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Example Questions
Example Question #1 : Find Roots Of Quadratic Equation Using Discriminant
True or false: for a quadratic function of form ax2 + bx + c = 0, if the discriminant b2 - 4ac = 0, there is exactly one real root.
False
True
True
This is true. The discriminant b2 - 4ac is the part of the quadratic formula that lives inside of a square root function. As you plug in the constants a, b, and c into b2 - 4ac and evaluate, three cases can happen:
b2 - 4ac > 0
b2 - 4ac = 0
b2 - 4ac < 0
In the first case, having a positive number under a square root function will yield a result that is a positive number answer. However, because the quadratic function includes , this scenario yields two real results.
In the middle case (the case of our example), . Going back to the quadratic formula
, you can see that when everything under the square root is simply 0, then you get only
, which is why you have exactly one real root.
For the final case, if b2 - 4ac < 0, that means you have a negative number under a square root. This means that you will not have any real roots of the equation; however, you will have exactly two imaginary roots of the equation.
Example Question #1 : Find Roots Of Quadratic Equation Using Discriminant
True or false: for a quadratic function of form ax2 + bx + c = 0, if the discriminant b2 - 4ac > 0, there are exactly 2 distinct real roots of the equation.
True
False
True
This is true. The discriminant b2 - 4ac is the part of the quadratic formula that lives inside of a square root function. As you plug in the constants a, b, and c into b2 - 4ac and evaluate, three cases can happen:
b2 - 4ac > 0
b2 - 4ac = 0
b2 - 4ac < 0
In the first case (the case of our example), having a positive number under a square root function will yield a result that is a positive number answer. However, because the quadratic function includes , this scenario yields two real results.
In the middle case, . Going back to the quadratic formula
, you can see that when everything under the square root is simply 0, then you get only
, which is why you have exactly one real root.
For the final case, if b2 - 4ac < 0, that means you have a negative number under a square root. This means that you will not have any real roots of the equation; however, you will have exactly two imaginary roots of the equation.
Example Question #3 : Find Roots Of Quadratic Equation Using Discriminant
True or false: for a quadratic function of form ax2 + bx + c = 0, if the discriminant b2 - 4ac < 0, there are exactly two distinct real roots.
True
False
False
This is false. The discriminant b2 - 4ac is the part of the quadratic formula that lives inside of a square root function. As you plug in the constants a, b, and c into b2 - 4ac and evaluate, three cases can happen:
b2 - 4ac > 0
b2 - 4ac = 0
b2 - 4ac < 0
In the first case, having a positive number under a square root function will yield a result that is a positive number answer. However, because the quadratic function includes , this scenario yields two real results.
In the middle case, . Going back to the quadratic formula
, you can see that when everything under the square root is simply 0, then you get only
, which is why you have exactly one real root.
For the final case (the case of our example), if b2 - 4ac < 0, that means you have a negative number under a square root. This means that you will not have any real roots of the equation; however, you will have exactly two imaginary roots of the equation.
Example Question #4 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: 4x2 + 19x - 5 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: 0
One real root:
Discriminant: 281
Two imaginary roots:
Discriminant: 281
Two imaginary roots:
Discriminant: 441
Two real roots: or
Discriminant: 441
Two real roots: or
Discriminant: 441
Two real roots: or
In the above equation, a = 4, b = 19, and c = -5. Therefore:
b2 - 4ac = (19)2 - 4(4)(-5) = 361 + 80 = 441.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, we have two real roots.
Finally, we use the quadratic function to find these exact roots. The quadratic function is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
which simplifies to
which gives us two answers:
or
These values of x are the two distinct real roots of the given equation.
Example Question #5 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: 4x2 + 12x + 10 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: 16
Types of Roots: Two distinct real roots
Exact Roots: -1, -2
Discriminant: -16
Types of Roots: No real roots; 2 distinct imaginary roots
Exact Roots:
Discriminant: 304
Types of Roots: Two distinct real roots
Exact Roots:
Discriminant: 304
Types of Roots: Two distinct real roots
Exact Roots:
Discriminant: -16
Types of Roots: No real roots; 2 distinct imaginary roots
Exact Roots:
Discriminant: -16
Types of Roots: No real roots; 2 distinct imaginary roots
Exact Roots:
In the above equation, a = 4, b = 12, and c = 10. Therefore:
b2 - 4ac = (12)2 - 4(4)(10) = 144 - 160 = -16.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, we have two distinct imaginary roots.
