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Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

If a circle has a circumference of $\displaystyle 33$ what is the radius?

$\frac{33}{2 \pi}$ $\displaystyle \frac{33}{2 \pi}$

$\displaystyle 33$

$\frac{33}{4 \pi}$ $\displaystyle \frac{33}{4 \pi}$

$\frac{1089}{4 \pi^{2}}$ $\displaystyle \frac{1089}{4 \pi^{2}}$

$\displaystyle 2$

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Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

If a circle has a circumference of $\displaystyle 33$ what is the radius?

$\frac{33}{2 \pi}$ $\displaystyle \frac{33}{2 \pi}$

$\displaystyle 33$

$\frac{33}{4 \pi}$ $\displaystyle \frac{33}{4 \pi}$

$\frac{1089}{4 \pi^{2}}$ $\displaystyle \frac{1089}{4 \pi^{2}}$

$\displaystyle 2$

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Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

If a circle has a circumference of $\displaystyle 33$ what is the radius?

Your answer:

$\displaystyle 33$

Your answer:

$\frac{33}{4 \pi}$ $\displaystyle \frac{33}{4 \pi}$

Your answer:

$\frac{1089}{4 \pi^{2}}$ $\displaystyle \frac{1089}{4 \pi^{2}}$

Your answer:

$\displaystyle 2$

Correct answer:

$\frac{33}{2 \pi}$ $\displaystyle \frac{33}{2 \pi}$

Explanation:

In order to find the radius of a circle, we need to recall the equation that involves both the radius and circumference.

$C = 2 \pi r$ $\displaystyle C = 2 \pi r$

Since we are given the circumference, we simply substitute 33 for $\uptext{C}$ $\displaystyle \uptext{C}$, and solve for $\uptext{r}$ $\displaystyle \uptext{r}$.

$33 = 2 \pi r$ $\displaystyle 33 = 2 \pi r$

Divide by $2 \pi$ $\displaystyle 2 \pi$ on each side to get

$r = \frac{33}{2 \pi}$ $\displaystyle r = \frac{33}{2 \pi}$

Thus the radius is

$\frac{33}{2 \pi}$ $\displaystyle \frac{33}{2 \pi}$

Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

If a cylinder has a radius of $\displaystyle 15$ and a height of $\displaystyle 25$ what is the volume?

$25 \pi^{2}$ $\displaystyle 25 \pi^{2}$

$5625 \pi$ $\displaystyle 5625 \pi$

375 $\displaystyle 375$

5625 $\displaystyle 5625$

$50 \pi$ $\displaystyle 50 \pi$

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Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

If a cylinder has a radius of $\displaystyle 15$ and a height of $\displaystyle 25$ what is the volume?

Your answer:

$25 \pi^{2}$ $\displaystyle 25 \pi^{2}$

Your answer:

375 $\displaystyle 375$

Your answer:

5625 $\displaystyle 5625$

Your answer:

$50 \pi$ $\displaystyle 50 \pi$

Correct answer:

$5625 \pi$ $\displaystyle 5625 \pi$

Explanation:

In order to find the volume, we need to recall the equation for the volume of a cylinder.

$V = \pi h r^{2}$ $\displaystyle V = \pi h r^{2}$

Since we are given the radius, and the height, we can simply plug in those values into the equation.

$\\r=15\rightarrow r^2=225 \\h=25$ $\displaystyle \\r=15\rightarrow r^2=225 \\h=25$

$V = 5625 \pi$ $\displaystyle V = 5625 \pi$

Thus the volume is

$5625 \pi$ $\displaystyle 5625 \pi$

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Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

All Common Core: High School - Geometry Resources

Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

Flashcards: Circumference and Area of a Circle, Volume of a Cylinder, Pyramid, and Cone Formulas: CCSS.Math.Content.HSG-GMD.A.1

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