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PSAT Math : Negative Numbers

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Example Questions

Example Question #1 : How To Add Negative Numbers

How many elements of the set $\left \{ -4, -3, -2, -1 \right \}$ are less than $\left | - 2 \frac{1}{2} \right |$ ?

Possible Answers:

None

Four

Two

Three

One

Correct answer:

Four

Explanation:

The absolute value of a negative number can be calculated by simply removing the negative symbol. Therefore,

$\left | - 2 \frac{1}{2} \right | = 2 \frac{1}{2}$

All four (negative) numbers in the set $\left \{ -4, -3, -2, -1 \right \}$ are less than this positive number.

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Example Question #1 : Negative Numbers

a, b, c are integers.

abc < 0

ab > 0

bc > 0

Which of the following must be true?

Possible Answers:

a > 0

a – b > 0

b > 0

ac < 0

a + b < 0

Correct answer:

a + b < 0

Explanation:

Let's reductively consider what this data tells us.

Consider each group (a,b,c) as a group of signs.

From abc < 0, we know that the following are possible:

(–, +, +), (+, –, +), (+, +, –), (–, –, –)

From ab > 0, we know that we must eliminate (–, +, +) and (+, –, +)

From bc > 0, we know that we must eliminate (+, +, –)

Therefore, any of our answers must hold for (–, –, –)

This eliminates immediately a > 0, b > 0

Likewise, it eliminates a – b > 0 because we do not know the relative sizes of a and b. This could therefore be positive or negative.

Finally, ac is a product of negatives and is therefore positive. Hence ac < 0 does not hold.

We are left with a + b < 0, which is true, for two negatives added must be negative.

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Example Question #1 : How To Divide Negative Numbers

What is $\frac{-36}{-9}$ ?

Possible Answers:

-(+4)

Correct answer:

Explanation:

A negative number divided by a negative number always results in a positive number. divided by equals . Since the answer is positive, the answer cannot be or any other negative number.

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Example Question #2 : How To Divide Negative Numbers

Solve for :

16-4x=x+6

Possible Answers:

$-\frac{1}{2}$

$-\frac{18}{5}$

$\frac{1}{2}$

Correct answer:

Explanation:

Begin by isolating your variable.

Subtract from both sides:

16-4x-x=6 , or 16-5x=6

Next, subtract from both sides:

-5x=6-16 , or -5x=-10

Then, divide both sides by :

$x=\frac{-10}{-5}$

Recall that division of a negative by a negative gives you a positive, therefore:

$x=\frac{10}{5}$ or x=2

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Example Question #1 : Negative Numbers

If is a positive number, and -3b is also a positive number, what is a possible value for ?

Possible Answers:

$\frac{1}{2}$

Correct answer:

Explanation:

Because $\dpi{100} \small -3b$ is positive, $\dpi{100} \small b$ must be negative since the product of two negative numbers is positive.

Because $\dpi{100} \small ab$ is also positive, $\dpi{100} \small a$ must also be negative in order to produce a prositive product.

To check you answer, you can try plugging in any negative number for $\dpi{100} \small a$ .

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Example Question #2 : Negative Numbers

, , and are all negative odd integers. Which of the following three expressions must be positive?

I) $a^{b+c}$

II) $a^{b-c}$

III) $a^{c-b}$

Possible Answers:

I only

III only

All of these

None of these

II only

Correct answer:

All of these

Explanation:

A negative integer raised to an integer power is positive if and only if the absolute value of the exponent is even. Since the sum or difference of two odd integers is always an even integer, this is the case in all three expressions. The correct response is all of these.

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Example Question #1791 : Psat Mathematics

is a positive integer; and are negative integers. Which of the following three expressions must be negative?

I) $b^{a+c}$

II) $b^{a-c}$

III) $b^{c-a}$

Possible Answers:

None of I, II or III

I and II only

II and III only

I and III only

I, II and III

Correct answer:

None of I, II or III

Explanation:

A negative integer raised to an integer power is positive if and only if the absolute value of the exponent is even; it is negative if and only if the absolute value iof the exponent is odd. Therefore, all three expressions have signs that are dependent on the odd/even parity of and , which are not given in the problem.

The correct response is none of these.

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Example Question #3 : Negative Numbers

, , and are all negative numbers. Which of the following must be positive?

