Algebra 1 : Proportions

Study concepts, example questions & explanations for Algebra 1

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Example Questions

Example Question #1 : Proportions

The  probability of an event is 3/11. Find the chance the event will not occur.

Possible Answers:

3/8

8/11

3/11

11/3

8/3

Correct answer:

8/11

Explanation:

If the chance an event will happen is 3/11, that means there are 8 instances where the even would not occur out of every 11, giving us 8/11.

3 chances out of 11 = event

11 – 3 = 8

8 chances out of 11 = no event

Example Question #2 : Proportions

Solve for \displaystyle x:

\displaystyle \small \frac{4}{7} = \frac{x}{28}

Possible Answers:

\displaystyle 12

\displaystyle 16

\displaystyle 7

\displaystyle 4

Correct answer:

\displaystyle 16

Explanation:

Cross multiply:

\displaystyle \small 7x\ =\ 4\times 28\ =112

Solve for \displaystyle x:

\displaystyle \small 7x\ =\ 112

\displaystyle \frac{112}{7}=16

Example Question #2 : Proportions

Solve for \displaystyle n in the following proportion statement:

\displaystyle \small \frac{n}{4\frac{1}{2}} = \frac{4\frac{2}{3}}{2\frac{1}{4}}

Possible Answers:

Correct answer:

Explanation:

Use cross-multiplication to set up the following equation:

\displaystyle \small \frac{n}{4\frac{1}{2}} = \frac{4\frac{2}{3}}{2\frac{1}{4}} 

Rewrite with improper fractions and solve:

\displaystyle \small \small \frac{9}{4} \cdot n = \frac{9}{2} \cdot \frac{14}{3} = \frac{3}{1} \cdot \frac{7}{1} = \frac{21}{1}

\displaystyle \small n= \frac{21}{1} \div \frac{9}{4} = \frac{21}{1} \cdot \frac{4}{9} = \frac{7}{1} \cdot \frac{4}{3} = \frac{28}{3} = 9 \frac{1}{3}

So the correct choice is \displaystyle \small 9 \frac{1}{3}.

Example Question #3 : Proportions

Possible Answers:

\displaystyle 60

\displaystyle 62

\displaystyle 40

\displaystyle 30

\displaystyle 70

Correct answer:

\displaystyle 60

Explanation:

Example Question #3 : Proportions

If Max drives 10 miles in 24 minutes, how many minutes will it take for him to drive 25 miles?

Possible Answers:

\displaystyle 36\ minutes

\displaystyle 60\ minutes

\displaystyle 48\ minutes

\displaystyle 75\ minutes

\displaystyle 60\ hours

Correct answer:

\displaystyle 60\ minutes

Explanation:

Set up a proportion, with miles driven on top and the time (in minutes) on the bottom:

\displaystyle \frac{10}{24} = \frac{25}{x}

Then, cross multiply:

\displaystyle 10x = 24(25), or

\displaystyle 10x = 600

Finally, dividing both sides by 10 gives:

\displaystyle x = 60 minutes.

 

Example Question #1 : Proportions

A recipe for making 24 cookies calls for 6 cups of sugar. How many cups of sugar would be needed to make 16 cookies?

Possible Answers:

\displaystyle 5

\displaystyle 3

\displaystyle 4

\displaystyle 2

\displaystyle 1

Correct answer:

\displaystyle 4

Explanation:

To solve the equation, you can set up a proportion with \displaystyle x as the cups of sugar needed for making \displaystyle y cookies. In this case, we know that it takes 6 cups of sugar to make 24 cookies, so we can set up the proportion as \displaystyle \frac{x}{y}=\frac{6}{24}. Since we know that we need to make 16 cookies, we can substitute 16 for \displaystyle y, \displaystyle \frac{x}{16}=\frac{6}{24}. Cross multiply the fractions to get \displaystyle 24x=96. Now, solve for \displaystyle x to get a solution of 4.

Example Question #3 : Proportions

Possible Answers:

\displaystyle 18

\displaystyle 24

\displaystyle 28

\displaystyle 20

\displaystyle 21

Correct answer:

\displaystyle 21

Explanation:

Example Question #5 : Proportions

To make 36 cookies, a recipe calls for 5 ounces of chocolate chips. How many ounces of chocolate chips would you need to make 900 cookies?

Possible Answers:

\displaystyle 130

\displaystyle 115

\displaystyle 125

\displaystyle 120

None of the other answers

Correct answer:

\displaystyle 125

Explanation:

To figure out how many ounces of chocolate chips are needed to make 900 cookies, you simply need to set up a proportion. In this case, we know that 5 ounces of chocolate chips are needed to make 36 cookies, and we are trying to make a total of 900 cookies. Therefore, you can set up the proportion as

\displaystyle \frac{5}{36}=\frac{x}{900}

where \displaystyle x is the ounces of chocolate chips needed to make 900 cookies.

For this proportion, solving for \displaystyle x would give you a result of 125 ounces of chocolate chips.

Example Question #6 : Proportions

If \displaystyle \frac{3}{x} = \frac{x+4}{20}, what is the value of \displaystyle x?

Possible Answers:

\displaystyle x=5

\displaystyle x=10\displaystyle x=-6

\displaystyle x=-3\displaystyle x=-24

\displaystyle x=8

\displaystyle x=6\displaystyle x=-10

Correct answer:

\displaystyle x=6\displaystyle x=-10

Explanation:

Proportions are useful for solving many types of problems, but here our equation itself is a proportion.

To solve, we cross-multiply: the numerator of one side times the denominator of the other and vice versa. We are left with

 \displaystyle x^{2}+4x=60 or

 \displaystyle x^{2}+4x-60=0

A simple FOIL gives us \displaystyle (x-6)(x+10)=0

so our solutions are \displaystyle x=6 and \displaystyle x=-10.

Example Question #4 : Proportions

If \displaystyle 9x = 17y, what is the value of \displaystyle 24x?

Possible Answers:

\displaystyle 36.2y

\displaystyle 9.1y

\displaystyle 49.5y

\displaystyle 12.7y

\displaystyle 45.3y

Correct answer:

\displaystyle 45.3y

Explanation:

To solve this equation, we need to set up a simple proportion. Since the variables \displaystyle x and \displaystyle y are already in use, let's call the quantity that we are solving for \displaystyle z. From the given information, we know we can use the proportion \displaystyle \frac{9x}{17y} = \frac{24x}{z}. Cross-multiplication yields \displaystyle (9x)(z) = (24x)(17y). Dividing by the common term of \displaystyle x and simplifying the right side gives us \displaystyle 9z = 408y, so our solution must be \displaystyle 45.3y.

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