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Algebra 1 : How to find mean

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Example Questions

Example Question #1 : Statistics And Probability

What is the mean of 44, 22, 134, and 200?

Possible Answers:

144

100

Correct answer:

100

Explanation:

To find the mean, you must add all of the numbers together and divide by the amount of numbers. In this case there are four numbers so, we must deivide the total sum by 4.

$\frac{22+44+134+200}{4}=\frac{400}{4}= 100$ $\displaystyle \frac{22+44+134+200}{4}=\frac{400}{4}= 100$

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Example Question #4 : Basic Statistics

Calculate the mean of the following numbers: 11, 13, 16, 13, 14, 19, 13, 13

Possible Answers:

$\displaystyle 14$

$\displaystyle 12$

$\displaystyle 15$

$\displaystyle 13$

Correct answer:

$\displaystyle 14$

Explanation:

First, calculate the sum of all of the numbers.

$\small 11+13+16+13+14+19+13+13=112$ $\displaystyle \small 11+13+16+13+14+19+13+13=112$

Next, divide by the total number.

$\small \frac{112}{8}=14$ $\displaystyle \small \frac{112}{8}=14$

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Example Question #1 : How To Find Mean

Find the mean of this number set: 2, 5, 6, 7, 7, 3

Possible Answers:

$\displaystyle 5$

$\displaystyle 4$

$\displaystyle 2$

$\displaystyle 6$

$\displaystyle 7$

Correct answer:

$\displaystyle 5$

Explanation:

The numbers add up to 30. To find the mean, divide by the number of numbers (6) and you get a mean of 5. Mean is a fancy way of saying average.

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Example Question #2 : Statistics And Probability

The class average in a class of 15 is 86%. If one additional student earns a 100% in the class, what is the new class average.

Possible Answers:

$93\%$ $\displaystyle 93\%$

$86.875\%$ $\displaystyle 86.875\%$

None of the available answers

There is not enough information to answer this question

$87.4\%$ $\displaystyle 87.4\%$

Correct answer:

$86.875\%$ $\displaystyle 86.875\%$

Explanation:

We can treat this as if the entire class had exactly 86% as their average, so the new average is:

$\frac{(86\cdot 15)+100}{16}=86.875$ $\displaystyle \frac{(86\cdot 15)+100}{16}=86.875$

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Example Question #1 : Mean

What is the mean of the following numbers?

88,99,31,47,68,27

Possible Answers:

$\displaystyle 88$

$\displaystyle 58$

$\displaystyle 64$

$\displaystyle 60$

Correct answer:

$\displaystyle 60$

Explanation:

To find the mean you add all of the numbers together and divide it by the amount of numbers. In this case there are six numbers so $\frac{(88+99+31+47+68+27)}{6}=\frac{360}{6}$ $\displaystyle \frac{(88+99+31+47+68+27)}{6}=\frac{360}{6}$

The answer is $\displaystyle 60$.

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Example Question #4 : How To Find Mean

$\textup{If Peter has }\$30\textup{, Paul has }\$40\textup{, and Mary has }\$80,$ $\displaystyle \textup{If Peter has }\$30\textup{, Paul has }\$40\textup{, and Mary has }\$80,$

$\textup{what is the mean (average) amount of money that each has?}$ $\displaystyle \textup{what is the mean (average) amount of money that each has?}$

Possible Answers:

$\$150$ $\displaystyle \$150$

$\$40$ $\displaystyle \$40$

$\$30$ $\displaystyle \$30$

$\$50$ $\displaystyle \$50$

$\$80$ $\displaystyle \$80$

Correct answer:

$\$50$ $\displaystyle \$50$

Explanation:

$\textup{The mean, or average, is the sum of all terms divided by the number of terms.}$ $\displaystyle \textup{The mean, or average, is the sum of all terms divided by the number of terms.}$

$\frac{30+40+80}{3}=50$ $\displaystyle \frac{30+40+80}{3}=50$

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Example Question #3 : Statistics And Probability

$\textup{The average of }a\textup{, }b\textup{, and }c\textup{ is 10.}$ $\displaystyle \textup{The average of }a\textup{, }b\textup{, and }c\textup{ is 10.}$

$\textup{If }a=6\textup{ and }b=9\textup{, what is the value of }c\textup{?}$ $\displaystyle \textup{If }a=6\textup{ and }b=9\textup{, what is the value of }c\textup{?}$

Possible Answers:

