Algebra 1 : Proportions

Study concepts, example questions & explanations for Algebra 1

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Example Questions

Example Question #1 : Proportions

The  probability of an event is 3/11. Find the chance the event will not occur.

Possible Answers:

3/11

3/8

8/3

11/3

8/11

Correct answer:

8/11

Explanation:

If the chance an event will happen is 3/11, that means there are 8 instances where the even would not occur out of every 11, giving us 8/11.

3 chances out of 11 = event

11 – 3 = 8

8 chances out of 11 = no event

Example Question #1 : Proportions

Solve for \(\displaystyle x\):

\(\displaystyle \small \frac{4}{7} = \frac{x}{28}\)

Possible Answers:

\(\displaystyle 16\)

\(\displaystyle 4\)

\(\displaystyle 7\)

\(\displaystyle 12\)

Correct answer:

\(\displaystyle 16\)

Explanation:

Cross multiply:

\(\displaystyle \small 7x\ =\ 4\times 28\ =112\)

Solve for \(\displaystyle x\):

\(\displaystyle \small 7x\ =\ 112\)

\(\displaystyle \frac{112}{7}=16\)

Example Question #2 : Proportions

Solve for \(\displaystyle n\) in the following proportion statement:

\(\displaystyle \small \frac{n}{4\frac{1}{2}} = \frac{4\frac{2}{3}}{2\frac{1}{4}}\)

Possible Answers:

\(\displaystyle \small 9\tfrac{1}{2}\)

\(\displaystyle \small 8\tfrac{1}{12}\)

\(\displaystyle \small 9\tfrac{1}{3}\)

\(\displaystyle \small 8\tfrac{1}{2}\)

\(\displaystyle \small 8\tfrac{2}{3}\)

Correct answer:

\(\displaystyle \small 9\tfrac{1}{3}\)

Explanation:

Use cross-multiplication to set up the following equation:

\(\displaystyle \small \frac{n}{4\frac{1}{2}} = \frac{4\frac{2}{3}}{2\frac{1}{4}}\) 

\(\displaystyle \small 2\tfrac{1}{4} \cdot n = 4\tfrac{1}{2} \cdot 4\tfrac{2}{3}\)

Rewrite with improper fractions and solve:

\(\displaystyle \small \small \frac{9}{4} \cdot n = \frac{9}{2} \cdot \frac{14}{3} = \frac{3}{1} \cdot \frac{7}{1} = \frac{21}{1}\)

\(\displaystyle \small n= \frac{21}{1} \div \frac{9}{4} = \frac{21}{1} \cdot \frac{4}{9} = \frac{7}{1} \cdot \frac{4}{3} = \frac{28}{3} = 9 \frac{1}{3}\)

So the correct choice is \(\displaystyle \small 9 \frac{1}{3}\).

Example Question #3 : Proportions

\(\displaystyle \textup{A taste test shows that out of every 5 people who participated, 3 of them preferred}\)

\(\displaystyle \textup{OK Cola to ABC Root Beer. If 100 people participated, how many preferred OK Cola?}\)

Possible Answers:

\(\displaystyle 60\)

\(\displaystyle 62\)

\(\displaystyle 40\)

\(\displaystyle 30\)

\(\displaystyle 70\)

Correct answer:

\(\displaystyle 60\)

Explanation:

\(\displaystyle \textup{Set up an equation with the two proportions: }\frac{3}{5}=\frac{x}{100}\)

\(\displaystyle \textup{Cross multiply and solve: }5x=300\;\;\;\;\;\;\;\;\;x=60\)

Example Question #1 : Proportions

If Max drives 10 miles in 24 minutes, how many minutes will it take for him to drive 25 miles?

Possible Answers:

\(\displaystyle 60\ hours\)

\(\displaystyle 60\ minutes\)

\(\displaystyle 48\ minutes\)

\(\displaystyle 36\ minutes\)

\(\displaystyle 75\ minutes\)

Correct answer:

\(\displaystyle 60\ minutes\)

Explanation:

Set up a proportion, with miles driven on top and the time (in minutes) on the bottom:

\(\displaystyle \frac{10}{24} = \frac{25}{x}\)

Then, cross multiply:

\(\displaystyle 10x = 24(25)\), or

\(\displaystyle 10x = 600\)

Finally, dividing both sides by 10 gives:

\(\displaystyle x = 60\) minutes.

 

Example Question #3 : Proportions

A recipe for making 24 cookies calls for 6 cups of sugar. How many cups of sugar would be needed to make 16 cookies?

