It is important to remember that the employees who receive an annual increase (Sally, Nancy and John), receive the 7% increase based on the salary from the year before.

If you answered $89,025, you did not account for the 7% increase in salary for Nancy and John.

If you answered $89,525, you did not increase John's salary by 7% for the third year ($26,750 * 7% = $1,872.50 --- $1,872.50 + $26,750 = $28,622.50).

If you answered $91,275, you did not account for the 7% to be applied to John's second year salary; rather, you added the dollar increase ($1750) that he received between his first and second year and added it to his second year salary.  

If you answered $93,872.50, you accounted for both part-time employees working 1,000 hours. Therefore, the correct answer is $94,397.50.

Percentage Increase = (Year Two Profit – Year One Profit) / Year One Profit

= ($12,000 - $10,000) / $10,000 = $2000 / $10,000 = .2 = 20%

Find a common unit—in this case it is inches. The increase is from 99” to 173”.  To find the percentage increase we find the difference and then divide by the length of Truck A.

\(\displaystyle \frac{173-99}{99}=\frac{74}{99}\approx 0.7474\) 

or 74.74%

Pay = Hours worked x Rate per hour

Retail job = 20 x $8.50 = $170.00

Office job = 15 x $12.00 = $180.00

Current weekly pay = $170.00 + $180.00 = $350.00

Additional Office job hours = 10 x $12.00 = $120.00

Percentage Increase = $120 / $350 = .343 (rounded) --> 34.3%

To find the percentage increase, use the following formula:

Increased # of students this year / # of students last year

If there were \(\displaystyle 500\) students last year, and this year there are \(\displaystyle 570\), the number of students increased by \(\displaystyle 70\).  Then, knowing this, you can find what percentage of the original number (\(\displaystyle 500\)) \(\displaystyle 70\) represents.

Therefore:

\(\displaystyle \frac{570-500}{500} = \frac{70}{500}=\frac{14}{100}=0.14\)

The number of students increased by \(\displaystyle 14\%\).

To find out which option is correct, simply follow one complete cycle (that is to say, one day's worth of actions).

We will use \(\displaystyle x\) to represent the initial amount.

\(\displaystyle x \cdot 1.01 = 1.01x\) First, increase by \(\displaystyle 1 \%\).

\(\displaystyle 1.01x \cdot .99 = .9999x\) Next, decrease by \(\displaystyle 1 \%\).

So, after each cycle, the total amount of money decreases by \(\displaystyle .0001 \%\). Eventually therefore, the money will run out.

To find percent change, subtract the "old" amount from the "new" amount, then divide the result by the "old" amount. The result is a percent increase if positive and a percent decrease if negative.

\(\displaystyle T_{change} = 100 \cdot \frac{T_2-T_1}{T_1} = 100 \cdot \frac{22-15}{15} = 46.66 \% \approx 47 \%\)

Thus, there was a \(\displaystyle 47 \%\) increase in temperature that day.

To find percent change, subtract the "old" amount from the "new" amount, then divide the result by the "old" amount. The result is a percent increase if positive and a percent decrease if negative. In this case, don't forget \(\displaystyle x\):

\(\displaystyle T_{change} = 100 \cdot \frac{T_2-T_1}{T_1} = 100 \cdot \frac{.40x-.18x}{.18x} = 122.22 \% \approx 122 \%\)

To find percent change, subtract the "old" amount from the "new" amount, then divide the result by the "old" amount. The result is a percent increase if positive and a percent decrease if negative.

\(\displaystyle T_{change} = 100 \cdot \frac{T_2-T_1}{T_1} = 100 \cdot \frac{6.17-5.52}{5.52} = 11.7 \% \approx 12 \%\)

To find percent change, subtract the "old" amount from the "new" amount, then divide the result by the "old" amount. The result is a percent increase if positive and a percent decrease if negative. In this case, to keep our amount constantly compared to Tuesday, set Tuesday's price as a variable.

\(\displaystyle x \cdot 1.2 = 1.2x\) On Tuesday, gain 20 percent.

\(\displaystyle 1.2x \cdot .88 = 1.056x\) On Wednesday, lose 12 percent (thus, multiply by 88 percent).

\(\displaystyle 1.056x\cdot 1.04 = 1.09824x \approx 1.10x\) On Thursday, gain 4 percent.

Thus, our final gain relative to Tuesday is \(\displaystyle 10 \%\).