$\displaystyle 13$

$\displaystyle 15$

$\displaystyle 16$

$\displaystyle 12$

$\displaystyle 14$

Correct answer:

$\displaystyle 15$

Explanation:

$\textup{Average is the sum of all terms divided by the number of terms.}$ $\displaystyle \textup{Average is the sum of all terms divided by the number of terms.}$

$\frac{a+b+c}{3}=10$ $\displaystyle \frac{a+b+c}{3}=10$

$6+9+c = 30\;\;\;\;\;\;\;\;\;\;\;\;15+c = 30\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;c = 15$ $\displaystyle 6+9+c = 30\;\;\;\;\;\;\;\;\;\;\;\;15+c = 30\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;c = 15$

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Example Question #3 : Statistics And Probability

The sum of the elements of a data set is 741 $\displaystyle 741$; the mean of the elements is $\displaystyle 57$. How many elements are there in the set?

Possible Answers:

$\displaystyle 18$

$\displaystyle 23$

$\displaystyle 19$

$\displaystyle 13$

It is impossible to tell from the imformation given.

Correct answer:

$\displaystyle 13$

Explanation:

The mean, $\overline{x}$ $\displaystyle \overline{x}$, of a data set is the sum of the elements, $\sum x$ $\displaystyle \sum x$, $\sumx$ $\displaystyle \sumx$ divided by the number of elements, $\displaystyle n$.

$\overline{x} = \frac{\sum x}{n}$ $\displaystyle \overline{x} = \frac{\sum x}{n}$

We know that $\bar{x}=57$ $\displaystyle \bar{x}=57$ and $\sum x=741$ $\displaystyle \sum x=741$. Now we can solve for $\displaystyle n$.

$57 = \frac{741}{n}$ $\displaystyle 57 = \frac{741}{n}$

$\displaystyle n* 57 = 741$

$n= \frac{741}{57}=13$ $\displaystyle n= \frac{741}{57}=13$

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Example Question #1 : Statistics And Probability

Two standard dice are rollled. What is the probability that the sum of both dice is greater than $\displaystyle 9$?

Possible Answers:

$\frac{1}{12}$ $\displaystyle \frac{1}{12}$

$\frac{1}{3}$ $\displaystyle \frac{1}{3}$

$\frac{2}{9}$ $\displaystyle \frac{2}{9}$

$\frac{1}{6}$ $\displaystyle \frac{1}{6}$

Correct answer:

$\frac{1}{6}$ $\displaystyle \frac{1}{6}$

Explanation:

There are $\displaystyle 36$ total possible outcomes ($\displaystyle 6$ sides on one die times $\displaystyle 6$ sides on the other). The following are the possible outcomes that are greater than $\displaystyle 9$.

$\displaystyle 4$ and $\displaystyle 6$

$\displaystyle 5$ and $\displaystyle 5$

5 and $\displaystyle 6$

$\displaystyle 6$ and $\displaystyle 4$

$\displaystyle 6$ and $\displaystyle 5$

$\displaystyle 6$ and $\displaystyle 6$

There are $\displaystyle 6$ possible outcomes greater than $\displaystyle 9$, out of $\displaystyle 36$ possible outcomes total; thus, there is a $\frac{6}{36}=\frac{1}{6}$ $\displaystyle \frac{6}{36}=\frac{1}{6}$ chance of rolling greater than $\displaystyle 9$.

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Example Question #1 : How To Find Mean

Is the following method for collecting data biased? If so, why?

A company would like to assess the approval of their new product. To determine if customers were happy with their product, they placed a link on their website to all consumers to opt-in to provide their opinion.

Possible Answers:

Yes; this is an example of analytical bias.

Yes; this is an example of selection bias.

No; the collection method is not biased.

Yes; this is an example of exclusion bias.

Correct answer:

Yes; this is an example of selection bias.

Explanation:

Because this is an "opt-in" study, certain individuals are more likely to participate than others resulting in a selection bias.

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Algebra 1 : How to find mean

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #1 : Statistics And Probability

Example Question #4 : Basic Statistics

Example Question #1 : How To Find Mean

Example Question #2 : Statistics And Probability

Example Question #1 : Mean

Example Question #4 : How To Find Mean

Example Question #3 : Statistics And Probability

Example Question #3 : Statistics And Probability

Example Question #1 : Statistics And Probability

Example Question #1 : How To Find Mean

All Algebra 1 Resources

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