The midpoint of a line segment is halfway between the two $\displaystyle \small x$ values and halfway between the two $\displaystyle \small y$ values.

Mathematically, that would be the average of each coordinate: $\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$.

Plug in the $\displaystyle (x,y)$ values from the given points and solve.

$\displaystyle (\frac{5+0}{2},\frac{7+1}{2})$

$\displaystyle (\frac{5}{2},\frac{8}{2})$

We can simplify the fraction to give our final answer.

$\displaystyle (\frac{5}{2},4)$

The midpoint of a line segment is halfway between the two $\displaystyle \small x$ values and halfway between the two $\displaystyle \small y$ values.

Mathematically, that would be the average of each coordinate: $\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$.

Plug in the $\displaystyle (x,y)$ values from the given points and solve.

$\displaystyle (\frac{9+1}{2},\frac{9+6}{2})$

$\displaystyle (\frac{10}{2},\frac{15}{2})$

Simplify the fractions to get the final answer.

$\displaystyle (5,7.5)$

The midpoint of a line segment is halfway between the two $\displaystyle \small x$ values and halfway between the two $\displaystyle \small y$ values.

Mathematically, that would be the average of the coordinates: $\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$.

Plug in the $\displaystyle (x,y)$ values from the given points.

$\displaystyle (\frac{4+0}{2},\frac{y+0}{2})=(2,5)$

Now we can solve for the missing value.

$\displaystyle (\frac{4}{2},\frac{y}{2})=(2,5)$

$\displaystyle \frac{4}{2}=2$

The $\displaystyle \small x$ values reduce, so both $\displaystyle \small x$ values equal $\displaystyle \small 2$. Now we need to create a new equation to solve for the $\displaystyle \small y$ value.

$\displaystyle \frac{y}{2}=5$

Multiply both sides by $\displaystyle 2$ to solve.

$\displaystyle (2)\frac{y}{2}=5(2)$

$\displaystyle y=10$

The midpoint formula is this: $\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$.

Plug in the given values from our points and solve:

$\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$

$\displaystyle (\frac{12+1}{2},\frac{12+1}{2})$

$\displaystyle (\frac{13}{2},\frac{13}{2})$

The midpoint formula is this: $\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$.

Plug in the given values from our points and solve:

$\displaystyle (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$

$\displaystyle (\frac{9+6}{2},\frac{2+3}{2})$

$\displaystyle (\frac{15}{2},\frac{5}{2})$

Add up the $\displaystyle x$'s and divide in half, which results in 5. Do the same to the $\displaystyle y$'s and you get 6. Put the $\displaystyle x$ and $\displaystyle y$ in an ordered pair so that your answer is (5, 6). 

To find the midpoint of a line segment, we find the average of the x and y coordinates of the endpoints. The average of two numbers is the sum of those numbers divided by $\displaystyle 2$. Thus, to find the x-coordinate of our midpoint, we find the average of $\displaystyle -6$ and $\displaystyle 2$, and we get $\displaystyle (-6+2)/2=-4/2 = -2$.

To find the y-coordinate of our midpoint, we find the average of $\displaystyle 8$ and $\displaystyle 12$, which is $\displaystyle (8+12)/2=20/2 = 10$.

Thus, our midpoint is $\displaystyle (-2, 10).$

To find the midpoint of a line segment, use the standard equation: 

$\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Plugging in the given points:

$\displaystyle (\frac{-2+-4}{2},\frac{3+16}{2})=(-3,9.5)$

The standard formula to find the midpoint of two points is $\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$.

Plug in the given points to find the answer:

$\displaystyle (\frac{-2+4}{2},\frac{13+(-9)}{2})=(\frac{2}{2},\frac{4}{2})=(1,2)$

My midpoint will be at the average of the $\displaystyle x$-values and the average of the $\displaystyle y$-values. Mathematically, $\displaystyle (\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})$.

Plug in our given values.

$\displaystyle (\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})$

$\displaystyle (\frac{-7+2}{2}, \frac{3+3}{2})$

$\displaystyle (\frac{-5}{2}, \frac{6}{2})$

$\displaystyle (-2.5,3)$