Finally, we use the quadratic function to find these exact roots. The quadratic function is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
In other words, our two distinct imaginary roots are and
Example Question #6 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: -3x2 + 6x - 3 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: 72
Two distinct real roots:
Discriminant: -72
Two distinct imaginary roots:
Discriminant: 72
Two distinct real roots:
Discriminant: 0
One real root: x = 1
Discriminant: 0
One real root: x = -1
Discriminant: 0
One real root: x = 1
In the above equation, a = -3, b = 6, and c = -3. Therefore:
b2 - 4ac = (6)2 - 4(-3)(-3) = 36 - 36 = 0.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, there is exactly one real root.
Finally, we use the quadratic function to find these exact root. The quadratic formula is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
which simplifies to
which gives us one answer: x = 1
This value of x is the one distinct real root of the given equation.
Example Question #1 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: x2 + 5x + 4 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: 41
Two imaginary roots:
Discriminant: 0
One real root:
Discriminant: 9
Two real roots: x = -1 or x = -4
Discriminant: 41
Two imaginary roots:
Discriminant: 9
Two real roots: x = 1 or x = 4
Discriminant: 9
Two real roots: x = -1 or x = -4
In the above equation, a = 1, b = 5, and c = 4. Therefore:
b2 - 4ac = (5)2 - 4(1)(4) = 25 - 16 = 9.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, we have two real roots.
Finally, we use the quadratic function to find these exact roots. The quadratic function is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
which simplifies to
which gives us two answers:
x = -1 or x = -4
These values of x are the two distinct real roots of the given equation.
Example Question #8 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: -x2 + 3x - 3 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: -8
Two imaginary roots:
Discriminant: 0
One real root:
Discriminant: -21
Two imaginary roots:
Discriminant: -8
Two imaginary roots: .
Discriminant: -21
Two imaginary roots:
Discriminant: -8
Two imaginary roots: .
In the above equation, a = -1, b = 3, and c = -3. Therefore:
b2 - 4ac = (3)2 - 4(-1)(-3) = 9 - 12 = -3.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, we have two distinct imaginary roots.
Finally, we use the quadratic function to find these exact roots. The quadratic function is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
Because , this simplifies to
. In other words, our two distinct imaginary roots are
and
Example Question #9 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: x2 + 2x + 10 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: 36
Two real roots: x = 5 or x = -7
Discriminant: 36
Two real roots: x = -5 or x = 7
Discriminant: -36
Two imaginary roots:
Discriminant: 0
One real root: x = -1
Discriminant: -36
Two imaginary roots:
Discriminant: -36
Two imaginary roots:
In the above equation, a = 1, b = 2, and c = 10. Therefore:
b2 - 4ac = (2)2 - 4(1)(10) = 4 - 40 = -36.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, we have two distinct imaginary roots.
Finally, we use the quadratic function to find these exact roots. The quadratic function is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
Because , this simplifies to
. We can further simplify this to
. In other words, our two distinct imaginary roots are
and
.
Example Question #10 : Find Roots Of Quadratic Equation Using Discriminant
Use the formula b2 - 4ac to find the discriminant of the following equation: x2 + 8x + 16 = 0.
Then state how many roots it has, and whether they are real or imaginary. Finally, use the quadratic function to find the exact roots of the equation.
Discriminant: 0
One real root: x = 0
Discriminant: 0
One real root: x = 4
Discriminant: 128
Two distinct real roots:
Discriminant: 0
One real root: x = -4
Discriminant: 72
Two distinct real roots:
Discriminant: 0
One real root: x = -4
In the above equation, a = 1, b = 8, and c = 16. Therefore:
b2 - 4ac = (8)2 - 4(1)(16) = 64 - 64 = 0.
When the discriminant is greater than 0, there are two distinct real roots. When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, there is exactly one real root.
Finally, we use the quadratic function to find these exact root. The quadratic formula is:
Plugging in our values of a, b, and c, we get:
This simplifies to:
which simplifies to
This value of x is the one distinct real root of the given equation.
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