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All Common Core: High School - Number and Quantity Resources

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Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

What are the components of a vector that has a terminal point of (5,10) , and an initial point of (2,3) ?

<3.5, -3>

<-3,-7>

<0,0>

<3,7>

<7,3>

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Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

What are the components of a vector that has a terminal point of (5,10) , and an initial point of (2,3) ?

Your answer:

<3.5, -3>

Your answer:

<-3,-7>

Your answer:

<0,0>

Your answer:

<7,3>

Correct answer:

<3,7>

Explanation:

In order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are.

$x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\\ \mbox{(x in terminal point)}=5 \\ \mbox{(x in initial point)}=2 \\ \mbox{(y in terminal point)}=10\\ \mbox{(y in initial point)}= 3$

x=5-2=3

y=10-3=7

To write this in component form, we need to put our , and into .

So the final answer is <3,7>

Below is a visual representation of what we just did.

Term

The blue line is our original vector, and the red line is the same vector, but begins at the origin rather than at the initial point.

Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

What are the components of a vector that has a terminal point of (5,-10) , and an initial point of (-2,3) ?

<-13,7>

<7,-13>

<13,7>

<-13,-7>

<-7,13>

Report an Error Copyright Notice

Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

What are the components of a vector that has a terminal point of (5,-10) , and an initial point of (-2,3) ?

Your answer:

<-13,7>

Your answer:

<13,7>

Your answer:

<-13,-7>

Your answer:

<-7,13>

Correct answer:

<7,-13>

Explanation:

n order to determine what the components of this vector has, we need to remember how to find components of a vector. It's simply the difference between the terminal point and initial point. The first step is to write an equation for what our "new" x and y are.

$x=\mbox{(x in terminal point)}-\mbox{(x in initial point) }$

$y=\mbox{(y in terminal point)}-\mbox{(y in initial point) }$

Now lets identify what these values are.

$\\ \mbox{(x in terminal point)}=5 \\ \mbox{(x in initial point)}=-2 \\ \mbox{(y in terminal point)}=-10\\ \mbox{(y in initial point)}= 3$

x=5-(-2)=7

y=-10-3=-13

To write this in component form, we need to put our , and into .

So the final answer is <7,-13>

Below is a visual representation of what we just did.

Comp2

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All Common Core: High School - Number and Quantity Resources

Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

Flashcards: Vector Components: CCSS.Math.Content.HSN-VM.A.2

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