4 : Solve Word Problems Involving Division Of Whole Numbers Leading To Answers In The Form Of Fractions Or Mixed Numbers: Ccss.Math.Content.5.Nf.B.3

Example Question #36 : Number & Operations With Fractions

All Common Core: 5th Grade Math Resources

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