Possible Answers:

$\frac{ a^{7}c^{5}}{b^{3}}$

$\frac{ a^{6}b^{4}}{c^{9}}$

$\frac{a^{4}b^{7}}{c^{5}}$

$\frac{ a^{8}c^{3}}{b^{6}}$

$\frac{ b^{5}c^{4}}{a^{12}}$

Correct answer:

$\frac{a^{4}b^{7}}{c^{5}}$

Explanation:

The key is knowing that a negative number raised to an odd power yields a negative result, and that a negative number raised to an even power yields a positive result.

$\frac{ a^{6}b^{4}}{c^{9}}$ : $a^{6}$ and $b^{4}$ are positive, yielding a positive dividend; $c^{9}$ is a negative divisor; this result is negative.

$\frac{ a^{7}c^{5}}{b^{3}}$ : $a^{7}$ and $c^{5}$ are negative, yielding a positive dividend; $b^{3}$ is a negative divisor; this result is negative.

$\frac{ a^{8}c^{3}}{b^{6}}$ : $a^{8}$ is positive and $c^{3}$ is negative, yielding a negative dividend; $b^{3}$ is a positive divisor; this result is negative.

$\frac{ b^{5}c^{4}}{a^{12}}$ : $b^{5}$ is negative and $c^{4}$ is positive, yielding a negative dividend; $a^{12}$ is a positive divisor; this result is negative.

$\frac{a^{4}b^{7}}{c^{5}}$ : $a^{4}$ is positive and $b^{7}$ is negative, yielding a negative dividend; $c^{5}$ is a negative divisor; this result is positive.

The correct choice is $\frac{a^{4}b^{7}}{c^{5}}$ .

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Example Question #6 : Negative Numbers

and are positive numbers; is a negative number. All of the following must be positive except:

Possible Answers:

$a+ b^{2} +c^{6}$

$a^{3}+ b^{4} +c$

$a^{2} -b^{7} +c$

$a^{4}+ b^{5} +c^{3}$

$a^{2}-b^{3} +c$

Correct answer:

$a^{4}+ b^{5} +c^{3}$

Explanation:

Since and are positive, all powers of and will be positive; also, in each of the expressions, the powers of and are being added. The clue to look for is the power of and the sign before it.

In the cases of $a^{3}+ b^{4} +c$ and $a+ b^{2} +c^{6}$ , since the negative number is being raised to an even power, each expression amounts to the sum of three positive numbers, which is positive.

In the cases of $a^{2} -b^{7} +c$ and $a^{2}-b^{3} +c$ , since the negative number is being raised to an odd power, the middle power is negative - but since it is being subtracted, it is the same as if a positive number is being added. Therefore, each is essentially the sum of three positive numbers, which, again, is positive.

In the case of $a^{4}+ b^{5} +c^{3}$ , however, since the negative number is being raised to an odd power, the middle power is again negative. This time, it is basically the same as subtracting a positive number. As can be seen in this example, it is possible to have this be equal to a negative number:

a = 1, b = -2, c= 1 :

$a^{4}+ b^{5} +c^{3} = 1^{4}+ (-2)^{5} +1^{3} = 1 + (-32)+ 1 = -30$

Therefore, $a^{4}+ b^{5} +c^{3}$ is the correct choice.

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Example Question #2 : How To Multiply Negative Numbers

Let be a negative integer and be a nonzero integer. Which of the following must be negative regardless of whether is positive or negative?

Possible Answers:

$a^{2}+ b$

$a+b^{2}$

None of the other answers is correct.

$a^{2}b$

$ab^{2}$

Correct answer:

$ab^{2}$

Explanation:

Since $b^{2}$ is positive, $ab^{2}$ , the product of a negative number and a positive number, must be negative also.

Of the others:

$a^{2}b$ is incorrect; if is negative, then $a^{2}$ is positive, and $a^{2}b$ assumes the sign of .

$a^{2}+ b$ is incorrect; again, $a^{2}$ is positive, and if is a positive number, $a^{2}+ b$ is positive.

$a+b^{2}$ is incorrect; regardless of the sign of , $b^{2}$ is positive, and if its absolute value is greater than that of , $a+b^{2}$ is positive.

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PSAT Math : Negative Numbers

Study concepts, example questions & explanations for PSAT Math

All PSAT Math Resources

Example Questions

Example Question #1 : How To Add Negative Numbers

Example Question #1 : Negative Numbers

Example Question #1 : How To Divide Negative Numbers

Example Question #2 : How To Divide Negative Numbers

Example Question #1 : Negative Numbers

Example Question #2 : Negative Numbers

Example Question #1791 : Psat Mathematics

Example Question #3 : Negative Numbers

Example Question #6 : Negative Numbers

Example Question #2 : How To Multiply Negative Numbers

All PSAT Math Resources

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