Possible Answers:

\(\displaystyle 3\)

\(\displaystyle 2\)

\(\displaystyle 5\)

\(\displaystyle 1\)

\(\displaystyle 4\)

Correct answer:

\(\displaystyle 4\)

Explanation:

To solve the equation, you can set up a proportion with \(\displaystyle x\) as the cups of sugar needed for making \(\displaystyle y\) cookies. In this case, we know that it takes 6 cups of sugar to make 24 cookies, so we can set up the proportion as \(\displaystyle \frac{x}{y}=\frac{6}{24}\). Since we know that we need to make 16 cookies, we can substitute 16 for \(\displaystyle y\), \(\displaystyle \frac{x}{16}=\frac{6}{24}\). Cross multiply the fractions to get \(\displaystyle 24x=96\). Now, solve for \(\displaystyle x\) to get a solution of 4.

Example Question #3 : Proportions

\(\displaystyle \textup{A bag contains 60 marbles, all of which are either red, white, or blue.}\)

\(\displaystyle \textup{If }\frac{2}{5}\textup{ of the marbles are red and }\frac{1}{4}\textup{ of the marbles are white,}\)

\(\displaystyle \textup{how many blue marbles are in the bag?}\)

Possible Answers:

\(\displaystyle 18\)

\(\displaystyle 24\)

\(\displaystyle 28\)

\(\displaystyle 20\)

\(\displaystyle 21\)

Correct answer:

\(\displaystyle 21\)

Explanation:

\(\displaystyle \textup{Probability}= \frac{\textup{desired outcomes}}{\textup{total outcomes}}\)

\(\displaystyle \textup{ First find out how many red and white marbles there are.}\)

\(\displaystyle \textup{Red: }\frac{2}{5}=\frac{r}{60}\;\;\;5r=120\;\;\;r=24\;\;\;\)

\(\displaystyle \textup{White: }\frac{1}{4}=\frac{w}{60}\;\;\;4w=60\;\;\;w=15\)

\(\displaystyle \textup{Blue: }b = 60-24-15\;\;\;\;\;b=21\)

Example Question #4 : Proportions

To make 36 cookies, a recipe calls for 5 ounces of chocolate chips. How many ounces of chocolate chips would you need to make 900 cookies?

Possible Answers:

\(\displaystyle 130\)

None of the other answers

\(\displaystyle 115\)

\(\displaystyle 125\)

\(\displaystyle 120\)

Correct answer:

\(\displaystyle 125\)

Explanation:

To figure out how many ounces of chocolate chips are needed to make 900 cookies, you simply need to set up a proportion. In this case, we know that 5 ounces of chocolate chips are needed to make 36 cookies, and we are trying to make a total of 900 cookies. Therefore, you can set up the proportion as

\(\displaystyle \frac{5}{36}=\frac{x}{900}\)

where \(\displaystyle x\) is the ounces of chocolate chips needed to make 900 cookies.

For this proportion, solving for \(\displaystyle x\) would give you a result of 125 ounces of chocolate chips.

Example Question #3 : Proportions

If \(\displaystyle \frac{3}{x} = \frac{x+4}{20}\), what is the value of \(\displaystyle x\)?

Possible Answers:

\(\displaystyle x=6\)\(\displaystyle x=-10\)

\(\displaystyle x=5\)

\(\displaystyle x=10\)\(\displaystyle x=-6\)

\(\displaystyle x=8\)

\(\displaystyle x=-3\)\(\displaystyle x=-24\)

Correct answer:

\(\displaystyle x=6\)\(\displaystyle x=-10\)

Explanation:

Proportions are useful for solving many types of problems, but here our equation itself is a proportion.

To solve, we cross-multiply: the numerator of one side times the denominator of the other and vice versa. We are left with

 \(\displaystyle x^{2}+4x=60\) or

 \(\displaystyle x^{2}+4x-60=0\)

A simple FOIL gives us \(\displaystyle (x-6)(x+10)=0\)

so our solutions are \(\displaystyle x=6\) and \(\displaystyle x=-10\).

Example Question #4 : Proportions

If \(\displaystyle 9x = 17y\), what is the value of \(\displaystyle 24x\)?

Possible Answers:

\(\displaystyle 36.2y\)

\(\displaystyle 9.1y\)

\(\displaystyle 49.5y\)

\(\displaystyle 12.7y\)

\(\displaystyle 45.3y\)

Correct answer:

\(\displaystyle 45.3y\)

Explanation:

To solve this equation, we need to set up a simple proportion. Since the variables \(\displaystyle x\) and \(\displaystyle y\) are already in use, let's call the quantity that we are solving for \(\displaystyle z\). From the given information, we know we can use the proportion \(\displaystyle \frac{9x}{17y} = \frac{24x}{z}\). Cross-multiplication yields \(\displaystyle (9x)(z) = (24x)(17y)\). Dividing by the common term of \(\displaystyle x\) and simplifying the right side gives us \(\displaystyle 9z = 408y\), so our solution must be \(\displaystyle 45.3y\).

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