PSAT Math : How to factor a trinomial

Study concepts, example questions & explanations for PSAT Math

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Example Questions

Example Question #1 : How To Factor A Trinomial

Factor the following expression completely:

\displaystyle x^4-8x^3+12x^2

Possible Answers:

\displaystyle x^2(x+6)(x+2)

\displaystyle x^2(x-3)(x-4)

\displaystyle x^2(x-6)(x-2)

\displaystyle x^2(x+3)(x+4)

\displaystyle x^2(x^2-8x+12)

Correct answer:

\displaystyle x^2(x-6)(x-2)

Explanation:

We must begin by factoring out \displaystyle x^2 from each term.

\displaystyle x^2(x^2-8x+12)

Next, we must find two numbers that sum to \displaystyle -8 and multiply to \displaystyle 12.

\displaystyle (-6)+(-2)=-8

\displaystyle -6*-2=12

Thus, our final answer is:

\displaystyle x^2(x-6)(x-2)

Example Question #2 : Trinomials

Factor the following trinomial:

\displaystyle x^2-x-12

Possible Answers:

\displaystyle (x+3)(x-4)

\displaystyle (x-3)(x-4)

\displaystyle (x-1)(x-12)

\displaystyle (x-6)(x+2)

\displaystyle (x+4)(x-3)

Correct answer:

\displaystyle (x+3)(x-4)

Explanation:

\displaystyle x^2-x-12

To trinomial is in \displaystyle ax+bx+c form

In order to factor, find two numbers whose procuct is \displaystyle c, in this case \displaystyle -12, and whose sum is \displaystyle b, in this case \displaystyle -1

Factors of \displaystyle -12:

\displaystyle -1, 12; 1, -12; -3,4; 3,-4;-2,6; 2,-6

Which of these pairs has a sum of \displaystyle -1?

\displaystyle 3 and \displaystyle -4

Therefore the factored form of \displaystyle x^2-x-12 is:

\displaystyle (x+3)(x-4)

Example Question #41 : Variables

Factor the trinomial.

\displaystyle x^{2}-5x-14

Possible Answers:

\displaystyle (x+7)(x-2)

\displaystyle (x-8)(x+3)

\displaystyle (x-7)(x+2)

\displaystyle (x-3)(x-2)

Correct answer:

\displaystyle (x-7)(x+2)

Explanation:

Our factors will need to have a product of \displaystyle (-14), and a sum of \displaystyle (-5), so our factors must be \displaystyle (-7) and \displaystyle 2.

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